Physics Wallah

NCERT Solutions for Class 5 Maths Chapter 11 Area and its Boundary

Here, we have provided NCERT Solutions for Class 5 Maths Chapter 11. Students can view these NCERT Solutions for Class 5 Maths Chapter 11 before exams for better understanding of the chapter.
authorImageAnanya Gupta20 May, 2024
Share

Share

NCERT Solutions for Class 5 Maths Chapter 11

NCERT Solutions for Class 5 Maths Chapter 11: The NCERT Solutions for Class 5 Maths Chapter 11 - "Area and its Boundary" provide students with a clear understanding of how to measure the area and perimeter of various shapes.

These solutions are designed to help students grasp the concept of area as the amount of space inside a shape and the boundary as the length around a shape. Through practical examples and exercises, students learn to calculate the area and perimeter of rectangles, squares, and other polygons. The solutions, prepared by experts, align with the CBSE syllabus, ensuring that students have a thorough understanding of these fundamental concepts in geometry. This foundation is important for their progress in higher mathematics.

NCERT Solutions for Class 5 Maths Chapter 11 PDF

NCERT Solutions for Class 5 Maths Chapter 11 - "Area and its Boundary" PDF is a very helpful resource for students. It provides clear explanations and step-by-step answers to help students learn how to measure the area and perimeter of different shapes. These solutions based on the CBSE syllabus and include practical examples to make learning fun and easy. By using this PDF, students can improve their problem-solving skills and get a better understanding of geometric concepts, which will help them do well in their exams. The solutions are easy to follow, making it a great tool for learning and practicing maths.

NCERT Solutions for Class 5 Maths Chapter 11 PDF

NCERT Solutions for Class 5 Maths Chapter 11 Area and its Boundary

PAGE: 146

Whose Slice is Bigger?

Parth and Gini bought aam pappad (dried mango slice) from a shop. Their pieces looked like these.

NCERT Solutions for Class 5 Maths Chapter 11 - Image 1 Both could not make out whose piece was bigger.

1. Suggest some ways to find out whose piece is bigger. Discuss.

Solution:

The length of piece A is 6 cm. So 6 squares of side 1 cm can be arranged along its length. The width of piece A is 5 cm. So 5 squares can be arranged along its width. NCERT Solutions for Class 5 Maths Chapter 11 - Image 4 Altogether 30 squares can be arranged on it. So, the area of piece A = 6 cm × 5 cm = 30 square cm

NCERT Solutions for Class 5 Maths

2. Altogether how many squares can be arranged on it? ________

Solution:

30

3. So the area of piece A = ________ square cm

So the area of piece A = 30 square cm

4. In the same way find the area of piece B.

Solution:

Now, the area of piece B = 11 cm × 3 cm = 33 square cm

5. Who had the bigger piece? How much bigger?

Solution:

So, the area of piece B is bigger than the area of piece A. Difference in area of piece A and piece B = 33 − 30 = 3 square cm So, piece B is 3 square cm bigger than piece A.

Cover with stamps:

This stamp has an area of 4 square cm. Guess how many such stamps will cover this big rectangle.

NCERT Solutions for Class 5 Maths Chapter 11 - Image 5 Solution: NCERT Solutions for Class 5 Maths Chapter 11 - Image 6 Check your guess:

a) Measure the yellow rectangle. It is ________ cm long.

Solution:

14cm

b) How many stamps can be placed along its length? ________

Solution:

7 stamps

c) How wide is the rectangle? ________ cm

Solution:

8cm

d) How many stamps can be placed along its width? ________

Solution:

4 stamps

e) How many stamps are needed to cover the rectangle? ________

Solution:

28 stamps

f) How close was your earlier guess? Discuss.

Solution:

It was pretty close.

g) What is the area of the rectangle? ________ Square cm

Solution:

Area of rectangle = 7 × 4 = 28 square cm

h) What is the perimeter of the rectangle? ________ cm

Solution:

Length of the rectangle = 14 cm Breadth of the rectangle = 8 cm A rectangle has 2 lengths and 2 breadths. So, perimeter of the rectangle = Sum of all its sides = Length of its boundary = 14 cm + 8 cm + 14 cm + 8 cm = 44 cm The perimeter of rectangle is 44 cm.

