RBI Office Attendant 2026 Reasoning Super Mock - 1

RBI Office Attendant 2026 Reasoning Super Mock – 1 is designed to help aspirants evaluate their preparation and strengthen core reasoning skills required for the exam. This mock test covers all high-weightage topics such as Inequalities, Coding-Decoding, Syllogism, Alphanumeric Series, Blood Relations, Direction and Distance, and puzzle-based arrangements.

Each question reflects the latest exam pattern and difficulty level, enabling candidates to build speed, accuracy, and confidence. By practicing this super mock, students can identify weak areas, improve logical thinking, and develop an effective exam strategy. Regular mock practice plays a vital role in boosting overall performance in competitive banking examinations.

RBI Office Attendant 2026 Reasoning Super Mock - 1

RBI Office Attendant 2026 Reasoning Super Mock – 1 is a focused practice test designed to strengthen key reasoning concepts and improve exam readiness. It covers all important topics as per the latest pattern.

Check below to attempt the mock, analyze your performance, and fine-tune your preparation for the RBI Office Attendant exam.

RBI Office Attendant Reasoning Section Introduction

The Reasoning section is crucial for the RBI Office Attendant exam. This analysis focuses on developing effective problem-solving strategies across various logical reasoning topics. Mastering these concepts and techniques, from deductive logic in syllogisms to systematic approaches for puzzles, is vital for achieving high scores and ensuring targeted preparation for success.

Inequalities

This section focuses on solving inequality problems by establishing a logical path between elements.

Problem 1

• Statements: J ≤ H, H ≤ F

• Conclusions:

1. J = F

2. J < F

• Analysis: Combining statements gives J ≤ H ≤ F, which simplifies to J ≤ F. This means either J < F or J = F. The conclusions (J = F and J < F) cover the possibilities within J ≤ F. However, the first conclusion J ≤ F is directly proven true. The second conclusion J < F is not definitively true on its own.

• Answer: Only Conclusion 1 follows.

Problem 2

• Conclusions:

1. R > A

2. M < T

• Analysis:

• Tracing the path from R to A does not establish R > A. Conclusion 1 is false.

• The path from M to T shows T > M, which means M < T. Conclusion 2 is true.

• Answer: Only Conclusion 2 follows.

Problem 3

• Statements: (Symbol-based, implying m% > # or similar relationships)

• Conclusions:

1. # > %

2. % ≥ @

• Analysis:

• Tracing the path from m% to # reveals a > sign, establishing # > %. Conclusion 1 is true.

• The path for the second conclusion contains a strict > sign, invalidating the ≥ possibility. Conclusion 2 is false.

• Answer: Only Conclusion 1 follows.

Chinese Coding-Decoding

This section demonstrates the elimination method for quickly solving Chinese Coding-Decoding problems. Speed is the most critical factor, with a target of 30 seconds per question.

Provided Codes:

• value of high tech

• high million world tax

• scale value people word

• in high of sector people

Problem 1: Find the code for 'scale'.

• Analysis: 'scale' appears only in the third line. Eliminate codes for 'value', 'people', 'word' by finding their occurrences elsewhere. The unique code remaining for 'scale' is XV.

• Answer: XV

Problem 2: Find the code for 'million of'.

• Analysis:

• 'million' is in the second line. Eliminating codes for 'high', 'world', 'tax' yields NG.

• 'of' is common to the first and fourth lines. Its common code is cl.

• Answer: NG cl

Problem 3: Find the code for 'sector'.

• Analysis: 'sector' appears only in the fourth line. Eliminating codes for 'in', 'high', 'of', 'people' yields TB.

• Answer: TB

Problem 4: Identify the word for the code UB.

• Analysis: Comparing the given codes and words, UB corresponds to 'tech'.

• Answer: tech

Syllogisms

This section covers solving syllogism problems using Venn diagrams, with a focus on "Only a few," "Possibility," and "Either/Or" cases.

Problem 1

• Statements:

1. All Cool is Hot.

2. Only a few Hot is Open.

3. No Cool is Open.

• Conclusions:

1. All Open can be Hot. (A possibility)

2. Some Open is Cool is a possibility.

• Analysis:

1. Only a few Hot is Open implies Some Hot is Open and Some Hot is not Open. This does not restrict all of Open from being inside Hot. Conclusion 1 is true.

