. Three houses are available in a locality.
Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is
No. of houses = 3 = No. of favourable cases
No. of applicants = 3
Therefore, Total number of events = 33
(because each candidate can apply in 3 ways)
Required probability 3/33=1/9
Hence, option (c) is correct.i.e 1/9