ICSE Class 10 Maths Selina Solutions Chapter 12 Reflection
Neha Tanna17 Feb, 2026
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ICSE Class 10 Mathematics preparation requires special focus on scoring chapters like Coordinate Geometry. Reflection is one of the important topics from this section and is regularly tested in board examinations through direct coordinate-based questions. As the ICSE board 10th Maths exam is scheduled on 2 March 2026, students must ensure complete clarity on reflection in the x-axis, y-axis, origin, and specific lines such as y = x and y = –x.
ICSE Class 10 Maths Selina Solutions Chapter 12 provides detailed, step-by-step solutions to all textbook exercises. These solutions help students understand sign changes, coordinate transformations, and symmetry rules correctly.
ICSE Class 10 Maths Selina Solutions Chapter 12 Reflection Overview
ICSE Class 10 Maths Selina Solutions Chapter 12, titled "Reflection," deals with the concept of reflecting shapes over a line or point to create mirror images. This chapter focuses on understanding how to find the reflected image of a geometric figure and the properties of these reflections, such as symmetry and congruence. ICSE Class 10 Maths Selina Solutions Chapter 12 for this chapter provide detailed, step-by-step answers to textbook problems, helping students grasp these concepts clearly. By working through these solutions, students can improve their problem-solving skills, better understand geometric transformations, and prepare effectively for their exams.ICSE Class 10 Maths Selina Solutions Chapter 12 PDF
Below we have provided ICSE Class 10 Maths Selina Solutions Chapter 12 in detail. This chapter will help you to clear all your doubts regarding the chapter Inequalities. Students are advised to prepare from these ICSE Class 10 Maths Selina Solutions Chapter 12 before the examinations to perform better.ICSE Class 10 Maths Selina Solutions Chapter 12 PDF
ICSE Class 10 Maths Selina Solutions Chapter 12 Exercise 12A
Below we have provided ICSE Class 10 Maths Selina Solutions Chapter 12 –1. Complete the following table:
| Point | Transformation | Image | |
| (a) | (5, -7) | _______________ | (-5, 7) |
| (b) | (4, 2) | Reflection in x-axis | _____ |
| (c) | _____ | Reflection in y-axis | (0, 6) |
| (d) | (6, -6) | _______________ | (-6, 6) |
| (e) | (4, -8) | _______________ | (-4, -8) |
Solution:
| Point | Transformation | Image | |
| (a) | (5, -7) | Reflection in origin | (-5, 7) |
| (b) | (4, 2) | Reflection in x-axis | (4, -2) |
| (c) | (0, 6) | Reflection in y-axis | (0, 6) |
| (d) | (6, -6) | Reflection in origin | (-6, 6) |
| (e) | (4, -8) | Reflection in y-axis | (-4, -8) |
2. A point P is its own image under the reflection in a line l. Describe the position of point the P with respect to the line l.
Solution:
As, the image of the point P is the same point under the reflection in the line l we can say, point P is an invariant point. Thus, the position of point P remains unaltered.3. State the co-ordinates of the following points under reflection in x-axis:
(i) (3, 2)
(ii) (-5, 4)
(iii) (0, 0)
Solution:
(i) (3, 2) The co-ordinates of the given point under reflection in the x-axis are (3, -2). (ii) (-5, 4) The co-ordinates of the given point under reflection in the x-axis are (-5, -4). (iii) (0, 0) The co-ordinates of the given point under reflection in the x-axis are (0, 0).4. State the co-ordinates of the following points under reflection in y-axis:
(i) (6, -3)
(ii) (-1, 0)
(iii) (-8, -2)
Solution
(i) (6, -3) The co-ordinates of the given point under reflection in the y-axis are (-6, -3). (ii) (-1, 0) The co-ordinates of the given point under reflection in the y-axis are (1, 0). (iii) (-8, -2) The co-ordinates of the given point under reflection in the y-axis are (8, -2).5. State the co-ordinates of the following points under reflection in origin:
