
Complete Class 12th Physics in 1 Shot for JEE 2026: Preparing for JEE 2026 can be challenging, but it’s possible to cover the entire Class 12 Physics syllabus in one go with the right strategy. By focusing on key concepts, important formulas, and high-weight topics, you can revise efficiently and strengthen your problem-solving skills.
Combining theory with the regular practice of previous years’ questions and mock tests will help you build speed and accuracy. This approach ensures that even if you’re short on time, you can confidently complete the Class 12 Physics syllabus and stay well-prepared for JEE 2026.
This comprehensive review focuses on high-scoring concepts for JEE Mains. The approach directly connects theoretical foundations to problem-solving strategies, enabling the effective application of formulas and concepts. Success hinges on correctly identifying the relevant concept and applying the appropriate formula without overcomplicating problems.
Also Check: JEE Mains 2026 Deleted Syllabus
This topic offers high-scoring potential for minimal effort, often yielding at least one question per paper.
Electromagnetic waves consist of electric (E) and magnetic (B) fields oscillating perpendicularly to each other and to the direction of wave propagation (v).
Key Relationships:
Magnitude: E = vB. In vacuum, E = cB. CAUTION: Always verify wave velocity v from its equation; do not assume c unless specified.
Vector: Directions of E, B, and v are mutually perpendicular, following a right-hand rule.
[Memory Tip] Use the (EBC cyclic diagram). For instance, v̂ = Ê x B̂.
This is the most probable question type, typically involving finding the B-field from an E-field equation (or vice-versa).
Example Equation: E = E₀ sin(ωt - kx + φ)
Key Principles:
Phase: Identical for both electric and magnetic fields.
Direction of Propagation (v̂): Determined by the sign between ωt and kx. ωt - kx means positive x-direction (+î); ωt + kx means negative x-direction (-î).
Wave Speed (v): Critical step. Calculate using v = ω/k. This may not always be c.
Wave speed is tied to the medium's properties:
In vacuum: c = 1 / √(μ₀ε₀)
In a medium: v = 1 / √(με)
Refractive index n = c/v = √(μᵣεᵣ).
Example: Calculating Wave Velocity
Given E = 50 sin(500x - 10x10¹⁰t).
ω = 10 x 10¹⁰, k = 500.
v = ω/k = (10 x 10¹⁰) / 500 = 2 x 10⁸ m/s.
Example: The Velocity Trap Question
Given B_y = 5x10⁻⁶ sin(5x - 4x10⁸t). Find the amplitude of the electric field.
v = ω/k = (4 x 10⁸) / 5 = 0.8 x 10⁸ m/s.
Since v ≠ c, use E₀ = vB₀.
E₀ = (0.8 x 10⁸) * (5 x 10⁻⁶) = 400 V/m.
Energy density is energy per unit volume. Energy is equally shared between electric and magnetic fields.
|
Component |
Instantaneous Energy Density |
Key Principle
|
|---|---|---|
|
Electric Field |
u_E = (1/2)ε₀E² |
Average electric and magnetic energy densities are equal. |
|
Magnetic Field |
u_B = B² / (2μ₀) |
Total average energy density: u_avg = (1/2)ε₀E₀² or B₀² / (2μ₀).
Total Energy (U) within volume V: U = u_avg × V.
Intensity (I) is power transmitted per unit area.
I = Power / Area
Relationship with E-field amplitude: I = u_avg × c = (1/2)ε₀cE₀².
In a charging/discharging capacitor, conduction current (I_C) in wires equals displacement current (I_D) between plates.
I_D = I_C
I = dQ/dt = C (dV/dt).
Displacement current density J_D = I_D / A.
Interference results from superposition of coherent waves, leading to energy redistribution.
|
Concept |
Formula
|
|---|---|
|
Path vs. Phase Difference |
Δφ = (2π/λ) * Δx |
|
Resultant Intensity |
I_res = I₁ + I₂ + 2√(I₁I₂) cos(Δφ) |
|
For Equal Intensities |
I_res = 4I₀cos²(Δφ/2) |
|
Condition |
Constructive (Maxima) |
Destructive (Minima)
|
|---|---|---|
|
Path Difference (Δx) |
nλ |
(2n-1)λ/2 |
|
Phase Difference (Δφ) |
2nπ |
(2n-1)π |
|
Max/Min Intensity |
I_max = (√I₁ + √I₂)² |
I_min = (√I₁ - √I₂)² |
YDSE demonstrates interference. D = screen distance, d = slit separation, λ = wavelength.
|
Parameter |
Formula
|
|---|---|
|
Fringe Width (β) |
β = λD/d |
|
Angular Fringe Width (α) |
α = λ/d (in radians) |
|
nth Bright Fringe (y_max) |
y_max = nβ = n(λD/d) |
|
nth Dark Fringe (y_min) |
y_min = (2n-1)β/2 = (2n-1)(λD/2d) |
If Amplitude (A) ∝ slit width (w), then Intensity (I) ∝ w². This modifies I_max/I_min calculations.
