. write chemical equations to show what happens when


(i) ethanol is heated with concentrated sulphuric acid at 443 K.

(ii) ethanol reacts with ethanoic acid in the presence of an acid acting as a catalyst.

(iii) an ester reacts with a base.

 

Best Answer

Ans. (i) When ethyanol is heated with concentrated sulphuric acid at 443k, it gets dehydrated to form ethane

were

(ii) When ethanol reacts with ethanoic acid on warming in the presence of a few drops of conc. Sulphuric acid to from a sweet smelling ester, ethyl ethanoate

were

Ethanoic acid    Ethanol

were

Ethyl Ethanoate     Water

(iii) when an ester is heated with a base ( sodium hydroxide) solution then solution then the ester gets hydrolysed (breaks down) to from the parents alcoholand sodium salt of the carboxylic acid

were

 

 

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