Practice time:

a) Arbaz plans to tile his kitchen floor with green square tiles. Each side of the tile is 10 cm. His kitchen is 220 cm in length and 180 cm wide. How many tiles will he need?

NCERT Solutions for Class 5 Maths Chapter 11 - Image 7 Solution: Given length of kitchen = 220 cm Width of the kitchen = 180 cm Each side of tile = 10 cm Area of floor = length × width = 220 × 180 = 39600 square cm Area of a tile = side × side = 10 × 10 = 100 square cm Number of tiles = area of floor/ area of a tile = 39600/100 = 396 tile.

b) The fencing of a square garden is 20 m in length. How long is one side of the garden?

Solution:

Given perimeter of garden = 20 m which has to be fenced. Length of one side = perimeter/4 = 20/5 = 5m.

c) A thin wire 20 centimeters long is formed into a rectangle. If the width of this rectangle is 4 centimeters, what is its length?

NCERT Solutions for Class 5 Maths Chapter 11 - Image 8 Solution:

Given perimeter of a rectangle = 20 cm Width of a rectangle = 4 cm We know that perimeter of rectangle = 2 (length + breadth) 20 = 2 length + 2 breadth 2 length = 20 – 2 breadth 2 length = 20 – 2 × 4 2 length = 20 – 8 Length = 12/2 = 6 cm

d) A square carrom board has a perimeter of 320 cm. How much is its area?

NCERT Solutions for Class 5 Maths Chapter 11 - Image 9 Solution: Given perimeter of carrom board is 320 cm We know that perimeter of square = 4 × side Side = perimeter/4 Side = 320/4 = 80 cm We know that area of square = side × side = 80 × 80 = 6400 square cm

e) How many tiles like the triangle given here will fit in the white design? Area of design = ________ square cm

NCERT Solutions for Class 5 Maths Chapter 11 - Image 10 Solution: 6 triangular tiles will fit in to the given white design. Now, area of 1 such triangular tile = 12 square cm Area of 6 triangular tiles that make this design = 6 × 12 = 3 square cm Area of design = 3 square cm NCERT Solutions for Class 5 Maths Chapter 11 - Image 12 f) Sanya, Aarushi, Manav and Kabir made greeting cards. Complete the table for their cards: NCERT Solutions for Class 5 Maths Chapter 11 - Image 13 Solution: Perimeter of Sanya’s card = Sum of all its sides = 10 + 8 + 10 + 8 = 36 cm Length of Manav’s card = 11 cm Perimeter of his card = 44 cm We have to find the width of Manav’s card. Perimeter of card = Sum of all its sides = 11 + 11 + sum of 2 other sides = 22 + sum of 2 other sides Now, sum of two other sides = 44 − 22 = 22 cm The two other sides of the greeting cards are width. So, width of Manav’s card = 22 ÷ 2 = 11 cm Width of Aarushi’s card = 8 cm Area of the card = 80 square cm Now, we have to find length of the card. Area of card = Length of card × 8 cm = 80 square cm So, on dividing the area of card by its width, we can get its length. Therefore, length of Aarushi’s card = 80 ÷ 8 = 10 cm

NCERT Solutions for Class 5 Maths Chapter 11 - Image 14 My belt is longest:

Take a thick paper sheet of length 14 cm and width 9 cm. You can also use an old postcard.

1. What is its area? What is its perimeter?

Solution:

Length of paper sheet   = 14 cm Breadth of paper sheet = 9 cm Area of the sheet = 14 cm × 9 cm = 126 square cm Perimeter of the sheet   = 14 cm + 9 cm + 14 cm + 9 cm = 46 cm

2. Now cut strips of equal sizes out of it. Using tape join the strips, end to end, to make a belt.

NCERT Solutions for Class 5 Maths Chapter 11 - Image 15 How long is your belt? _____

Solution:

84 cm

3. What is its perimeter _____?

Solution:

90 cm

4. Whose belt is the longest in the class? _____

Solution:

Strips of the least width will make the longest belt in the class.

