. Then the value of m is


The polynomials mz3 + 3z2 – 3 and 2z3 – 5z – 28m when divided by (z – 5) leave the same remainder in each case

a. 1

b. 2

c. 3

d. 4

Best Answer

Sol :a

If mz3 + 3z2 – 3 is divided by (z – 5)

Then the remainder will be

P(5) = m(5)3+ 3(5)2 –3

 P(5) = 125m + 72

 If 2z3 – 5z – 28m is divided by (z – 5)

Then the remainder will be

P(5) = 2(5)3 – 5(5) – 28m

P(5) = 225 – 28m

The remainder will same in each case.

Then,  from (1) and (2) eq.

125m + 72 = 225 – 28m

153m = 153

m = 1

 

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