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. What is ∆E for the system that does 300 cal of work on surroundings and 500 cal of heat is absorbed by the system

A. -200 cal 
B. -300 cal 
C. +200 cal 
D. +300 cal 
 

Best Answer

(c)

From the First Law of Thermodynamics, ∆U=q+w 
q=+500cal (as heat is absorbed by the system) and 
w=-300cal (as work is done by the system on the surroundings) 
∆U = ∆E = (500cal) + (-300cal) = +200 cal

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