. The oxidation number of sulphur in
H2S2O8 is:
A: + 2
B: + 4
C: + 6
D: + 7
Best Answer
Solution :
The correct answer is Option C i.e. the oxidation state of S in H2S2O8 (Peroxydisulphuric acid) is +6.
H2S2O8 is known as Peroxydisulphiric acid. It is an inorganic compound and is also known as Marshall’s acid.
In the above figure, as it can be clearly seen that the two oxygen atoms between the two Sulphur
atoms are in -1 oxidation state(peroxy linkage), and the OH group as a whole is in -1 oxidation state while all other
Oxygen atoms are in -2 oxidation states. So ,the sulphur in H2S2O8 has to be in +6 oxidation state.
Final Answer:
Hence, the sulphur in H2S2O8 is in +6 oxidation state
Thus, the correct answer is option C. i.e. +6.
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