. Two resistors A and B of 4 ohm and 6 ohm respectively are connected in parallel. The combination is connected across a 6 volt battery of negligible re

Best Answer

Given,

Resistance, R_A = 4 ohm

Resistance, R_B = 6 ohm

Voltage, V = 6 V

(i) Since the resistances are connected in parallel

Equivalent Resistance, 1 / R = 1 / R_A + 1 / R_B

1 / R = 1 / 4 + 1 / 6

1 / R = 10 / 24

R = 2.4 ohm

We know that,

Power, P = V² / R

P = (6)² / 2.4

P = 15 W

(ii) Power dissipation across each resistor, P = VI

Current across resistor R_A, I_A = V / R_A

I_A = 6 / 4 = 1.5 A

Power dissipation across resistor R_A,

P = VI_A

P = 6 × 1.5

P = 9 W

(iii) Current across resistor R_B, I_B = V / R_B

I_B = 6 / 6

I_B = 1 A

Power dissipation across resistor R_B,

P = VI_B

P = 6 × 1

P = 6 W