. The diagonals AC and BD of a cyclic quadrilateral ABCD intersect at right angles at E
A line l drawn through E and perpendicular to AB meets CD at F. Prove that F is the mid point of CD.
Best Answer
Sol: ABCD is a cyclic quadrilateral in which diagonals AC and BD intersect in E at right angles. l is a line through E and perpendicular to AB meets CD in F
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