. The reaction between red lead and hydrochloric acid is given below


The reaction between red lead and hydrochloric acid is given below:

Pb3O+ 8HCl 3PbCl+ 4H2O + Cl2

Calculate: (a) the mass of lead chloride formed by the action of the 6.85 g of red lead, (b) the mass of the chlorine and (c) the volume of the chlorine evolved at S.T.P.

 

Best Answer

(a) Molecular mass of Pb3O= 3×207.2 + 4×16 = 685 g

685 g of Pb3Ogives = 834 g of PbCl2

Hence, 6.85 g of Pb3Owill give = 6.85×834/685 = 8.34 g

 

(b) 685g of Pb3Ogives = 71g of Cl2

Hence, 6.85 g of Pb3Owill give = 6.85 ×71/685 = 0.71 g Cl2

 

(c) 1 V Pb3O4produces 1 V Cl2

685g of Pb3O4has volume = 22.4 litres = volume of Cl2 produced

So, 6.85 Pb3O4 will produce = 6.85×22.4/685 = 0.224 litres of Cl2

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