Questions based on equilibrium often involve multiple connected concepts like equilibrium constant, pH, ionic equilibrium, and Le Chatelier’s Principle, which require both conceptual clarity and numerical practice. Many NEET questions from this chapter involve reaction direction, concentration changes, solubility calculations, and acid-base equilibria.
Understanding how reactions respond to changes in temperature, pressure, and concentration helps improve problem-solving ability in Physical Chemistry. Regular revision of formulas, graphs, and equilibrium concepts helps improve calculation accuracy and conceptual understanding. Physics Wallah provides preparation resources for Equilibrium, including PYQs, MCQs, formula sheets, and mind maps focused on strengthening concepts and problem-solving in chemical equilibrium.
Equilibrium is not always chemical. Sometimes the substance changes only its form, like water turning into steam. In other reactions, the actual chemicals change into something new and then back again. Knowing whether the change is physical or chemical helps us predict how the system might respond to a change in pressure, temperature, or concentration. This understanding makes solving problems easier and boosts our confidence.
Only the physical state changes while the chemical identity remains the same; for example, liquid water turning to vapour and back as vapour condenses.
Occurs at the melting point.
H₂O(s) ⇌ H₂O(l)
At constant pressure, the melting point is unique.
Occurs at the boiling point.
H₂O(l) ⇌ H₂O(g)
Vapour pressure depends only on temperature.
Sublimation processes.
I₂(s) ⇌ I₂(g)
Dissolution of a solid in a liquid or a gas in a liquid.
CO₂(g) ⇌ CO₂(aq)
Reactants and products continuously change into each other, but their total amounts stay constant once equilibrium is achieved.
It involves the rearrangement of atoms, the breaking of old bonds, and the formation of new bonds.
N₂(g) + 3H₂(g) ⇌ 2NH₃(g)
Some reactions complete fully and cannot go back to reactants. Others can move in both forward and backward directions. Equilibrium happens only in reversible reactions. They respond to changes around them and try to stay balanced. Understanding the difference helps us see why some reactions can be controlled and others cannot, which is very important in practical chemistry.
They move in both directions and reach equilibrium depending on temperature, concentration, and pressure changes.
These reactions occur in a closed vessel so that volatile gases cannot escape.
Reactants are never completely consumed. ΔG eventually becomes zero.
Examples:
PCl₅(g) ⇌ PCl₃(g) + Cl₂(g)
CH₃COOH + C₂H₅OH ⇌ CH₃COOC₂H₅ + H₂O
They proceed in only one direction and do not come back, such as food burning into ash.
Usually occur in open vessels or involve the escape of a gas or the formation of a precipitate.
Examples:
NaOH + HCl → NaCl + H₂O
AgNO₃ + NaCl → AgCl↓ + NaNO₃
At equilibrium, reactions do not stop. The particles keep reacting both ways, but the overall condition remains the same. This continuous motion is useful in real processes like gas exchange in our lungs. Graphs help us see how reactions slow down and finally balance out. Understanding this behaviour makes it easier to answer graph-based and concept-based questions in NEET.
Both forward (rₓ) and backward (rᵦ) reactions continue at the same rate, giving the system a stable appearance.
rₓ = rᵦ
Properties such as concentration, colour, density, pressure, and temperature remain constant with time.
The curve for reactants slopes downward and the curve for products slopes upward. Both lines become horizontal when equilibrium is reached, showing constant concentration.
The forward reaction rate decreases while the backward reaction rate increases until both become equal and form a single horizontal line.
rₓ = rᵦ
Every reaction depends on the number of molecules available for collisions. This idea is explained by the Law of Mass Action. It leads to the equilibrium constant K, which helps us know whether reactants or products are more stable in the final mixture. By using K and Q values, we can easily tell the direction of the reaction and predict what will happen next.
The rate of a chemical reaction is directly proportional to the product of the active masses (molar concentrations) of reacting substances raised to the power of their stoichiometric coefficients.
For a general reaction:
aA + bB ⇌ cC + dD
Kc = ([C]^c [D]^d) / ([A]^a [B]^b)
Kp = (P(C)^c P(D)^d) / (P(A)^a P(B)^b)
Kp = Kc(RT)^Δng
Where:
Δng = (moles of gaseous products) − (moles of gaseous reactants)
If Δng = 0 → Kp = Kc
If Δng > 0 → Kp > Kc
If Δng < 0 → Kp < Kc
Calculated using the same formula as K, but using concentrations at any time instead of equilibrium concentrations.
If K > 10³ → Products are highly favoured.
