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- Two deuterons undergo nuclear fusion to form a Helium nucleus. The energy released in this process is
. Two deuterons undergo nuclear fusion to form a Helium nucleus. The energy released in this process is
(given binding energy per nucleon for deuteron=1.1 MeV and for helium=7.0 MeV)
A. 30.2 MeV
B. 32.4 MeV
C. 23.6 MeV
D. 25.8 MeV
Best Answer
Ans: C
Sol: Nuclear fusion is a phenomenon in which two or more atomic nuclei are combined to form one or more different atomic nuclei.
Given that two deuterons undergo nuclear fusion to form a Helium nucleus.
1H2 + 1H2----2He4
Initially, the binding energy of deuterons is 1.1 × 4 = 4.4 MeV
Final energy after fusion is, the energy of helium = 4 × 7 = 28 MeV
released energy= 28 – 4.4 = 23.6 MeV
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