Ans: C
Sol :Energy required to remove e− from singly ionized helium atom = 54.4 eV
Let energy required to remove e− form helium atom = N eV
From the question,
54.4 eV = 2.2×N
∴ N = 24.72 eV
Energy required to ionize helium atom
(54.4 + 24.72) = 79.12 eV