. Two resistors A and B of 4 ohm and 6 ohm respectively are connected in parallel. The combination is connected across a 6 volt battery of negligible re


Best Answer

Given,

Resistance, RA = 4 ohm

Resistance, RB = 6 ohm

Voltage, V = 6 V

(i) Since the resistances are connected in parallel

Equivalent Resistance, 1 / R = 1 / RA + 1 / RB

1 / R = 1 / 4 + 1 / 6

1 / R = 10 / 24

R = 2.4 ohm

We know that,

Power, P = V2 / R

P = (6)2 / 2.4

P = 15 W

(ii) Power dissipation across each resistor, P = VI

Current across resistor RA, IA = V / RA

IA = 6 / 4 = 1.5 A

Power dissipation across resistor RA,

P = VIA

P = 6 × 1.5

P = 9 W

(iii) Current across resistor RB, IB = V / RB

IB = 6 / 6

IB = 1 A

Power dissipation across resistor RB,

P = VIB

P = 6 × 1

P = 6 W

 

Talk to Our counsellor