Discuss:

1. Why did some of your friends get longer belts than others?

Solution:

This is because they made belts from thinner strips than others.

2. Is the area of your belt the same as the area of the postcard? Why or why not?

Solution:

Area of the belt of 3 cm wide strip = length × breadth = 3 × 42 = 126 square cm Yes, the area of my belt is the same as the area of the post card. This is because every area of the post card is used for making the belt.

3. What will you do to get a longer belt next time?

Solution:

I can get a longer belt by making thinner belts next time.

Share the land:

Nasreena is a farmer who wants to divide her land equally among her three children — Chumki, Jhumri and Imran. She wants to divide the land so that each piece of land has one tree. Her land looks like this.

NCERT Solutions for Class 5 Maths Chapter 11 - Image 16 1. Can you divide the land equally? Show how you will divide it. Remember each person has to get a tree. Colour each person’s piece of land differently

Solution:

Total number of boxes = 90 Hence, one person’s share is = 90/3 = 30 boxes. The division can be done as shown in the given figure:

2. If each square on this page is equal to 1 square metre of land, how much land will each of her children get? ________ Square m

Solution:

30 square meter.

3. Chumki, Jhumri and Imran need wire to make a fence.

NCERT Solutions for Class 5 Maths Chapter 11 - Image 18

Who will need the longest wire for fencing? _________

Solution:

Perimeter of Chumki’s land = 9 + 2 + 3 + 2 + 6 + 4 = 26 m Perimeter of Jhumri’s land = 6 + 3 + 2 + 3 + 4 + 6 = 24 m Perimeter of Imraan’s land = 8 + 5 + 3 + 2 + 5 + 3 = 26 m So it is clear that Chumki and Imraan need longest wire of fencing.

4. How much wire in all will the three need? ___________

Solution:

Total length of wire = 26 m + 24 m + 26 m = 76 m. NCERT Solutions for Class 5 Maths Chapter 11 - Image 19 Solution: NCERT Solutions for Class 5 Maths Chapter 11 - Image 21 B. Draw a square of 9 square cm. Write A on it. Draw another square with double the side. Write B on it

Solution:

NCERT Solutions for Class 5 Maths Chapter 11 - Image 22 Answer these —

1. The perimeter of square A is __________ cm.

Solution:

12 cm

2. The side of square B is __________ cm.

Solution:

6 cm

3. The area of square B is __________ square cm.

Solution:

36 cm

4. The area of square B is __________ times the area of square A.

Solution:

4 times

5. The perimeter of square B is __________ cm.

Solution:

24 cm

6. The perimeter of square B is __________ times the perimeter of square A.

Solution:

2 times

Save the Birds:

There are two beautiful lakes near a village. People come for boating and picnics in both the lakes. The village Panchayat is worried that with the noise of the boats the birds will stop coming. The Panchayat wants motor boats in only one lake. The other lake will be saved for the birds to make their nests.

NCERT Solutions for Class 5 Maths Chapter 11 - Image 23 a) How many cm is the length of the boundary of Lake A in the drawing? _____________ (use thread to find out)

Solution:

When we measure the boundary of Lake A with the help of thread, it comes out to be around 30 cm.

b) What is the length of the boundary of Lake B in the drawing?

Solution:

When we measure the boundary of Lake B with the help of thread, it comes out to be around 25 cm.

c) How many kilometers long is the actual boundary of Lake A?

Solution:

Here, the scale is 1 cm = 1 km So, length of the actual boundary of lake A = 30 km

d) How many kilometers long is the actual boundary of Lake B?

Solution:

Here, the scale is 1 cm = 1 km So, length of the actual boundary of lake B = 25 km

e) A longer boundary around the lake will help more birds to lay their eggs. So which lake should be kept for birds? Which lake should be used for boats?