If K < 10⁻³ → Reactants are highly favoured.
If Q = K → System is at equilibrium.
If Q < K → Reaction moves in the forward direction.
If Q > K → Reaction moves in the backward direction.
K depends only on temperature.
If the reaction is reversed:
K(new) = 1/K
If the equation is multiplied by n:
K(new) = Kⁿ
If a system at equilibrium is disturbed by changing temperature, pressure, or concentration, the reaction shifts to counter the change. This idea is called Le-Chatelier’s Principle. Industries use it to make more products. For example, it helps produce more ammonia for fertilizers. It helps us understand how reactions behave in different conditions.
Increasing reactant concentration shifts equilibrium forward.
Increasing product concentration shifts the equilibrium backward.
Effect of Pressure and Volume
Increasing pressure shifts the equilibrium toward the side containing fewer moles of gas.
Decreasing pressure shifts equilibrium toward the side with more moles of gas.
No effect is observed if Δng = 0.
Increasing temperature shifts equilibrium forward.
K increases.
Increasing temperature shifts equilibrium backward.
K decreases.
No effect on equilibrium.
Equilibrium shifts toward the side with more gaseous moles.
Substances that dissolve in water behave differently depending on how completely they break into ions. The ability to form ions decides whether a substance conducts electricity strongly or weakly. Acids and bases are explained through different theories, which help us understand how they donate protons or accept electrons. This knowledge is useful in pH calculations and ionic equilibrium questions.
Break fully into ions in water.
α ≈ 1 or 100%
Examples:
Strong acids: HCl, HNO₃, H₂SO₄
Strong bases: NaOH, KOH
Most soluble salts are also strong electrolytes.
Ionize partially.
α << 1
They conduct electricity weakly.
For a weak electrolyte:
AB ⇌ A⁺ + B⁻
Ka or Kb = (Cα²)/(1 − α)
For weak electrolytes:
Ka ≈ Cα²
Therefore:
α = √(K/C)
Where:
α = degree of ionization
C = concentration
Acids give H⁺ ions in water.
Bases give OH⁻ ions in water.
Acids are proton donors.
Bases are proton acceptors.
This theory forms conjugate acid–base pairs differing by one H⁺ ion.
Lewis acids are electron pair acceptors.
Lewis bases are electron pair donors.
Examples:
Lewis acids: BF₃, AlCl₃
Lewis bases: NH₃, H₂O
Kw = [H⁺][OH⁻] = 1.0 × 10⁻¹⁴ at 25°C
pH = −log[H⁺]
pOH = −log[OH⁻]
pH + pOH = 14
When we add an ion that is already present in a weak electrolyte, the weak electrolyte ionizes even less. This is called the common ion effect. It helps us prepare buffer solutions that keep pH constant even when small amounts of acid or base are added. Buffers are very important in living bodies because enzymes work properly only at a certain pH.
The suppression of the degree of dissociation of a weak electrolyte by the addition of a strong electrolyte containing a common ion.
It reduces ionization and helps control pH in solutions like blood and laboratory mixtures.
A solution that resists changes in pH upon adding small amounts of acid or base.
Composed of a weak acid and its salt with a strong base.
Example:
CH₃COOH + CH₃COONa
Henderson–Hasselbalch Equation:
pH = pKa + log([Salt]/[Acid])
Composed of a weak base and its salt with a strong acid.
Example:
NH₄OH + NH₄Cl
pOH = pKb + log([Salt]/[Base])
Therefore:
pH = 14 − pOH
Some salts dissolve slightly in water and reach a point where no more can dissolve. This balance between dissolved ions and solid salt is linked to Ksp, which helps us find solubility. When ion concentration increases beyond the allowed limit, the excess forms a solid called a precipitate. This concept helps predict whether mixing two solutions will form a solid or not.
For a salt:
AₓBᵧ ⇌ xAʸ⁺ + yBˣ⁻
Where S is molar solubility:
Ksp = [Aʸ⁺]^x [Bˣ⁻]^y
Ksp = (xS)^x × (yS)^y
Example: AgCl
Ksp = S²
Therefore:
S = √Ksp
Examples: MgCl₂, CaF₂
Ksp = 4S³
Therefore:
S = ∛(Ksp/4)
Calculated using current concentrations instead of equilibrium concentrations.
If Qsp < Ksp → Solution is unsaturated.
If Qsp = Ksp → Solution is saturated.
If Qsp > Ksp → Precipitation occurs.
The molar solubility of a sparingly soluble salt decreases in the presence of a common ion because equilibrium shifts backward according to Le-Chatelier’s Principle.
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