Example: If I_max / I_min = 9/4 and A ∝ w, for slit widths d and xd.
((x+1)/(x-1))² = 9/4 => (x+1)/(x-1) = 3/2 => x = 5.
Each wavelength λ produces its own fringe pattern with β = λD/d.
Central Maxima (CM): Coincides for all colors.
Coincidence of Maxima: n₁λ₁ = n₂λ₂.
Example: Where do bright fringes of λ₁ = 300 nm and λ₂ = 400 nm first coincide?
n₁ * 300 = n₂ * 400 => 3n₁ = 4n₂. Smallest integers: n₁ = 4, n₂ = 3.
So, 4th maximum of 300 nm coincides with 3rd maximum of 400 nm.
If the apparatus is in a medium of refractive index n:
Wavelength changes: λ_medium = λ_air / n.
Fringe width changes: β_medium = β_air / n (decreases).
Central maxima position does not change.
Placing a slab (thickness t, refractive index μ) in front of one slit:
Fringe width (β) does not change.
The entire pattern shifts. Shift distance: y₀ = (μ - 1)t * (D/d). Direction is towards the slab.
Conditions for interference depend on an optical path difference (2μt) and phase shift upon reflection.
[Memory Tip] Reflection from a denser medium causes a (π phase shift). Reflection from a rarer medium causes (no phase shift).
Net 0 or 2π shift: Maxima for 2μt = nλ, Minima for 2μt = (2n - 1)λ/2.
Net π shift: Maxima for 2μt = (2n - 1)λ/2, Minima for 2μt = nλ.
This is a very important topic.
Unpolarized Light through First Polarizer: Transmitted intensity is I₁ = I₀ / 2.
Polarized Light through Analyzer (Malus's Law): I_out = I_in * cos²θ (θ is angle between polarization and analyzer axis).
Example: Three polaroids P1, P2, P3. P2 at 60° to P1, P3 at 90° to P1. I₀ = 256 W/m².
After P1: I₁ = 256 / 2 = 128.
After P2: I₂ = 128 * cos²(60°) = 32.
After P3: Angle between P2 axis (60°) and P3 axis (90°) is 30°. I₃ = 32 * cos²(30°) = 32 * (3/4) = 24 W/m².
At Brewster's Angle (θ_B), reflected light is fully polarized.
Formula: tan(θ_B) = n2 / n1.
Key Property: At θ_B, the reflected ray and refracted ray are perpendicular (90°).
Refractive index n = √(μᵣεᵣ). Assume μᵣ = 1 for dielectrics.
Minima (Dark Fringes): a * sin(θ) = nλ. Linear position y_min = nλD / a.
Secondary Maxima (Bright Fringes): a * sin(θ) = (2n + 1)λ / 2. Linear position y_max ≈ (2n + 1)λD / 2a.
Central Maxima Width: Linear width = 2λD / a. Secondary maxima are half this width.
Image is virtual, erect, same size, same distance behind as object in front.
Combination of Two Plane Mirrors:
Parallel Mirrors: Infinite images.
Inclined Mirrors (angle θ): Number of images N = (360/θ) - 1 if 360/θ is even OR if 360/θ is odd and object is on angle bisector. N = 360/θ if 360/θ is odd and object is asymmetrical. JEE Tip: Assume asymmetrical unless stated otherwise for odd m = 360/θ.
Snell's Law: sin(i) / sin(r) = n2 / n1 = v1 / v2 = λ1 / λ2. Frequency (f) is constant.
TIR Conditions: 1) Denser to rarer medium. 2) i > C.
Critical Angle (C): sin(C) = n_rarer / n_denser. (Smaller n / Larger n).
Light from a source at depth H in denser medium emerges through a circular area of radius R = H tan(C).
Prisms bend light towards their base.
