Question of Exercise 2

Probability of Class 9

Question
The probability that in the toss of two dice we obtain the sum of 7 or 11 is

Answer

Option 1 1/6

Option 2 1/18

Option 3 2/9

Option 4 23/108

Frequently Asked Questions

Represent Root 9 point 3 on the number line

Solution:

Explanation:

Step 1: Draw a line segment AB of length 9.3 units.

Step 2: Now, Extend the line by 1 unit more such that BC=1 unit .

Step 3: Find the midpoint of AC.

Step 4: Draw a line BD perpendicular to AB and let it intersect the semicircle at point D.

Step 5: Draw an arc DE such that BE=BD.

Represent1

Final Answer:

Hence, Number line of √ 9.3 is attached below.

 

Which one of the following statement is true

 

A: Only one line can pass through a single point.

B: There are an infinite number of lines which pass through two distinct points.

C: Two distinct lines cannot have more than one point in common.

D: If two circles are equal, then their radii are not equal.

 

Solution:

Explanation:

From one point there is an uncountable number of lines that can pass through.

Hence, the statement “ Only one line can pass through a single point” is false.

We can draw only one unique line passing through two distinct points.

Hence, the statement “There are an infinite number of lines which pass through two distinct points” is false.

Given two distinct points, there is a unique line that passes through them.

Hence, the statement “Two distinct lines cannot have more than one point in common” is true.

If circles are equal, which means the circles are congruent. This means that circumferences are equal and so the radii of two circles are also equal.

Hence, the statement “If two circles are equal, then their radii are not equal” is false.

Final Answer:

The correct option is (C) Two distinct lines cannot have more than one point in common.

 

The class mark of the class 90-120 is

A: 90

B: 105

C: 115

D: 120

 

Solution:

Explanation:

To find the class mark of a class interval, we find the sum of the upper limit and lower limit of a class and divide it by 2 Thus,

Class -mark=Upper limit + Lower limit/2

Here, the lower limit of 90-120=90

And the upper limit of 90-120=120

So, 

Class -mark=120+90/2

=210/2

=105

Hence, the class mark of the class 90-120 is 105

That is, option (B) is correct.

Final Answer:

Option (B) 105  is correct.

 

ABCD is a parallelogram and AP

and CQ are perpendiculars from vertices A and C on diagonal BD Show that i)ΔAPBΔCQD ii) AP = CQ

perpendiculars

Solution:

parallelogram

parallelogram2

Find the roots of the following equation

roots of

A: - 1, - 2

B: - 1, - 3

C: 1,3

D: 1,2

 

Solution:

Explanation:-

roots of1

Final answer:-

Hence the correct option is (D) i.e. 1,2.

 

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