. The oxidation number of sulphur in

H2S2O8 is:

A: + 2

B: + 4

C: + 6

D: + 7


Best Answer

Solution :

The correct answer is Option C i.e. the oxidation state of S in H2S2O8 (Peroxydisulphuric acid) is +6.

H2S2O8 is known as Peroxydisulphiric acid. It is an inorganic compound and is also known as Marshall’s acid.

Marshall acid    

In the above figure, as it can be clearly seen that the two oxygen atoms between the two Sulphur

atoms are in -1 oxidation state(peroxy linkage), and the OH group as a whole is in -1 oxidation state while all other

Oxygen atoms are in -2 oxidation states. So ,the sulphur in H2S2O8 has to be in +6 oxidation state.

Final Answer:

Hence, the sulphur in H2S2O8 is in +6 oxidation state

Thus, the correct answer is option C. i.e. +6.



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