The CSIR NET Life Science July 2026 examination tested candidates on conceptual understanding, analytical reasoning, and numerical problem-solving across the complete Life Science syllabus. According to students, the paper maintained a moderate difficulty level, with several questions requiring application of core biological concepts rather than direct factual recall.
This article provides a topic-wise collection of memory-based questions with explanations, helping aspirants understand the exam pattern while serving as a valuable revision resource for future CSIR NET, GATE Biotechnology, DBT BET, and other Life Science competitive examinations.
Question:
Original Km = 16, Apparent Km = 24, Inhibitor concentration = 6. Calculate Ki.
Competitive inhibition follows:
α = Apparent Km / Original Km
= 24 /16
= 1.5
Using
α = 1 + [I]/Ki
1.5 = 1 + 6/Ki
Ki = 12
Correct Answer: Ki = 12
Key Concept
Competitive inhibitors increase Km
Vmax remains unchanged
The catalytic F₁ portion of ATP Synthase possesses three-fold symmetry, consisting of:
3 α subunits
3 β subunits
Central γ subunit
The rotating γ subunit drives ATP synthesis.
| Amino Acid | Important Property |
| Glycine | Smallest amino acid; nonpolar |
| Histidine | Contains imidazole ring |
| Threonine | Polar, hydroxyl-containing |
| Cysteine | Contains thiol (-SH), forms disulfide bonds |
A question stated that two genes are 20 cM apart.
20 cM = 20% recombination frequency
Genes remain linked but recombine in 20% of meioses.
The developing heart:
Originates from Mesoderm
Starts forming around Day 18–19
Develops before lungs
A memory-based question asked about Erythroblastosis Fetalis.
Correct Concept
Occurs when:
Mother = Rh negative
Baby = Rh positive
Maternal antibodies destroy fetal RBCs.
Cross:
Carrier Mother × Normal Father
Result:
| Offspring | Probability |
| Normal daughters | 100% |
| Normal sons | 50% |
| Hemophilic sons | 50% |
| Hemophilic daughters | 0% |
Correct sequence:
5′ Capping
RNA Splicing
Polyadenylation
Nuclear Export
mRNA Degradation
Cytosine → Guanine
Since:
Cytosine = Pyrimidine
Guanine = Purine
This is a Transversion Mutation.
Important proteins involved:
RAG1
RAG2
Terminal deoxynucleotidyl transferase (TdT)
These generate antibody diversity.
| Repair Type | Major Protein |
| Base Excision Repair | DNA Glycosylase |
| Mismatch Repair | MutS, MutL |
| Homologous Recombination | Rec proteins |
| Translesion Synthesis | Error-prone DNA Polymerases |
| Protein | Function |
| CI Repressor | Maintains lysogenic cycle |
| Cro Protein | Promotes lytic cycle |
| Release Factor | Stop Codons |
| RF1 | UAA, UAG |
| RF2 | UAA, UGA |
| RF3 | Releases RF1 & RF2 |
Students were asked about PAGE and SDS-PAGE.
Important facts:
SDS provides uniform negative charge.
Separation occurs according to molecular weight.
Acrylamide concentration determines pore size.
Higher acrylamide → Smaller pores.
| Condition | Net Charge |
| pH < pI | Positive |
| pH = pI | Neutral |
| pH > pI | Negative |
Fluidity increases with:
Short-chain fatty acids
Cis-unsaturated fatty acids
Answer: HTLV
Human T-cell Leukemia Virus causes leukemia.
| Molecule | Presented To |
| MHC-I | CD8+ T cells |
| MHC-II | CD4+ T cells |
Golgi-derived vesicles form the cell plate during cytokinesis.
Cellulose is synthesized at the plasma membrane.
Important regulators:
Cyclin D + CDK4/6 → G1 phase
Cyclin E → G1/S transition
APC promotes anaphase progression
ABC transporters use ATP hydrolysis for transport.
A classic example is CFTR, which functions as a chloride channel.
Examples of free-living nitrogen-fixing organisms:
Azotobacter
Clostridium
Nostoc
Calothrix
Primary precursor:
Tryptophan
Mevalonic acid is not an auxin precursor.
Two models were tested:
ABC Model
ABCDE Model
Glyceraldehyde-3-phosphate (G3P):
High Pi → Sucrose synthesis
Low Pi → Starch synthesis
Paraquat accepts electrons from Photosystem I and generates reactive oxygen species (ROS), ultimately damaging plant cells.
Energy pyramid is always upright because energy decreases at every trophic level.
| Succession Type | P/R Ratio |
| Autotrophic | >1 |
| Heterotrophic | <1 |
The logistic growth curve approaches carrying capacity (K) as resources become limited.
| Index | Measures |
| Simpson Index | Dominance and diversity |
| Shannon Index | Diversity and evenness |
Given:
q² = 1/1100
Then:
q ≈ 0.03
p ≈ 0.97
2pq ≈ 0.058
Answer: Approximately 6% heterozygotes
Large population
Random mating
No mutation
No migration
No natural selection
| r-selected | K-selected |
| Small body size | Large body size |
| Many offspring | Few offspring |
| Rapid reproduction | Slow reproduction |
| Type III survivorship | Type I survivorship |
Formula:
n = (log N − log N₀)/log2
Generation Time:
G = t/n
COMT metabolizes:
Epinephrine
Norepinephrine
Acetylcholine is degraded by Acetylcholinesterase, not COMT.
| Enzyme | Product |
| Papain | 2 Fab + Fc |
| Pepsin | F(ab')₂ |
Highest secretion occurs from:
Mast Cells
Mycobacterial infections produce Delayed-Type (Type IV) Hypersensitivity.
Formula:
t½ = 0.693 / λ
If λ = 0.02 min⁻¹
Answer:
34.65 minutes
Genome = 50 Mb
Coverage = 100×
Required sequencing data:
5000 Mb = 5 Gb
Procaine and Tetracaine block voltage-gated sodium channels, preventing nerve impulse transmission.
Trypsin cleaves after:
Lysine
Arginine
Cleavage does not occur when Proline follows these residues.
Phototransduction begins when:
11-cis retinal → all-trans retinal
Kingdom → Division → Class → Order → Family → Genus → Species
Examples:
Crystal Violet
Methylene Blue
Radio waves are reflected by the Ionosphere, enabling long-distance communication.
The July 2026 paper emphasized conceptual clarity, numerical problem-solving, and application-based learning rather than direct factual recall. Topics such as enzyme kinetics, Hardy-Weinberg equilibrium, DNA repair, electrophoresis, immunology, ecology, and plant physiology carried significant weight. Aspirants preparing for upcoming CSIR NET examinations should strengthen their fundamentals, practice numerical questions, and revise molecular biology, genetics, cell biology, and ecology thoroughly.
