. The freezing point depression constant for water is 1.86 ° Cm^-1
The freezing point depression constant for water is 1.86 ° Cm-1. If 5 g is dissolved in 45 g H2O, the freezing point is changed by - 3.82 °. Calculate the van't Hoff factor for Na2SO4
A: 0.381
B: 2.05
C: 2.63
D: 3.11
Best Answer
Explanation:
For depression in freezing point the formula is
T=Kfm
m = molality
molality(m) = number of moles/mass of solvent in Kg
m = 5x1000/ Mx 45
3.82 = 1.86x5x1000/ Mcal x45
Mcal= 54.10g
vant hoff"s factor (i) = Mobs/Mcal
i = 142/54.1 = 2.624 ≈ 2.63
Final Answe:
The van’t hoff factor (C) (i) = 2.63
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