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- The bob of a simple pendulum is imparted a velocity of 5m s-1 when it is at its mean position
. The bob of a simple pendulum is imparted a velocity of 5m s-1 when it is at its mean position
The bob of a simple pendulum is imparted a velocity of 5m s-1 when it is at its mean position. To what maximum vertical height will it rise on reaching at its extreme position if 60% of its energy is lost in overcoming the friction of air?
(Take g = 10 m s-2).
Best Answer
Total kinetic energy at mean position = 1 / 2 mv2
= 1 / 2 m × 52
Energy lost = 1 / 2 m × 52 × 60 / 100
Energy available = 1 / 2 m × 52 × 40 / 100
According to energy conservation
1 / 2 m × 52 × 40 / 100 = mgh
5 = 10 × h
h = 0.5m
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