Mole Concept JEE Questions: The mole concept is one of the most basic yet very important topics in Chemistry. It forms the foundation of physical chemistry and is the key to solving numerical problems in almost every chapter. In the JEE Main and JEE Advanced exams, the mole concept plays a vital role because it helps students connect atomic-level calculations with real, measurable quantities. Whether it is balancing equations, calculating moles, or solving stoichiometry problems, a clear understanding of this topic makes problem-solving much easier.
In JEE Main, one to two direct questions are usually asked every year from the mole concept. In JEE Advanced, questions are often asked in the form of tricky stoichiometry problems where students need to apply concepts carefully. This makes practicing mole concept JEE questions and JEE Advanced stoichiometry problems very important for scoring well. Since many other chemistry chapters depend on it, this chapter becomes a stepping stone for mastering the subject.
The mole concept connects the world of atoms, molecules, and particles with measurable mass and volume. It allows us to calculate the number of entities in a substance, balance chemical reactions, and find limiting reagents. The JEE Main exam pattern often includes numerical value-type questions and multiple-choice questions from this chapter. Most of these problems test accuracy, speed, and a clear understanding of Avogadro’s number, molar mass, empirical formulas, and equivalent concept.
Mole Concept JEE Questions are usually direct and formula-based, while in JEE Advanced, the problems are conceptual and involve multiple steps. Students who practice important mole concept JEE Main previous year questions regularly develop strong calculation skills and become comfortable with applying formulas in different ways. This is why teachers always suggest that the mole concept should be revised again and again during preparation.
Let us look at some practice Mole Concept JEE Questions problems that follow the JEE exam pattern.
Single Correct Type Questions
(A) 2.12 mol kg⁻¹
(B) 2.24 mol kg⁻¹
(C) 2.50 mol kg⁻¹
(D) 3.0 mol kg⁻¹
(A) 6.95%
(B) 3.476%
(C) 4.376%
(D) 1.738%
(A) 33.6 L H₂ (g) is produced regardless of temperature and pressure for every mole Al that reacts
(B) 67.2 L H₂ (g) at STP is produced for every mole Al that reacts
(C) 11.2 L H₂ (g) at STP is produced for every mole HCl (aq) consumed.
(D) 6 L HCl (aq) is consumed for every 3L H₂ (g) produced.
(A) 1.78 M
(B) 2.00 M
(C) 0.97 M
(D) 2.22 M
(A) 12 × 23
(B) 26 × 10²³
(C) 34 × 10²³
(D) 48 × 10²³
(A) 3.60 × 10²²
(B) 7.20 × 10²²
(C) 1.20 × 10²³
(D) 2.40 × 10²³
(A) 20 g glucose (C₆H₁₂O₆)
(B) 9.5 g sucrose (C₁₂H₂₂O₁₁)
(C) 40 g urea (NH₂CONH₂)
(D) 62/3 g ethylene glycol
(A) 10 u
(B) 15 u
(C) 20 u
(D) None of these
(A) 0.01 M
(B) 0.1 M
(C) 1.0 M
(D) 10 M
(A) 22 g
(B) 12.57 g
(C) 1.257 g
(D) None of these
Watch Mole Concept Question Practice Video on YT
PW has created a special Mole Concept JEE Questions PDF with Solutions to help students practice more effectively. This PDF contains solved mole concept JEE Mains questions, tricky JEE Advanced stoichiometry problems, and all important mole concept PYQs arranged in a systematic manner. Each question is explained with detailed steps so that students can understand the concept as well as the method. By using this PDF, students can practice at home and build their confidence before the exam.
Practice Now