. Two resistors of 2 ohm and 3 ohm are connected


Two resistors of 2 ohm and 3 ohm are connected (a) in series, (b) in parallel, with a battery of 6.0 V and negligible internal resistance. For each case draw a circuit diagram and calculate the current through the battery.

 

Best Answer

(a)

(A)

R1 = 2 ohm

R2 = 3 ohm

R = R1 + R2

R = 2 + 3

R = 5 ohm

V = 6 V

Now, I = V / R

I = 6 / 5

I = 1.2 ohm

(b)

(B)

Here, R1 and R2 are connected in parallel

1 / R = 1 / R1 + 1 / R2

1 / R = 1 / 2 + 1 / 3

1 / R = (3 + 2) / 6

1 / R = 5 / 6

R = 6 / 5

R = 1.2 ohm

V = 6 V

We know that,

I = V / R

I = 6 / 1.2

I = 5 A

Therefore in series: 1.2 A and in parallel: 5 A

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