CUET 2026 General Aptitude Test Paper Analysis: Difficulty Level, Important Questions & Preparation Strategy

CUET 2026 General Aptitude Test Paper Analysis: The General Aptitude Test (GAT) for CUET 2026 primarily assesses fundamental concepts in Quantitative Aptitude and Reasoning. Based on past analyses, the paper is not very difficult, featuring mostly basic questions. The strategy focuses on conceptual clarity, formula application, and consistent practice for predictable sections, while managing time and exam pressure. Effective preparation involves revisiting core GAT concepts, practicing extensively, and maintaining composure during the exam.

CUET 2026 General Aptitude Test Paper Analysis

I. General Aptitude Test (GAT) Exam Analysis & Preparation Strategy

The GAT is typically straightforward, with some shifts including 5-8 Static GK questions. A robust preparation strategy is vital for success:

• Don't Panic: Panic often leads to errors on known questions. Maintaining composure is crucial.

• Revise GAT Classes: Focus on revising GAT classes, particularly Quant and Reasoning.

• Self-Practice with PPTs: Instead of re-watching videos, download PPTs from Quant and Reasoning classes and practice questions using pen and paper. This is essential for solving questions efficiently within time limits.

• Current Affairs: Review provided Current Affairs materials (e.g., October to March).

• GK vs. Quant/Reasoning: While GK can be unpredictable, Quant and Reasoning sections are more predictable. Strong command over their concepts and logic ensures better scores.

Also Check: CUET 2026 Paper Easy or Tough

II. Problem Solving: Quantitative Aptitude & Reasoning

1. Blood Relations: Brother and Son

Problem: Rajesh is the brother of Ankit. Ankit is the son of Sushma. Sushma is the sister of Shubham. How is Rajesh related to Sushma?

Solution Process:

1. Rajesh is the brother of Ankit.

2. Ankit is the son of Sushma. Since Rajesh and Ankit are brothers, Rajesh is also Sushma's son.

3. Sushma is the sister of Shubham. This information provides additional context but does not alter Rajesh's relationship with Sushma.
   Answer: Rajesh is the son of Sushma.

2. Number System: Division Properties

Problem: On dividing a number (dividend) by a certain number (divisor), the quotient is 89 and the remainder is 37. The dividend is 5368. Find the sum of the digits of the divisor.

Conceptual Explanation & Revision:

• Divisor: The number by which another number is divided.

• Dividend: The number being divided.

• Quotient: The result of a division.

• Remainder: The amount left over after a division.
  The fundamental relationship is: Dividend = (Divisor × Quotient) + Remainder. (Memory Tip: Think 'DR. Q. R.' for Dividend, Divisor, Quotient, Remainder, where the Dividend is the largest, like a Doctor.)

To find the divisor: Divisor = (Dividend - Remainder) / Quotient.

Solution Process:

1. Given: Dividend = 5368, Quotient = 89, Remainder = 37.

2. Calculate the Divisor:

• Divisor = (5368 - 37) / 89 = 5331 / 89 = 179

3. Calculate the Sum of Digits of the Divisor:

• Sum of digits = 1 + 7 + 9 = 17

3. Clocks: Right Angle between Hands

Problem: How many times do the hands of a clock form a right angle in a day?

Key Concept: The hands of a clock form a 90-degree angle (right angle) twice every hour, except between 2-4 and 8-10, where it happens only three times (instead of four for two hours). (Memory Tip: In 12 hours, a right angle forms 22 times. Since a day has 24 hours, it forms 44 times.)

4. Simplification: Algebraic Identities

Problem: Simplify: (256³ - 144³) / (256² + 256 × 144 + 144²)

Conceptual Explanation: This problem utilizes the algebraic identity for the difference of cubes:

a³ - b³ = (a - b)(a² + ab + b²)

Solution Process:

1. Identify a and b: Let a = 256, b = 144.

2. Substitute into the expression: (a³ - b³) / (a² + ab + b²)

3. Apply the identity: [(a - b)(a² + ab + b²)] / (a² + ab + b²)

4. Cancel common terms: This simplifies to (a - b).

5. Calculate the final value: a - b = 256 - 144 = 112.

5. Simple Interest Calculation

Problem: Calculate the simple interest on a principal of ₹4800 at 10.5% per annum for 2 years and 3 months.