Angle of Deviation (δ): δ = I + E - A.
Prism Angle (A): A = R₁ + R₂.
Minimum Deviation (δ_min): Occurs when I = E and R₁ = R₂ = A/2. Formula: δ_min = 2I - A. Light ray is parallel to the base.
Small Angle Prism: δ = (n - 1)A.
Dispersion: θ = (n_v - n_r)A. Dispersive power ω = (n_v - n_r) / (n_y - 1).
Combination of Prisms: Achromatic (no dispersion) θ_net = 0. Direct Vision (no deviation) δ_net = 0.
When viewed from a rarer medium:
Apparent Depth = Real Depth / n.
For multiple layers: Total Apparent Depth = (t₁/n₁) + (t₂/n₂) + ....
A parallel-sided slab causes zero net deviation but a lateral shift d = t * sin(I - R) / cos(R).
Mirror Formula: 1/v + 1/u = 1/f.
Focal Length: f = R/2. Concave f is negative, Convex f is positive.
Magnification: m = -v/u = hᵢ / h₀.
Longitudinal Velocity of Image: Vᵢ = - (v²/u²) * V₀.
nᵣ/v - nᵢ/u = (nᵣ - nᵢ)/R.
nᵢ: refractive index of incident medium.
nᵣ: refractive index of refracted medium.
Sign Convention: Incident light direction is negative.
In Air: 1/f = (n - 1) (1/R₁ + 1/R₂)
[Memory Tip] (For this specific formula, use: convex surface R is positive, concave R is negative.)
In Medium: 1/f_medium = ((n_lens/n_surrounding) - 1) (1/R₁ + 1/R₂)
Ratio: f_air / f_medium = ((n_lens/n_surrounding) - 1) / (n_lens - 1).
Cutting Lenses:
Along principal axis (horizontal): P and f unchanged.
Perpendicular to principal axis (vertical): P becomes P/2, f becomes 2f.
Combination of Lenses: P_eq = P₁ + P₂, 1/f_eq = 1/f₁ + 1/f₂.
Silvering of a Lens: The system acts as an equivalent mirror. 1/F_eq = 1/f_m - 2/f_l. (Often f_m = R/2).
Position: 1/v - 1/u = 1/f.
Transverse Magnification: m = v/u.
Velocity of Image (Longitudinal): v_image = (v/u)² * v_object.
|
Defect |
Correction |
Key Formula / Identifier
|
|---|---|---|
|
Myopia |
Concave Lens |
f = -x (where x is far point) |
|
Hypermetropia |
Convex Lens |
f = 25x / (x - 25) (where x is near point) |
|
Astigmatism |
Cylindrical Lens |
Keyword: "distorted" or "non-uniform" appearance |
Image at Infinity: M = D / f.
Image at Near Point: M = 1 + (D / f).
Approximate Magnification: M = (L / F_o) * (D / F_e) (for JEE Mains, L = tube length, D = 25 cm).
Angular Magnification: M = F_o / F_e.
Tube Length: L = F_o + F_e.
Electrostatic Force: F = k * q1 * q2 / r² (Vector).
Potential Energy: U = k * q1 * q2 / r (Scalar - include sign of charges).
Superposition Principle: Net force/potential is vector/scalar sum.
Effect of Dielectric (K): F_medium = F_vacuum / K.
Point Charge: E = kQ / R², V = kQ / R.
Uniformly Charged Arc (center): E = (2kλ / r) * sin(θ/2). V = kQ_total / r.
Uniformly Charged Ring (on axis x): E = kQx / (R² + x²)^(3/2) (max at x = ±R/√2). V = kQ / √(R² + x²).
Uniformly Charged Disk (on axis x): E = σ/(2ε₀) * [1 - x/√(R² + x²)]. V = σ/(2ε₀) * [√(R² + x²) - x].
Infinite Sheet: E = σ / (2ε₀) (uniform).
Between Oppositely Charged Parallel Plates: E = σ/ε₀.
Infinite Long Wire: E = 2kλ / R.
Hollow Sphere (R, Q): E_in = 0, V_in = kQ/R. E_out = kQ/r², V_out = kQ/r.
Solid Sphere (R, Q): E_out = kQ/r², V_out = kQ/r. E_in = kQr / R³, V_in = (kQ / 2R³) * (3R² - r²).