Solution:

The boundary around the lake A is more than the boundary around the lake B. So, Lake A should be kept for birds and Lake B should be used for boats.

f) Find the area of Lake B on the drawing in square cm. What is its actual area in square km?

Solution:

Lake B has 15 fully filled squares and 11 half-filled or more than half – filled squares. Area of 15 fully filled squares = 15 × 15 = 225 square cm We consider the area of every single half – filled or more than half – filled square as 1 square cm Thus, the area of 11 such squares = 11 × 11 = 121 square cm So, total area of lake B = 225 + 121 = 346 square cm We are given 1 cm on drawing = 1 km on ground Therefore, 346 square cm on drawing = 346 km

King’s Story:

The King was very happy with carpenters Cheggu and Anar. They had made a very big and beautiful bed for him. So as gifts the king wanted to give some land to Cheggu, and some gold to Anar. King’s Story Cheggu was happy. He took 100 metres of wire and tried to make different rectangles. He made a 10 m × 40 m rectangle. Its area was 400 square metres. So he next made a 30 m × 20 m rectangle.

NCERT Solutions for Class 5 Maths Chapter 11 - Image 24 1. What is its area? Is it more than the first rectangle?

Solution:

Area of rectangle = 30 × 20 = 600 square m. Yes, it is more than the first rectangle.

2. What other rectangles can he make with 100 metres of wire? Discuss which of these rectangles will have the biggest area.

Solution:

Following rectangles are possible: 5 × 45 = 225 square m 15 × 35 = 525 square m 25 × 25 = 625 square m The square will have the biggest area.

3. Cheggu’s wife asked him to make a circle with the wire. She knew it had an area of 800 square metres. Why did Cheggu not choose a rectangle? Explain.

Solution:

Because none of the rectangles will have area 0f 800 square meter.

4. So Anar also tried many different ways to make a boundary for 800 square metres of land. He made rectangles A, B and C of different sizes. Find out the length of the boundary of each. How much gold wire will he get for these rectangles?

NCERT Solutions for Class 5 Maths Chapter 11 - Image 25 i. Gold wire for A = _________ metres

Solution:

As the area of rectangle A is shown as 40 m × 20 m. So, the length of rectangle = 40 m Width of rectangle = 20 m Gold wire for A = 40 + 20 + 40 + 20 = 120 metres

ii. Gold wire for B = _________ metres

Solution:

As the area of rectangle B is shown as 80 m ×10 m. So, the length of rectangle = 80 m Width of rectangle = 10 m Gold wire for B =   80 + 10 + 80 + 10 = 180 metres

iii. Gold wire for C = ____________ metres

Solution:

As the area of rectangle C is shown as 800 m × 1 m. So, the length of rectangle = 800 m width of rectangle = 1 m Gold wire for C = 800 + 1 + 800 + 1 = 1602 metres

iv. So he will get ____________ metres of gold wire!!

Solution:

As the area of rectangle D is shown as 8000 m × 0.1 m. So, the length of rectangle = 8000 m Width of rectangle = 0.1 m Gold wire for C = 8000 + 0.1 + 8000 + 0.1 = 16000 + 0.2 = 16000.2 metres. So, he will get 16000.2 metres of gold wire.

NCERT Solutions Class 5 Maths

NCERT Solutions for Class 5 Maths Chapter 1
NCERT Solutions for Class 5 Maths Chapter 2
NCERT Solutions for Class 5 Maths Chapter 3
NCERT Solutions for Class 5 Maths Chapter 4
NCERT Solutions for Class 5 Maths Chapter 5
NCERT Solutions for Class 5 Maths Chapter 6
NCERT Solutions for Class 5 Maths Chapter 7
NCERT Solutions for Class 5 Maths Chapter 8
NCERT Solutions for Class 5 Maths Chapter 9
NCERT Solutions for Class 5 Maths Chapter 10
NCERT Solutions for Class 5 Maths Chapter 11
NCERT Solutions for Class 5 Maths Chapter 12
NCERT Solutions for Class 5 Maths Chapter 13
NCERT Solutions for Class 5 Maths Chapter 14

