. The locus of the foot of the perpendicular from the centre of the hyperbola xy
The locus of the foot of the perpendicular from the centre of the hyperbola xy = c2 on a variacle tangent is
(A): (x2 - y2)2 = 4c2xy
(B): (x2 + y2)2 = 2c2xy
(C): (x2 + y2)2 = 4x2xy
(D): (x2 + y2)2 = 4c2xy
Best Answer
Correct Answer is:
(D): (D): (x2 + y2)2 = 4c2xy
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