(i) (-2, -4)
(ii) (-2, 7)
(iii) (0, 0)
Solution:
(i) (-2, -4) The co-ordinates of the given point under reflection in origin are (2, 4). (ii) (-2, 7) The co-ordinates of the given point under reflection in origin are (2, -7). (iii) (0, 0) The co-ordinates of the given point under reflection in origin are (0, 0).6. State the co-ordinates of the following points under reflection in the line x = 0:
(i) (-6, 4)
(ii) (0, 5)
(iii) (3, -4)
Solution:
(i) (-6, 4) The co-ordinates of the given point under reflection in the line x = 0 are (6, 4). (ii) (0, 5) The co-ordinates of the given point under reflection in the line x = 0 are (0, 5). (iii) (3, -4) The co-ordinates of the given point under reflection in the line x = 0 are (-3, -4).7. State the co-ordinates of the following points under reflection in the line y = 0:
(i) (-3, 0)
(ii) (8, -5)
(iii) (-1, -3)
Solution:
(i) (-3, 0) The co-ordinate of the given point under reflection in the line y = 0 is (-3, 0). (ii) (8, -5) The co-ordinate of the given point under reflection in the line y = 0 is (8, 5). (iii) (-1, -3) The co-ordinate of the given point under reflection in the line y = 0 is (-1, 3).8. A point P is reflected in the x-axis. Co-ordinates of its image are (-4, 5).
(i) Find the co-ordinates of P.
(ii) Find the co-ordinates of the image of P under reflection in the y-axis.
Solution:
(i) As, M x (-4, -5) = (-4, 5) Hence, the co-ordinates of P are (-4, -5). (ii) Co-ordinates of the image of P under reflection in the y-axis (4, -5).9. A point P is reflected in the origin. Co-ordinates of its image are (-2, 7).
(i) Find the co-ordinates of P.
(ii) Find the co-ordinates of the image of P under reflection in the x-axis.
Solution:
(i) As, M O (2, -7) = (-2, 7) Hence, the co-ordinates of P are (2, -7). (ii) Co-ordinates of the image of P under reflection in the x-axis (2, 7)ICSE Class 10 Maths Selina Solutions Chapter 12 Exercise 12(B)
1. Attempt this question on graph paper.
(a) Plot A (3, 2) and B (5, 4) on graph paper. Take 2 cm = 1 unit on both the axes.
(b) Reflect A and B in the x-axis to A’ and B’ respectively. Plot these points also on the same graph paper.
(c) Write down:
(i) the geometrical name of the figure ABB’A’;
(ii) the measure of angle ABB’;
(iii) the image of A” of A, when A is reflected in the origin.
(iv) the single transformation that maps A’ to A”.
Solution:
(c) (i) From the graph, it’s clearly seen that ABB’A’ is an isosceles trapezium. (ii) The measure of angle ABB’ is 45°. (iii) A” = (-3, -2) (iv) Single transformation that maps A’ to A” is the reflection in y-axis.2. Points (3, 0) and (-1, 0) are invariant points under reflection in the line L 1 ; points (0, -3) and (0, 1) are invariant points on reflection in line L 2 .
(i) Name or write equations for the lines L 1 and L 2 .
(ii) Write down the images of the points P (3, 4) and Q (-5, -2) on reflection in line L 1 . Name the images as P’ and Q’ respectively.
(iii) Write down the images of P and Q on reflection in L 2 . Name the images as P” and Q” respectively.
(iv) State or describe a single transformation that maps P’ onto P”.
Solution:
(i) We know that, every point in a line is invariant under the reflection in the same line. As the points (3, 0) and (-1, 0) lie on the x-axis. Thus, (3, 0) and (-1, 0) are invariant under reflection in x-axis. Therefore, the equation of line L 1 is y = 0. Similarly, (0, -3) and (0, 1) are also invariant under reflection in y-axis. Therefore, the equation of line L 2 is x = 0. (ii) P’ = Image of P (3, 4) in L 1 = (3, -4) And, Q’ = Image of Q (-5, -2) in L 1 = (-5, 2) (iii) P” = Image of P (3, 4) in L 2 = (-3, 4) And, Q” = Image of Q (-5, -2) in L 2 = (5, -2) (iv) Single transformation that maps P’ onto P” is reflection in origin.3. (i) Point P (a, b) is reflected in the x-axis to P’ (5, -2). Write down the values of a and b.
