Properties of Bulk Matter JEE Mains Questions, Download PDF

Properties of Bulk Matter JEE Mains Questions is an important topic in the JEE Mains syllabus. Elasticity, stress-strain relationship, Hooke’s Law, Young’s modulus, bulk modulus, viscosity, etc, are some of the key concepts covered in this unit. Generally, around 1-2 questions are asked in JEE Mains from this section. Students must understand the concepts of solids and liquids under different conditions to easily tackle questions in JEE Mains. 

Practising Properties of Bulk Matter JEE Mains Questions sharpens understanding of fundamentals related to mechanical properties and fluid dynamics, which are frequently tested. Regular problem-solving improves accuracy, helps identify common pitfalls, and speeds up the application of formulas during exams.

Properties of Bulk Matter JEE Mains Questions PDF Download

Properties of Bulk Matter JEE Mains Questions PDF offers a structured collection of previous years’ problems with solutions. The PDF aids in comprehensive understanding by providing theory along with a variety of questions from basics to advanced levels. 

Solving these JEE Main questions on Properties of Bulk Matter enhances problem-solving skills and improves scoring ability in exams.

Here are some Properties of Bulk Matter JEE Mains Questions 

Question 1. Two steel wires having same length are suspended from a ceiling under the same load. If the ratio of their energy stored per unit volume is, the ratio of their diameters is?

[JEE Main 2020, 9 Jan (Shift 2)]

 Question 2. If and are the values of Young's modulus, bulk and modulus of rigidity of any material  respectively. Choose the correct relation for those parameters.

[JEE Main 2021, 24 Feb (Shift 1)]

Question 3. The length of a metal wire is, when the tension in it is and is when the tension is. The natural length of the wire is:

[JEE Main 2021, 20 Jul (Shift 2)]

  Question 4. Two blocks of masses and are connected by a metal wire going over a smooth pulley. The breaking stress of the metal is. What is the minimum radius of the wire?

[JEE Main 2021, 26 Aug (Shift 2)]

 Question 5 Two wires of same length and radius are joined end to end and loaded. The Youngs modulii of the materials of the two wires are and. If the combination behaves as a single wire then its Youngs modulus is: 

[JEE Main 2021, 25 Jul (Shift 1)]

For more Properties of Bulk Matter JEE questions with solutions, download the PDF from the link below: 

Properties of Bulk Matter JEE Mains Questions PDF Download

Properties of Bulk Matter JEE Mains Important Questions

Here are some important Properties of Bulk Matter JEE questions with solutions, similar to those commonly asked in the exam:

Question 1. A steel wire of length L = 2.00 m and cross-sectional area A = 1.00×10⁻⁶ m² is stretched by a force F = 200 N. Young’s modulus Y = 2.00×10¹¹ Pa. Find the extension ΔL.
Formula (plain): ΔL = (F * L) / (A * Y)
Solution:
A * Y = 1.00×10⁻⁶ * 2.00×10¹¹ = 2.00×10⁵
Numerator = F * L = 200 * 2.00 = 400
ΔL = 400 / 2.00×10⁵ = 400 / 200000 = 0.002 m = 2.0 mm

Question 2. Q: Water (surface tension T = 0.072 N/m, ρ = 1000 kg/m³) rises in a clean vertical capillary of radius r = 0.50 mm. Contact angle θ = 0. Find the capillary rise h. (Take g = 9.8 m/s².)
Formula (plain): h = (2 * T * cosθ) / (ρ * g * r)
Solution:
r = 0.50 mm = 5.0×10⁻⁴ m, cosθ = 1
Numerator = 2 * 0.072 * 1 = 0.144
Denominator = 1000 * 9.8 * 5.0×10⁻⁴ = 9800 * 5.0×10⁻⁴ = 4.90
h = 0.144 / 4.90 = 0.0293878 m ≈ 0.0294 m = 2.94 cm

Question 3. A metal cube of side a = 0.10 m is fully immersed in water (ρ = 1000 kg/m³). Find the buoyant force Fb. (g = 9.8 m/s²)
Formula (plain): Fb = ρ * g * V ; V = a^3
Solution:
V = (0.10)^3 = 0.001 m³
Fb = 1000 * 9.8 * 0.001 = 9.8 N

Question 4. A gas at P1 = 1.20×10⁵ Pa occupies V1 = 2.00×10⁻³ m³. If pressure increases to P2 = 2.50×10⁵ Pa isothermally, find V2.
Formula (plain): P1 * V1 = P2 * V2 => V2 = (P1 * V1) / P2
Solution:
P1 * V1 = 1.20×10⁵ * 2.00×10⁻³ = 240
V2 = 240 / 2.50×10⁵ = 240 / 250000 = 0.00096 m³ = 9.6×10⁻⁴ m³

Question 5. A glass sphere (density ρ_s = 2500 kg/m³) of radius r = 1.00 mm falls through water (ρ_f = 1000 kg/m³, viscosity η = 1.00×10⁻³ Pa·s). Find the terminal velocity vt. (Use g = 9.8 m/s².)
Formula (plain): vt = (2/9) * (r^2 * (ρ_s - ρ_f) * g) / η
Solution:
r = 1.00×10⁻³ m → r^2 = 1.00×10⁻⁶ m²
(ρ_s - ρ_f) = 1500 kg/m³
Numerator inside = r^2 * (ρ_s - ρ_f) * g = 1.00×10⁻⁶ * 1500 * 9.8 = 0.0147
Divide by η = 0.0147 / 1.00×10⁻³ = 14.7
vt = (2/9) * 14.7 = 29.4 / 9 = 3.266666... m/s ≈ 3.27 m/s

Question 6. Find the pressure at depth h = 5.00 m in water (ρ = 1000 kg/m³). Take atmospheric pressure P0 = 1.013×10⁵ Pa and g = 9.8 m/s².
Formula (plain): P = P0 + ρ * g * h
Solution:
ρ * g * h = 1000 * 9.8 * 5.00 = 49000 Pa
P = 1.013×10⁵ + 49000 = 101300 + 49000 = 150300 Pa = 1.503×10⁵ Pa

Important Concepts for Properties of Bulk Matter JEE Mains Questions

Below are the key concepts required to solve Properties of Bulk Matter JEE Mains questions and answers effectively: 

How to Prepare Using Properties of Bulk Matter JEE Mains Questions PDF?

Preparing with a JEE Mains Properties of Bulk Matter questions PDF helps you revise key concepts, practice important problem types, and analyse repeated patterns. Here is how you can use the PDF for effective JEE Mains preparation: 

• Revise key concepts like Hooke’s Law, bulk modulus, surface tension, and viscosity while solving properties of Bulk Matter JEE Mains Questions. 
• Make concise notes on important formulas and concepts highlighted in the PDF for quick revision.
• Combine PDF practice with theory revision to create an effective preparation. 
• Practice mixed conceptual and mathematical problems from the Properties of Bulk Matter JEE Mains Questions PDF.
• Solve Properties of Bulk Matter JEE Mains previous year questions to understand JEE patterns.
• Attempt questions under timed conditions.
• Revisit weak areas and check detailed solutions for improvement.