The Karnataka 2nd PUC Biology Chapter 5 Important Questions 2027 are useful for students preparing the Biology board examination. Chapter 5, Molecular Basis of Inheritance, covers important concepts related to genetic material and the molecular processes involved in inheritance.
Practising 2nd PUC Biology Chapter 5 Important Questions can help students revise important concepts, improve answer-writing skills, and identify topics that require additional attention.
Molecular Basis of Inheritance is Chapter 5 of Karnataka 2nd PUC Biology. Students should study the chapter thoroughly and focus on understanding the concepts before attempting important questions.
Some important areas to revise while preparing this chapter include:
Molecular basis of inheritance
Genetic material and its characteristics
DNA and its organisation
Molecular processes involved in inheritance
Important biological terms and concepts related to the chapter
Diagrams and processes that require step-by-step explanation
Students should refer to their prescribed textbook while preparing answers and ensure that important biological terms are used accurately.
Answer: A nucleosome is the basic structural unit of chromatin in which DNA is wrapped around a core of histone proteins.
Answer: DNA polymerase catalyses the synthesis of a new DNA strand by adding nucleotides to the growing strand.
Answer: A codon is a sequence of three nucleotides on mRNA that specifies an amino acid or a stop signal during protein synthesis.
Answer:
mRNA: Carries genetic information from DNA to the ribosome for protein synthesis.
tRNA: Carries specific amino acids to the ribosome and recognises the corresponding codons on mRNA.
Answer: Semiconservative replication is the process in which each newly formed DNA molecule contains one parental strand and one newly synthesised strand. This mode of replication was demonstrated by Meselson and Stahl.
Answer:
DNA has two polynucleotide strands that are held together by hydrogen bonds between nitrogenous bases.
Adenine (A) pairs with Thymine (T) through two hydrogen bonds.
Guanine (G) pairs with Cytosine (C) through three hydrogen bonds.
Answer:
Initiation: RNA polymerase binds to the promoter region of DNA and initiates RNA synthesis.
Elongation: RNA polymerase uses one DNA strand as a template and adds complementary ribonucleotides.
Termination: The RNA polymerase reaches the termination region, and the newly formed RNA is released.
Answer:
The genetic code is triplet, meaning three nucleotides form one codon.
It is degenerate, as more than one codon can specify the same amino acid.
AUG acts as the initiation codon and also codes for methionine.
Answer:
DNA consists of two polynucleotide chains arranged in a double helix.
The two strands are antiparallel, with one strand running 5′→3′ and the other 3′→5′.
Each nucleotide consists of a deoxyribose sugar, phosphate group and nitrogenous base.
The nitrogenous bases of the two strands show complementary base pairing. Adenine pairs with thymine through two hydrogen bonds, while guanine pairs with cytosine through three hydrogen bonds.
The two strands are held together by hydrogen bonds, while nucleotides within each strand are joined by phosphodiester bonds.
Answer:
DNA replication begins with the unwinding and separation of the two DNA strands.
Each parental strand acts as a template for the synthesis of a new complementary strand.
DNA polymerase adds complementary nucleotides to the newly forming DNA strand.
The nucleotides are joined through phosphodiester bonds to form the sugar-phosphate backbone.
Two daughter DNA molecules are produced, each containing one parental strand and one newly synthesised strand. Hence, DNA replication is called semiconservative replication.
Answer:
Initiation: The ribosome binds to mRNA, and the initiator tRNA recognises the start codon, AUG.
Elongation: tRNAs bring specific amino acids according to the codon sequence on mRNA. Peptide bonds are formed between adjacent amino acids.
The ribosome moves along the mRNA, allowing successive amino acids to be added to the growing polypeptide chain.
Termination: When a stop codon is reached, translation stops and the completed polypeptide is released.
Thus, translation converts the genetic information present in mRNA into a specific sequence of amino acids.
Students should focus on understanding Molecular Basis of Inheritance, revising key terms, practising questions, and improving accuracy through regular revision and self-assessment.
Read the chapter carefully and understand its key concepts.
Prepare concise notes on definitions, processes, and important terms.
Practise PYQs regularly to strengthen understanding.
Revise diagrams, model papers and important biological processes.
Analyse mistakes and improve accuracy after each practice session.
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