. Two masses A and B of 10 Kg and 5 Kg respectively
are connected with a string passing over a frictionless pulley at a corner of a table a shown in the adjoining diagram. The coefficient of friction of A with the table is 0.2. The minimum mass of C that may be placed on A to prevent it from moving is equal to?
Best Answer
Explanation:
The tension working at mass B is
T=mBg [Where mB is the mass of B. g is the acceleration]
⇒T=5×10N
⇒T=50N
The tension worked in the blocks of A,C
T=u(mA+mC)g [Where mA is the mass of A.mC is the mass of C ,g is the acceleration, is the frictional constant]
⇒T=0.2(10+mC)10
⇒50=20+2mC
⇒mC=50-20/2
⇒mC=15kg
Final Answer:
The mass of the block C is 15kg.
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