. The hybridisation of Ni inNi(CO)4 is


A:sp2

B:dsp2

C:sp3

D:sp3p

 

Best Answer

Explanation:-

  • The outer electronic configuration of Ni is 3d84s2 .
  • Now ,Ni is in zero oxidation state. The 2 electrons from 4s orbitals moves to the 3d orbital and we get completely filled 3d orbital and vacant 4s and 4 p orbital. 

3d104s04d0

  • This way we get sp3  hybridization and shape is tetrahedral.
  • It does not have any unpaired electrons so it is diamagnetic in nature.

Final Answer:-

The hybridization of Ni in Ni(CO)4   complex  is  (C ) sp3

 

 

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