. What happens to the force between two objects, if
(i) The distance between the objects is doubled and tripled?
(ii) The masses of both objects are doubled?
Answer: i. If the distance between the objects is doubled and tripled
If it’s doubled
F = (Gm1m2)/(2R)2
F = 1/4 (Gm1m2)/R2
F = F/4
Force thus becomes one-fourth of its initial force.
Now, if it’s tripled
F = (Gm1m2)/(3R)2
F = 1/9 (Gm1m2)/R2
F = F/9
Force thus becomes one-ninth of its initial force.
ii. If masses of both the objects are doubled, then
F = (G2m1 2m2)/R2
F = 4F, Force will therefore be four times greater than its actual value.