2. There is a definite No Cool is Open relationship. Thus, Some Open is Cool is impossible. Conclusion 2 is false.

• Answer: Only 1 follows.

Problem 2

• Statements:

1. Only a few Room are Flat.

2. Only a few Flat are House.

3. No House is Building.

• Conclusions:

1. All Room being House is a possibility.

2. Some Flat are not Building.

• Analysis:

1. No direct or indirect negative relationship exists between Room and House, so the possibility exists. Conclusion 1 is true.

2. From Only a few Flat are House, we know Some Flat are House. Since No House is Building, the portion of Flat that is House cannot be Building. Thus, Some Flat are not Building is definite. Conclusion 2 is true.

• Answer: Both follow.

Problem 3

• Statements:

1. No Rose is Jasmine.

2. All Jasmine are Lotus.

3. A few Lotus are Marigold. (A few means Some)

• Conclusions:

1. All Marigold are Jasmine.

2. Some Marigold are Jasmine.

• Analysis: No definite relationship exists between Marigold and Jasmine. Individually, both conclusions are false. However, they form an Either/Or case for the elements Marigold and Jasmine. (The instructor points out the "All / Some" pair can signify Either/Or).

• Answer: Either/Or.

Problem 4

• Statements:

1. Only a few Cream are Lotion.

2. Only a few Lotion is Moisturizer.

3. All Moisturizer is Foam.

• Conclusions:

1. All Lotion being Foam is a possibility.

2. Some Cream is not Foam.

• Analysis:

1. Since Some Lotion is Moisturizer and All Moisturizer is Foam, it is possible for the entire 'Lotion' to be contained within 'Foam'. Conclusion 1 is true.

2. No information restricts Cream from being Foam. Some Cream is not Foam cannot be definitively concluded. Conclusion 2 is false.

• Answer: Only 1 follows.

Problem 5

• Statements:

1. Some Balls are Eyes.

2. Some Eyes are Dums.

3. All Slabs are Balls.

• Conclusions:

1. Some Slab are Eye.

2. No Eye is Slab.

• Analysis: There is no definite relationship between Slab and Eye. Both conclusions are individually false. However, they form a complementary pair (Some + No) concerning the same elements (Slab, Eye), fulfilling the conditions for an Either/Or case.

• Answer: Either/Or.

Alphanumeric Series (Number-Based)

This section focuses on operations on a series of numbers, emphasizing speed and careful instruction reading.

Number Series: 928, 548, 237, 109, 675

Problem 1

• Instruction: Arrange all numbers in ascending order. Which number will be exactly in the middle?

• Analysis: Ascending order: 109, 237, **548**, 675, 928. The middle number is 548.

• Answer: 548

Problem 2

• Instruction: If 1 is subtracted from each number, which of the resulting numbers will have only odd digits?

• Analysis:

• 928 - 1 = 927 (contains 2, an even digit)

• 548 - 1 = 547 (contains 4, an even digit)

• 237 - 1 = 236 (contains 2, 6, even digits)

• 109 - 1 = 108 (contains 0, 8, even digits)

• 675 - 1 = 674 (contains 4, an even digit)

• Answer: None. (The instructor differentiates 'None' meaning zero, from 'None of these' meaning the answer exists but isn't an option.)

Problem 3

• Instruction: What is the third digit of the fourth highest number in the sequence?

• Analysis: The numbers in descending order are: 928, 675, 548, **237**, 109. The fourth highest number is 237. Its third digit is 7.

• Answer: 7

Problem 4

• Instruction: If the first digit of each number is dropped, how many of the new numbers will be less than 58?

• Analysis:

• 928 → 28 (< 58)

• 548 → 48 (< 58)

• 237 → 37 (< 58)

• 109 → 09 (< 58)

• 675 → 75 (not < 58)

• Answer: Four (more than three).

Problem 5

• Instruction: Which number will become the third highest if the second digit of each number is dropped?

• Analysis: Since all the first digits are unique, dropping the second digit will not change the relative order of the numbers. Therefore, the original third highest number remains the third highest. The original third highest number was 548.

