. Then the value of m is
The polynomials mz3 + 3z2 – 3 and 2z3 – 5z – 28m when divided by (z – 5) leave the same remainder in each case
a. 1
b. 2
c. 3
d. 4
Best Answer
Sol :a
If mz3 + 3z2 – 3 is divided by (z – 5)
Then the remainder will be
P(5) = m(5)3+ 3(5)2 –3
P(5) = 125m + 72
If 2z3 – 5z – 28m is divided by (z – 5)
Then the remainder will be
P(5) = 2(5)3 – 5(5) – 28m
P(5) = 225 – 28m
The remainder will same in each case.
Then, from (1) and (2) eq.
125m + 72 = 225 – 28m
153m = 153
m = 1
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