Formula for Simple Interest: Simple Interest (SI) = (Principal × Rate × Time) / 100

Solution Process:

1. Given: Principal (P) = ₹4800, Rate (R) = 10.5% p.a. = 21/2 % p.a., Time (T) = 2 years 3 months.

2. Convert Time to Years: 3 months = 3/12 years = 1/4 years. Total Time = 2 + 1/4 years = 9/4 years.

3. Calculate Simple Interest:

• SI = (4800 × (21/2) × (9/4)) / 100

• SI = (4800 × 21 × 9) / (2 × 4 × 100) = (48 × 21 × 9) / 8 = 6 × 21 × 9 = 126 × 9 = ₹1134.

6. Reasoning: Alphabet Series (Coding-Decoding)

Problem: If ROAST is coded as PQYUR, how is SLOPPY coded?

Conceptual Explanation: This involves a specific pattern of letter shifts based on alphabetical position. (Memory Tip: Recall numerical positions of letters (A=1, B=2, etc.). Use aids like 'ISOTY' (E=5, J=10, O=15, T=20, Y=25) for quick reference.)

Decoding ROAST to PQYUR:

• R (18) → P (16) : -2

• O (15) → Q (17) : +2

• A (1) → Y (25) : -2 (1-2 = -1, which is 25 in a 26-letter cycle)

• S (19) → U (21) : +2

• T (20) → R (18) : -2
  Pattern Identified: -2, +2, -2, +2, -2

Encoding SLOPPY:

• S (19) → S-2 = Q (17)

• L (12) → L+2 = N (14)

• O (15) → O-2 = M (13)

• P (16) → P+2 = R (18)

• P (16) → P-2 = N (14)

• Y (25) → Y+2 = A (1) (25+2 = 27, which is 1 in a 26-letter cycle)
  Answer: QNMRNA

7. Reasoning: Pattern Recognition (Non-Verbal)

Problem: Identify the next pattern in a sequence of figures involving the movement of symbols (+, -, ×, ÷).

Conceptual Explanation: These questions require observing the individual movement of each symbol across frames. Look for consistent patterns like clockwise rotation, anti-clockwise movement, or specific jumps. For example, if a '+' symbol moves from top-left to bottom-left, then to bottom-right, the next position would likely be top-right, following a clockwise path.

8. Geometry: Area of a Right-Angled Triangle

Problem: The area of a right-angled triangle is numerically 30 times its height. Find the breadth (base) of the triangle.

Formula for Area of a Right-Angled Triangle: Area = (1/2) × Base × Height

Solution Process:

1. Define Variables: Let Height = h, Base = b.

2. Given Relationship: Area = 30 × Height = 30h.

3. Substitute into Area Formula: 30h = (1/2) × b × h.

4. Solve for Base (b): Cancel 'h' from both sides (since h ≠ 0).

• 30 = (1/2) × b

• b = 30 × 2 = 60 units.

9. Time and Work: Men and Women Efficiency

Problem: 8 men can complete a work in 10 days. 12 women can complete the same work in 10 days. How many days will it take for 4 men and 4 women to complete the work?

Key Concept: Total Work = Number of Workers × Efficiency × Time

Solution Process:

1. Equate Work Done: 8 Men × 10 Days = 12 Women × 10 Days.

2. Find Relationship between Men's and Women's Efficiency: 8 Men = 12 Women => 1 Man = (12/8) Women = (3/2) Women.

3. Calculate Equivalent Women for 4 Men: 4 Men = 4 × (3/2) Women = 6 Women.

4. Find Total Equivalent Women: 6 Women (from men) + 4 Women = 10 Women.

5. Use Total Work (from Women's group) to find Days: Total Work = 12 Women × 10 Days = 120 (Woman-Days).

• Days for 10 Women = 120 / 10 = 12 Days.

