Ans: A
Sol: Any point on the line is
P = (6r1 + 2, 3r1 + 3, –4r1 –4).
Direction ration of the line segment PQ, where Q = (–1, 2, 6), are
6r1 + 3, 3r1 + 1, – 4r, – 10.
If ‘P’ be the foot of altitude drawn from Q to the given line, then
6(6r1 + 3) + 3(3r1 + 1) + 4(4r1 + 10) = 0.
r1 = –1.
Thus, P = (–4, 0, 0)
Required distance= 