Solid Sphere with Off-Center Cavity: E_cavity = ρa / (3ε₀) (uniform, a = vector from sphere center to cavity center).
dV = -E · dr or E = -∇V.
Dipole Moment (p): p = qd (from -q to +q).
Electric Field: E_axial = 2kp / r³, E_equatorial = kp / r³. E_axial is twice E_equatorial.
In Uniform Field E:
Torque: τ = pE sinθ (τ = p × E).
Potential Energy: U = -pE cosθ (U = -p · E).
Work Done (0° to 180°): W = 2pE.
Time Period of Small Oscillation: T = 2π√(I / pE).
Electric Flux (Φ): Φ = E ⋅ A = EA cos(θ).
Gauss's Law: Φ_net = ∮ E ⋅ dA = Q_enclosed / ε₀.
Applications for Symmetry:
Charge q at center of cube: Φ_total = q / ε₀, Φ_face = q / (6ε₀).
Charge q at face center: Φ = q / (2ε₀).
Charge q at edge center: Φ = q / (4ε₀).
Charge q at corner: Φ = q / (8ε₀).
Current (I): I = n A e v_d.
Current Density (J): J = I / A = n e v_d.
Resistance (R): R = ρL / A.
Ohm's Law: J = σE or E = ρJ, and V = IR.
Resistivity (ρ): ρ = m / (n e² τ).
Mobility (μ): μ = v_d / E.
Resistance of Stretched Wire: R ∝ L² (volume constant).
Temperature Dependence: R = R₀ (1 + αΔT). R₀ is resistance at 0°C.
Also Check: JEE 2026 Error & Measurement One-Shot
|
Geometry |
Current Flow |
Resistance Formula
|
|---|---|---|
|
Hollow Sphere |
Radially outward |
R = (ρ / 4π) * (1/a - 1/b) |
|
Hollow Cylinder |
Radially outward |
R = (ρ / 2πL) * ln(b/a) |
|
Frustum of a Cone |
Axially (along length) |
R = ρL / (πab) |
Series: R_eq = R₁ + R₂ + ....
Parallel: 1/R_eq = 1/R₁ + 1/R₂ + ....
Current Divider (R₁ || R₂): I₁ = [R₂ / (R₁ + R₂)] * I_total.
Polygons: Use Unitary Method. For n-sided polygon, resistance across an edge is R_eq = (n-1)R / n².
Wheatstone Bridge (Balanced): R₁/R₂ = R₄/R₃. No current through middle resistor.
Current Law (KCL - Junction Rule): Sum of currents entering = Sum of currents leaving.
Voltage Law (KVL - Loop Rule): Sum of potential changes in a closed loop = 0.
Calculate R_bulb = (V_rated)² / P_rated. This resistance is constant.
Actual power dissipated P_actual = I²R_bulb or V_actual² / R_bulb.
In series, bulb with higher R (lower rated power) glows brighter.
Ammeter: Shunt (small S) in parallel. S = (I_G * R_G) / (I_A - I_G).
Voltmeter: Large R in series. V = I_G * (R_G + R).
Current Sensitivity (CS): CS = BNA / C.
Voltage Sensitivity (VS): VS = BNA / CR.
Based on balanced Wheatstone bridge. R / X = L / (100 - L).
Capacitance: C = ε₀A / d.
Charge: Q = CV.
Energy Stored: U = ½CV² = Q²/2C = ½QV.
Energy Density: u = ½ ε₀ E².
Rules are inverse of resistors.
Series: 1/C_eq = 1/C₁ + 1/C₂ + ... (charge Q is same).
Parallel: C_eq = C₁ + C₂ + ... (voltage V is same).
Wheatstone Bridge (Capacitors): Balanced if C₁C₃ = C₂C₄. Middle capacitor can be removed.
Capacitance: C_dielectric = K × C_air = K (ε₀A / d).
K=1 for air, K=∞ for metals.
Bound Charge (Q_b): Q_b = Q (1 - 1/K).
Combinations of Dielectrics:
In Series: Treat as capacitors in series.
In Parallel: Treat as capacitors in parallel.
When two capacitors C₁, C₂ (initially V₁, V₂) are connected:
Common Potential (Like Terminals): V_f = (C₁V₁ + C₂V₂) / (C₁ + C₂)
Common Potential (Opposite Terminals): V_f = |C₁V₁ - C₂V₂| / (C₁ + C₂)
Energy (Heat) Loss: ΔH = ½ [ (C₁C₂) / (C₁ + C₂) ] × (V₁ - V₂)² (for like terminals).