10. Time and Work: Individual vs. Combined Work

Problem: A and B working together can do a work in 10 days. If A alone can do the work in 15 days, how many days will B alone take to complete the same work?

Key Concept: Use the LCM (Least Common Multiple) method to find total work and individual efficiencies.

Solution Process:

1. Total Time Taken: (A + B) take 10 days; A takes 15 days.

2. Calculate Total Work (LCM): LCM of 10 and 15 = 30 units.

3. Calculate Individual Efficiencies:

• Efficiency of (A + B) = 30 / 10 = 3 units/day.

• Efficiency of A = 30 / 15 = 2 units/day.

4. Calculate B's Efficiency: Efficiency of B = (A + B)'s Efficiency - A's Efficiency = 3 - 2 = 1 unit/day.

5. Calculate Time for B Alone: Time for B = Total Work / B's Efficiency = 30 / 1 = 30 days.

11. Mensuration: Area of Four Walls of a Hall

Problem: The area of the four walls of a rectangular hall with length 18m and height 8m is 448 sq m. Find the breadth of the hall.

Formula for Area of Four Walls (Lateral Surface Area): Area = 2 × Height × (Length + Breadth)

Solution Process:

1. Given: Area of four walls = 448 sq m, Length (L) = 18 m, Height (H) = 8 m.

2. Substitute into the formula: 448 = 2 × 8 × (18 + Breadth) => 448 = 16 × (18 + Breadth).

3. Solve for Breadth (B):

• 448 / 16 = 18 + Breadth

• 28 = 18 + Breadth

• Breadth = 28 - 18 = 10 meters.

12. Exponents and Roots

Problem: Simplify: (Fourth root of 625)³

Conceptual Explanation:

• The nth root of x can be written as x^(1/n).

• Power of a power: (a^m)^n = a^(m*n).

Solution Process:

1. Express 625 as a power: 625 = 5 × 5 × 5 × 5 = 5⁴.

2. Rewrite the expression: (Fourth root of 5⁴)³ = ((5⁴)^(1/4))³.

3. Simplify the root: (5^(4 × 1/4))³ = (5¹ )³ = 5³.

4. Calculate the final value: 5³ = 5 × 5 × 5 = 125.

13. Reasoning: Number Series (Analogy)

Problem: If 15 is to 256, then 18 is to what?

Pattern Identification:

• Observe 15 and 256. 256 is 16².

• This indicates the pattern: (Number + 1)².

• For 15: (15 + 1)² = 16² = 256.
  Apply Pattern to 18:

• For 18: (18 + 1)² = 19² = 361.

14. Reasoning: Number Series (Squares of Odd Numbers)

Problem: Find the missing number in the series: 1, 9, 25, 49, 81, ?

Pattern Identification:

• 1 = 1²

• 9 = 3²

• 25 = 5²

• 49 = 7²

• 81 = 9²
  The series consists of the squares of consecutive odd numbers.

Next Number: The next odd number after 9 is 11. 11² = 121.

15. Reasoning: Ranking and Order

Problem: Suresh is five ranks below the top student, Samir, in a class of 40 students. What is Suresh's rank from the bottom?

Solution Process:

1. Determine Suresh's Rank from the Top: Samir is 1st. Suresh is 5 ranks below, so Suresh's rank from the top = 1 + 5 = 6th.

2. Formula for Rank from Bottom: Rank from Bottom = Total Students - Rank from Top + 1. (Memory Tip: The '+1' accounts for the person's own position after subtracting those above them.)

3. Calculate Suresh's Rank from the Bottom: Rank from Bottom = 40 - 6 + 1 = 34 + 1 = 35th.

16. Algebra: Sum of Cubes Identity

Problem: Given a + b + c = 6 and ab + bc + ca = 10, find the value of a³ + b³ + c³ - 3abc.

