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at (1, –1), directrix along x –y + 1 = 0 and with eccentricity root 2 is
A. x2 –y2 =1
B. xy = 1
C. 2xy –4x + 4y + 1= 0
D. 2xy + 4x – 4y – 1= 0
Ans: C
Sol: Let P (x, y) be any point on the conic. Then
2xy –4x + 4y + 1 = 0