. The temperature of 600 g of cold water rises by 15o C when 300 g of hot water at 50o C is added to it. What was the initial temperature of the cold wa

Best Answer

Mass of hot water (m₁) = 300 g

Temperature (T₁) = 50⁰ C

Mass of cold water (m₂) = 600 g

Change in temperature of cold water (T – T₂) = 15⁰ C

Final temperature = T⁰ C

The specific heat capacity of water is c

m₁c (T₁ – T) = m₂c (T – T₂)

300 (50 – T) = 600 (15)

T = 6000 / 300

T = 20⁰ C

Final temperature = 20⁰ C

Change in temperature = 15⁰ C

Initial temperature of cold water = 20⁰ C – 15⁰ C

= 5⁰ C