Key Algebraic Identity:

a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c² - ab - bc - ca)

This can also be expressed as:

a³ + b³ + c³ - 3abc = (a + b + c)[(a + b + c)² - 3(ab + bc + ca)]

Solution Process:

1. Given: (a + b + c) = 6, (ab + bc + ca) = 10.

2. Apply the identity (second form): a³ + b³ + c³ - 3abc = (a + b + c)[(a + b + c)² - 3(ab + bc + ca)]

3. Substitute values:

• = 6 × [(6)² - 3 × (10)]

• = 6 × [36 - 30]

• = 6 × 6 = 36.

17. Water Image Recognition

When identifying a water image, the top and bottom parts of an object are inverted, while the left and right sides remain unchanged. This means mentally flipping the object vertically.

18. Indian States Sharing Border with China

The following Indian states share a border with China:

• Arunachal Pradesh

• Sikkim

• Uttarakhand
  A state like Nagaland does NOT share a border with China.

19. Number/Alphabet Series Reasoning

Series: A, D, G, J, M, P, S, …

Pattern Identification:

1. Assign numerical positions: A=1, D=4, G=7, J=10, M=13, P=16, S=19.

2. The pattern is to add 3 to the previous number (1+3=4, 4+3=7, etc.).
   Next Term: 19 + 3 = 22. The 22nd letter of the alphabet is V.

20. Arranging Fractions in Decreasing Order

Objective: Arrange fractions (e.g., 4/5, 7/8, 3/7, 5/9) in decreasing order.

Method: Percentage/Decimal Conversion (Recommended)

This is the most efficient approach.

1. Convert fractions to decimals (using known percentage equivalents):

• 4/5 = 0.80 (since 1/5 = 0.20)

• 7/8 = 0.875 (since 1/8 = 0.125)

• 3/7 ≈ 0.4284 (since 1/7 ≈ 0.1428)

• 5/9 ≈ 0.5555 (since 1/9 ≈ 0.1111)

2. Compare decimals: 0.875, 0.80, 0.4284, 0.5555.

3. Arrange in decreasing order: 7/8 > 4/5 > 5/9 > 3/7.
   (Memory Tip: Memorizing common Percentage-Fraction Equivalences (e.g., 1/2=50%, 1/4=25%, 1/7=14.28%) significantly speeds up this process.)

21. Chronological Order of Historical Landmarks

To arrange historical events from earliest to most recent:

1. First Battle of Panipat (1526 AD) – Bahadur Shah defeated Ibrahim Lodi, marking the beginning of the Mughal Empire.

2. Sher Shah defeated Humayun (circa 1539 AD) – Sher Shah usurped the Delhi throne.

3. Nadir Shah's invasion (circa 1739 AD).

4. Ahmed Shah Abdali defeated Marathas (1761 AD).

22. Number Pattern/Series Completion

A repeating sequence of additions: +1, +1, +1, +3. For instance, applying this pattern to a starting number results in 16 after one cycle.

23. Seating Arrangement (Reasoning)

Problem Setup: Five persons seated in a row, all facing South. When facing South, Left and Right directions are inverted compared to facing North.

Clues:

1. C is fourth to the Left of M.

2. B is exactly in the middle of the row (3rd position for 5 people).

3. V does not sit adjacent to C.
   Based on such clues, one can deduce positions and relationships. For example, 'V is second to the Right of N' or 'V is immediate Left of M' could be correct descriptions of V's position in a hypothetical arrangement.

24. Origin of Kuchipudi Classical Dance

Kuchipudi is a classical dance form that originated from Andhra Pradesh, India.

25. Order & Ranking (People in a Row)

Problem Setup: Total 40 people in a row.

Given Positions: P is 13th from Left, Q is 10th from Right, M is 4th to the Right of P.

Derivations:

• P's rank from Left: 13th.

