. The heat of atomization of PH3(g) is 228 kcal mol


The heat of atomization of PH3(g) is 228 kcal mol–1 and that of P2H4(g) is 355 kcal mol–1. The energy of the P – P bond is

  1. 102 kcal mol–1   
  2. 51 kcal mol–1
  3. 26 kcal mol–1       
  4. 204 kcal mol–1

 

Best Answer

Correct answer is 2

The balanced chemical equation for the atomization of phosphine is PH3 P + 3H; ΔH = 228

ep-H = 228/3

The balanced chemical equation for the atomization of  P2H4(g) is H2P-PH2 2P + 4H; ΔH = 355

ep-p + 4 x ep-H = 355

ep-p + 4 x 228/3 = 355

ep-p = 51

The energy of the P−P bond is 51 kcal.

 

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