CSIR NET Chemical Science July 2026 Memory Based Questions

CSIR NET Chemical Science July 2026 Memory Based Questions: The National Testing Agency (NTA) is the governing body to organise the CSIR NET exam. CSIR NET Chemical Science exam has been concluded on July 18, 2026. A list of the CSIR NET Chemical Science July 2026 Memory Based Questions compiled based on the candidates' responses recorded after the exam. Candidates can know the topics and types of questions. 

CSIR NET Chemical Science July 2026 Memory Based Questions Overview

CSIR NET Chemical Science July 2026 is a CBT online paper for the July 2026 exam, organised on July 18, 2026. NTA has conducted the paper on behalf of CSIR NET. 

CSIR NET Chemical Science Exam Review 2026

The CSIR NET Chemical Science Exam Review 2026 is based on candidates' feedback after the examination. Candidates observed that the exam level was expected to be moderate to difficult. Chemical Science examination included mostly the conceptual and application-based questions asked in the paper. 

Topics Asked In CSIR NET Chemical Science July 2026 Exam

A list of the topics asked in the CSIR NET Chemical Science July 2026 Exam considered the candidates' feedback recorded who appeared in the exam. 

Organic Chemistry

• Reactive Intermediates (Carbocations, Carbanions, Free Radicals, Benzynes)

• Nucleophilic Substitution and Elimination mechanisms

• Stereochemistry (Stereogenicity, Stereoselectivity, Enantioselectivity)

• Pericyclic Reactions and Named Organic Reactions

Inorganic Chemistry

• Coordination Compounds and Crystal Field Theory (CFT)

• Organometallic Compounds and homogenous catalytic cycles

• Transition metal complexes (Spectroscopic and magnetic properties)

Physical Chemistry

• Quantum Chemistry equations

• Chemical Kinetics and Thermodynamics

• Solid State Chemistry and Group Theory

• Electrochemistry

Analytical Techniques

• Chromatography and Spectroscopy interpretation

CSIR NET Chemical Science July 2026 Memory Based Questions

Candidates can check the memory based questions of the Chemical Science exam. The information has been collected based on the candidates' responses collected after the exam shift is over. Future aspirants can solve the questions to know the pattern covered in the exam. 

• Bridging Carbonyls Count: Finding the number of bridging CO ligands in metal carbonyl clusters by comparing Co₄(CO)₁₂, Rh₄(CO)₁₂, and Ir₄(CO)₁₂.

• Answer pattern: Co₄(CO)₁₂ = 3, Rh₄(CO)₁₂ = 0, Ir₄(CO)₁₂ = 0 (3, 0, 0)

• CO Stretching Frequency Order (νCO): Determining the νCO stretching frequency order for Ni(CO)(PR₃)₃ by comparing substituents –F, –CH₃, –Ph, –OMe.

• Rule: More electron-withdrawing ligand → Less back-bonding → Higher νCO

• More electron-donating ligand → More back-bonding → Lower νCO

• EPR Hyperfine Lines and Intensity: Calculating the number of hyperfine lines using the formula:

• Number of lines = 2nI + 1

• Where n = number of equivalent nuclei and I = nuclear spin

• For 3 equivalent ¹⁴N nuclei (I = 1):

• 2 × 3 × 1 + 1 = 7 lines

• Intensity ratio: 1 : 3 : 6 : 7 : 6 : 3 : 1

• Bragg's Law Sin θ Calculation: Solving Solid State numerical problems using:

• Bragg's Law: nλ = 2d sinθ

• Interplanar spacing: d = a / √(h² + k² + l²)

• Given values such as λ = 154 pm, a = 0.5 nm, and (hkl) = (2,2,1), calculate d, then sinθ, and finally θ.

• Vibrational Spectroscopy Overtone: Finding ωₑ and ωₑxₑ using:

• Fundamental transition: ν₀→₁ = ωₑ − 2ωₑxₑ

• First overtone: ν₀→₂ = 2ωₑ − 6ωₑxₑ

• Solve the two equations simultaneously.

• Isolobal Analogy: Identifying organometallic fragments isolobal to a CH₂ fragment.

• CH₂ fragment: 6 valence electrons

• Common isolobal fragments: Fe(CO)₄ (16 VE) and [Co(CO)₄]⁺ (16 VE)

• Symmetry Polarised Transition: Determining whether an electronic transition in a C₃v point group is Z-polarised.

• Selection rule: Γ(initial) × Γ(z) × Γ(final) must contain A₁.

• In C₃v: z → A₁, (x, y) → E

• Maximum Degeneracy Calculations: Calculating maximum degeneracy for different systems.

• Hydrogen atom: Maximum degeneracy = 2n²

• Rigid rotor: Degeneracy = 2J + 1

• Simple Harmonic Oscillator (SHO): Degeneracy = 1 (non-degenerate)