Solution
From the given table, we may prepare the (less than type) cumulative frequency table as shown below:
|
Age (in years)
|
c.f.
|
|
Less than 5
|
36
|
|
Less than 6
|
78
|
|
Less than 7
|
130
|
|
Less than 8
|
190
|
|
Less than 9
|
258
|
|
Less than 10
|
342
|
|
Less than 11
|
438
|
|
Less than 12
|
520
|
|
Less than 13
|
586
|
|
Less than 14
|
634
|
|
Less than 15
|
684
|
|
Less than 16
|
700
|
On a graph paper, we plot the points (5, 36), (6, 78), (7, 130), (8, 190), (9, 258), (10, 342), (11, 438), (12, 520), (13, 586), (14, 634), (15, 684), (16, 700).
We join these points successively to get the cumulative frequency curve or an ogive.
Here,

Take a point
on the y-axis and draw AP II x-axis, meeting the curve at P. Draw PM ⊥x-axis, intersecting the x-axis at M.
Then, OM = 10 units, and hence median = 10.