. Two deuterons undergo nuclear fusion to form a Helium nucleus. The energy released in this process is


(given binding energy per nucleon for deuteron=1.1 MeV and for helium=7.0 MeV)

A. 30.2 MeV

B. 32.4 MeV 

C. 23.6 MeV

D. 25.8 MeV 

Best Answer

Ans: C

Sol: Nuclear fusion is a phenomenon in which two or more atomic nuclei are combined to form one or more different atomic nuclei. 

Given that two deuterons undergo nuclear fusion to form a Helium nucleus.
 

1H2 + 1H2----2He4 

Initially, the binding energy of deuterons is 1.1 × 4 = 4.4 MeV

Final energy after fusion is, the energy of helium = 4 × 7 = 28 MeV

released energy=  28 – 4.4 = 23.6 MeV

 

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