Time Constant: τ = RC.
Charging:
q(t) = CV (1 - e⁻ᵗ/τ).
i(t) = (V/R) e⁻ᵗ/τ.
At t=0, capacitor acts as short circuit (i=V/R).
At t=∞, capacitor acts as open circuit (i=0).
Discharging:
q(t) = Q₀ e⁻ᵗ/τ.
i(t) = (Q₀/RC) e⁻ᵗ/τ.
Finite Straight Wire: B = (μ₀I / 4πr) * (sin α + sin β). Field on axis is zero.
Right-Hand Thumb Rule: Thumb = current, Fingers curl = B-field direction.
Infinitely Long Wire: B = μ₀I / 2πr.
Semi-Infinite Wire: B = μ₀I / 4πr.
Center of Coil (N turns): B_center = μ₀NI / 2R.
Axis of Coil (at distance x): B_axis = μ₀NIR² / 2(R² + x²)^(3/2).
Right-Hand Curl Rule: Fingers curl = current, Thumb = B-field direction.
Arc of a Loop (angle θ): B_arc = (μ₀I / 2R) * (θ / 2π).
Hollow Cylinder: B_in = 0. B_out = μ₀I / 2πr.
Solid Cylinder: B_out = μ₀I / 2πr. B_in = μ₀Ir / 2πR².
Field is maximum at the surface (r=R) for a solid cylinder.
Ideal Solenoid: B_in = μ₀nI = μ₀NI / L. B_out = 0.
Toroid: B = μ₀NI / 2πr (inside core). B_out = 0.
Magnetic Medium (μᵣ): B_medium = μᵣ * B_vacuum.
∮ B ⋅ dl = μ₀ * I_enclosed. I_enclosed is current passing through the loop, with sign determined by right-hand rule.
Lorentz Force: F = q(v × B). Magnitude F = |q|vB sin(θ).
F is perpendicular to v and B.
Magnetic force does no work, does not change speed or kinetic energy.
Right-Hand Palm Rule: Fingers = v, Palm = B, Thumb = F. (Opposite for negative charges).
v || B: Straight line path (F=0).
v ⊥ B: Uniform circular motion.
Radius (r): r = mv / qB = p / qB = √(2mKE) / qB = √(2mqV) / qB.
Time Period (T): T = 2πm / qB (independent of v, r).
Angular Frequency (ω): ω = qB / m.
v at Arbitrary Angle: Helical path.
Pitch: (v cosθ) * T = (v cosθ) * (2πm / qB).
Formula: F = I (L_eq × B). L_eq is vector from start to end.
Closed Loop in Uniform Field: Net force is zero.
Same direction currents attract. Opposite direction currents repel.
Force per Unit Length: F/L = (μ₀ * I₁ * I₂) / (2πr).
Magnetic Dipole Moment (M): M = N * I * A.
Torque (τ): τ = M × B. Magnitude τ = MB sin(θ).
Potential Energy (U): U = -M ⋅ B.
Time Period of Small Oscillation: T = 2π√(I / MB).
Bar Magnets: Analogy to electric dipoles applies (k → μ₀/4π, p → M, E → B).
Principle: BINA = Cφ. (Magnetic torque = Restoring torque). φ in radians.
Current Sensitivity (CS): CS = BNA / C.
Voltage Sensitivity (VS): VS = BNA / CR.
Net Field: B_net = μ_r * B_external.
Susceptibility (χ): μ_r = 1 + χ.
Classification:
Diamagnetic: χ < 0, 0 ≤ μ_r < 1 (repelled).
Paramagnetic: χ > 0 (small), μ_r > 1 (slightly attracted).
Ferromagnetic: χ >> 1, μ_r >> 1 (strongly attracted).
Magnetic Flux (Φ): Φ = BA cosθ (single surface). Φ_total = NBA cosθ (N turns). Unit: Weber (Wb).
Faraday's Law: ε = -dΦ/dt. (Lenz's Law gives negative sign).
Motional EMF (straight rod): ε = vBL (if v, B, L are mutually perpendicular).
Right-Hand Rule for Polarity: Fingers = v, Palm = B, Thumb = Positive terminal.
Rotational EMF (rod rotating): ε = ½ BωL² (rod rotates about one end). ε = ½ Bω(L₂² - L₁²) (arbitrary axis).