. The shortest distance of the plane
12 + 4y + 3z = 327, from the sphere X2+Y2+Z2+4x-2y-6z=155 is equal to
A. 39 units
B. 26 sq. units
C. 13 units
D. None of these
Best Answer
Ans: C
Sol: Center and radius of given sphere are (–2, 1, 3) and 13 unit respectively.
Now, distance of center of the sphere from the given plane
Shortest distance = (26 – 13) = 13 units
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