. The amount of zinc required to produce 224 mL
of H2 at STP on treatment with dilute H2SO4 will be
(a) 65 g
(b) 0.065 g
(c) 0.65 g
(d) 6.5 g
Best Answer
Correct Option is: (C)
Zn + H2SO4 → ZnSO4 + H2
65 g 22400 mL
65 g of zinc yields 22400 mL of H2 at STP
Zinc needed to produce 224 mL of H2 at STP = 65/22400×224 = 0.65 g
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