• Q's rank from Left: Total people - Rank from Right + 1 = 40 - 10 + 1 = 31st from Left.

• M's rank from Left: M is 4th to the Right of P. Since P is 13th from Left, M's position = 13 + 4 = 17th from Left.

Question: How many people are between Q and M?

• Q's rank from Left = 31.

• M's rank from Left = 17.
  Calculation Method: Number of people between M and Q = |Q's Rank - M's Rank| - 1 = |31 - 17| - 1 = 14 - 1 = 13 people. (Memory Tip: Use |Rank_A - Rank_B| - 1 to find people between two individuals, ensuring neither person is counted.)

26. Time & Work Problem 1 (Sequential Work)

Problem: A works in 10 days, B in 15 days. They work together for 5 days, then B leaves. A completes the remaining work. Find total days.

Solution Method: LCM Method

1. Total Work (LCM of 10, 15): 30 units.

2. Individual Efficiencies: A = 30/10 = 3 units/day, B = 30/15 = 2 units/day.

3. Combined Efficiency (A+B): 3 + 2 = 5 units/day.

4. Work Done Together (5 days): 5 units/day * 5 days = 25 units.

5. Remaining Work: 30 - 25 = 5 units.

6. Time for A (remaining work): 5 units / 3 units/day = 5/3 days.

7. Total Days: 5 (together) + 5/3 (A alone) = 20/3 = 6 2/3 days.

27. Time & Work Problem 2 (Person Leaves Before Completion)

Problem: A works in 10 days, B in 20 days. They work together, but A leaves 2 days before work completion. Find total days.

Solution Method: LCM Method with "Stop the Leaver" Rule

1. Total Work (LCM of 10, 20): 20 units.

2. Individual Efficiencies: A = 20/10 = 2 units/day, B = 20/20 = 1 unit/day.

3. (Memory Tip: If a person leaves 'X' days *before completion, calculate the work they would have done in 'X' days and add it to the total work. Then, divide this adjusted total work by the combined efficiency, as if everyone worked till the end.*)

4. Work A would have done (2 days): 2 units/day * 2 days = 4 units.

5. Adjusted Total Work: 20 + 4 = 24 units.

6. Combined Efficiency (A+B): 2 + 1 = 3 units/day.

7. Total Days (Adjusted): 24 units / 3 units/day = 8 days.

28. Percentage Calculation (Time Units)

Problem: What percentage is 15 seconds of 3 minutes?

Solution Steps:

1. Convert to same unit (seconds): 3 minutes = 3 * 60 = 180 seconds.

2. Set up percentage equation: (x/100) * 180 = 15.

3. Solve for x: x = (15 * 100) / 180 = 1500 / 180 = 150 / 18 = 25 / 3 = 8 1/3 %.

29. Percentage Word Problem (Marks)

Problem: A scored 60 marks, which is 20% more than B's score. Find B's score.

Solution Method: Using Fractional Equivalents

1. Convert percentage to fraction: 20% = 20/100 = 1/5.

2. Interpret "20% more": If B's score is 5 units, A's score is 5 + 1 = 6 units.

3. Relate units to marks: A's score (6 units) = 60 marks.

4. Value of one unit: 1 unit = 60 / 6 = 10 marks.

5. B's score (5 units): 5 * 10 = 50 marks.

30. Geography - Diurnal Temperature Range

In Kerala, there is hardly any difference between day and night temperatures, indicating a low diurnal temperature range. This is characteristic of coastal regions, unlike inland areas which experience larger temperature fluctuations.

31. Indian Classical Dance Exponents

Renowned dancers like Padma Subrahmanyam, Alarammel Valli, Yamini, and Anita are prominent exponents of the classical Indian dance form Bharatanatyam.

32. Indian Constitution - Article 129 (Supreme Court)

Article 129 of the Indian Constitution declares the Supreme Court as a Court of Record. This implies its proceedings and decisions are preserved as judicial precedents and it possesses the inherent power to punish for contempt of itself.

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