• Answer: 548

Blood Relations Puzzle

Problem Statement: A family has 9 members. Every male member has a sister. Only married couples have children. N is the son of M. N is the father of T. T is the granddaughter of P. Q is the daughter-in-law of P. O is the brother-in-law of P. S is married to O and has no siblings. R does not belong to O's generation.

Analysis and Resolution:

The crucial clarifying clue is that O is P's wife's brother.

Final Arrangement:

• Generation 1: P (male) is married to U (female). U has a brother, O.

• Generation 2: O (male) is married to S (female). P and U have a son, N, and a daughter, R. N (male) is married to Q (female).

• Generation 3: N and Q have a daughter, T.

Structure Overview:

• P and U are a couple. O is U's brother. S is O's wife.

• N and R are children of P and U. N is a male, R is a female.

• N and Q are a couple. T is their daughter.

• This structure ensures all conditions are met, including "Every male member has a sister" (N has R, O has U, P has U's sister U, if U is seen as a 'sister' from O's perspective for P, or P has U's sister-in-law. More directly, N has R). T is P's granddaughter, Q is P's daughter-in-law.

Question: How is R related to T?

• Answer: R is T's father's sister, making R the Aunt of T.

Direction and Distance

Problem Walkthrough:

1. Point P is 17m West of Q.

2. Q is 9m North of R.

3. W is 9m South of P. (This places W directly West of R, at the same horizontal level as R).

4. W is 6m North of V.

5. S is 15m East of R.

6. T is 22m North of S.

7. T is 15m West of U. (This places U directly North of R, 22m North).

Question: What is the shortest distance between W and R?

• Analysis: From the established positions, W is 9m South of P, and Q is 9m North of R. Since P is 17m West of Q, and W and R are vertically aligned with P and Q respectively, the horizontal distance between W and R is the same as between P and Q.

• Answer: 17m.

Month-Based Puzzle

Problem Statement: Nine people (P, Q, R, S, T, U, V, W, X) were born in nine different months: Jan, Mar, Apr, May, Jul, Aug, Sep, Oct, Nov.

Setup and Key Clues:

• Step 1: List months and their days accurately:

• Jan (31), Mar (31), Apr (30), May (31), Jul (31), Aug (31), Sep (30), Oct (31), Nov (30).

• Clue 1: Q was born in a month with 30 days, after July -> Q is in September.

• Clue 2: T was born after Q and before R -> This places T in October and R in November.

• Clue 3: Four people were born between P and T. P was born before T -> Counting back four slots from T (October) places P in April.

• Clue 4: As many people were born before X as after R -> R is in the last month (November). Therefore, X must be in the first month. X is in January.

• Clue 5: S was born before U and after W (W…S…U).

• Clue 6: One person was born between U and V.

• Final Placement: Based on remaining slots and clues 5 & 6:

• W in March

• S in May

• U in July

• V in August

Final Arrangement:

Question: Four of the following five are alike (T, R, V, U, S). Find the odd one out.

• Analysis:

• T (October - 31 days)

• V (August - 31 days)

• U (July - 31 days)

• S (May - 31 days)

• R (November - 30 days)

• Answer: R, as he was born in a month with 30 days, while the others were born in months with 31 days.

Linear Arrangement Puzzle

Problem Statement: Seven people (A, B, C, D, E, F, G) are sitting in a row.

Analysis and Arrangement:

• Clue 1: Only two people sit to the left of F. This places F at the 3rd position: _ _ F _ _ _ _

• Clue 2: B sits second to the right of G, and G is to the immediate right of D. This forms a block: D G _ B.

• Clue 3: A sits at one of the extreme ends.

• Clue 4: C is an immediate neighbor of F.

• Clue 5: E sits to the immediate left of B. This refines the block to D G E B.

Solving:

• Place the D G E B block into the _ _ F _ _ _ _ structure. The only fitting arrangement is _ _ F D G E B.

• A must be at the extreme left end: A _ F D G E B.

• C is an immediate neighbor of F. The only remaining spot next to F is the second position: A C F D G E B.

Final Arrangement:

A C F D G E B

Question: Who are the neighbors of E?

• Answer: G and B.