. Two masses A and B of 10 Kg and 5 Kg respectively


are connected with a string passing over a frictionless pulley at a corner of a table a shown in the adjoining diagram. The coefficient of friction of A with the table is 0.2. The minimum mass of C that may be placed on A to prevent it from moving is equal to?

 

 

Best Answer

Explanation:

The tension working at mass B is 

T=mBg  [Where mB is the mass of B. g is the acceleration]

⇒T=5×10N

⇒T=50N

The tension worked in the blocks of A,C

T=u(mA+mC)g   [Where mA is the mass of A.mC is the mass of C  ,g is the acceleration, is the frictional constant]

⇒T=0.2(10+mC)10

⇒50=20+2mC

⇒mC=50-20/2

⇒mC=15kg

Final Answer:

The mass of the block C is 15kg.

 

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