(ii) P” is the image of P when reflected in the y-axis. Write down the co-ordinates of P”.
(iii) Name a single transformation that maps P’ to P”.
Solution:
(i) As, M x (x, y) = (x, -y) P’ (5, -2) = reflection of P (a, b) in x-axis. Hence, the co-ordinates of P are (5, 2). Thus, a = 5 and b = 2. (ii) P” = image of P (5, 2) reflected in y-axis = (-5, 2) (iii) Single transformation that maps P’ to P” is the reflection in origin.4. The point (-2, 0) on reflection in a line is mapped to (2, 0) and the point (5, -6) on reflection in the same line is mapped to (-5, -6).
(i) State the name of the mirror line and write its equation.
(ii) State the co-ordinates of the image of (-8, -5) in the mirror line.
Solution:
(i) We know that, reflection of a point (x, y) in y-axis is (-x, y). So, the point (-2, 0) when reflected in y-axis is mapped to (2, 0). Hence, the mirror line is the y-axis and it’s equation is x = 0. (ii) The co-ordinates of the image of (-8, -5) in the mirror line (i.e., y-axis) are (8, -5).5. The points P (4, 1) and Q (-2, 4) are reflected in line y = 3. Find the co-ordinates of P’, the image of P and Q’, the image of Q.
Solution:
The line y = 3 is a line parallel to x-axis and at a distance of 3 units from it. Let’s mark the points P (4, 1) and Q (-2, 4). Now from P, draw a straight line perpendicular to line CD and produce. Mark a point P’ on this line which is at the same distance above CD as P is below it. Thus, the co-ordinates of P’ are (4, 5). Similarly, from Q, draw a line perpendicular to CD and mark point Q’ which is at the same distance below CD as Q is above it. Hence, the co-ordinates of Q’ are (-2, 2).
6. A point P (-2, 3) is reflected in line x = 2 to point P’. Find the coordinates of P’.
Solution:
The line x = 2 is a line parallel to y-axis and at a distance of 2 units from it. Let’s mark the point P (-2, 3). From P, draw a straight line perpendicular to line CD and produce. Mark a point on this line which is at the same distance to the right of CD as P is to the left of it. Hence, the co-ordinates of P’ are (6, 3).
7. A point P (a, b) is reflected in the x-axis to P’ (2, -3). Write down the values of a and b. P” is the image of P, reflected in the y-axis. Write down the co-ordinates of P”. Find the co-ordinates of P”’, when P is reflected in the line, parallel to y-axis, such that x = 4.
Solution:
A point P (a, b) is reflected in the x-axis to P’ (2, -3). We know that, M x (x, y) = (x, -y) Hence, the co-ordinates of P are (2, 3). And thus, a = 2 and b = 3. P” = Image of P reflected in the y-axis = (-2, 3) P”’ = Reflection of P in the line (x = 4, a line parallel to y-axis and at a distance of 4 units from it) = (6, 3)
8. Points A and B have co-ordinates (3, 4) and (0, 2) respectively. Find the image:
(a) A’ of A under reflection in the x-axis.
(b) B’ of B under reflection in the line AA’.
(c) A” of A under reflection in the y-axis.
(d) B” of B under reflection in the line AA”.
Solution:
(a) A’ = Image of A under reflection in the x-axis = (3, -4) (b) B’ = Image of B under reflection in the line AA’ (x = 3) = (6, 2) (c) A” = Image of A under reflection in the y-axis = (-3, 4) (d) B” = Image of B under reflection in the line AA” (y = 4) = (0, 6)
Common Mistakes to Avoid in Reflection
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Confusing reflection in the x-axis with reflection in the y-axis
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Forgetting to change the correct coordinate sign
-
Making errors while reflecting in the origin
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Not carefully reading whether reflection is over a line or an axis
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Skipping diagram-based verification of the reflected image
Avoiding these common mistakes can significantly improve accuracy in examinations.
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