. Three houses are available in a locality.
Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is
A: 1/9
B: 2/9
C: 7/9
D: 8/9
Best Answer
Explanation:
No. of houses = 3 = No. of favourable cases
No. of applicants = 3
Therefore, Total number of events = 33
(because each candidate can apply in 3 ways)
Required probability 3/33=1/9
Final Answer:
Hence, option (c) is correct.i.e 1/9
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