Benefits of NCERT Solutions for Class 5 Maths Chapter 11 Area and its Boundary

  • Clear explanations: The NCERT Solutions provide clear and concise explanations for each concept covered in Chapter 11 - "Area and its Boundary." This clarity helps students understand the topics better.
  • Practice questions: The solutions include a variety of practice questions that cover different aspects of finding the area and perimeter of shapes. This helps students reinforce their learning and build confidence in solving mathematical problems.
  • Coverage of CBSE syllabus: The solutions are designed according to the CBSE syllabus, ensuring that students are well-prepared for their exams and can excel in their studies.
  • Improves problem-solving skills: By solving the practice questions provided in the solutions, students can improve their problem-solving skills and develop a deeper understanding of mathematical concepts related to area and perimeter.
  • Enhances exam preparation: Using the NCERT Solutions, students can effectively prepare for their exams by practicing a wide range of questions and mastering the concepts covered in Chapter 11. This can lead to better performance in exams.

NCERT Solutions for Class 5 Maths Chapter 11 FAQs

How can I calculate the area of different shapes like rectangles, squares, and triangles?

The area of a rectangle is calculated by multiplying its length and width. The area of a square is found by squaring the length of one of its sides. The area of a triangle is calculated by multiplying its base and height and dividing by 2.

What is the perimeter of a shape, and how is it calculated?

The perimeter of a shape is the total length of its boundary. It is calculated by summing the lengths of all its sides.

What are some common units used to measure area and perimeter?

Common units used to measure area include square units such as square meters, square centimeters, and square feet. Perimeter is measured in linear units like meters, centimeters, or feet.

How can I determine the boundary or perimeter of irregular shapes?

For irregular shapes, you can calculate the perimeter by measuring the lengths of their sides and summing them up.

How does understanding area and perimeter relate to other mathematical concepts?

Understanding area and perimeter is foundational in geometry and is often used in more advanced mathematical concepts such as calculus, trigonometry, and geometry.
Popup Close ImagePopup Open Image
Talk to a counsellorHave doubts? Our support team will be happy to assist you!
Popup Image
Join 15 Million students on the app today!
Point IconLive & recorded classes available at ease
Point IconDashboard for progress tracking
Point IconMillions of practice questions at your fingertips
Download ButtonDownload Button
Banner Image
Banner Image
Free Learning Resources
Know about Physics Wallah
Physics Wallah is an Indian edtech platform that provides accessible & comprehensive learning experiences to students from Class 6th to postgraduate level. We also provide extensive NCERT solutions, sample paper, NEET, JEE Mains, BITSAT previous year papers & more such resources to students. Physics Wallah also caters to over 3.5 million registered students and over 78 lakh+ Youtube subscribers with 4.8 rating on its app.
We Stand Out because
We provide students with intensive courses with India’s qualified & experienced faculties & mentors. PW strives to make the learning experience comprehensive and accessible for students of all sections of society. We believe in empowering every single student who couldn't dream of a good career in engineering and medical field earlier.
Our Key Focus Areas
Physics Wallah's main focus is to make the learning experience as economical as possible for all students. With our affordable courses like Lakshya, Udaan and Arjuna and many others, we have been able to provide a platform for lakhs of aspirants. From providing Chemistry, Maths, Physics formula to giving e-books of eminent authors like RD Sharma, RS Aggarwal and Lakhmir Singh, PW focuses on every single student's need for preparation.
What Makes Us Different
Physics Wallah strives to develop a comprehensive pedagogical structure for students, where they get a state-of-the-art learning experience with study material and resources. Apart from catering students preparing for JEE Mains and NEET, PW also provides study material for each state board like Uttar Pradesh, Bihar, and others

Copyright © 2025 Physicswallah Limited All rights reserved.