Important Questions for Class 7 Maths Chapter 9: Important questions from CBSE Class 7 Maths Chapter 9 Perimeter and Area are highly beneficial for exam preparation. They help reinforce key concepts such as calculating the perimeter and area of rectangles and squares.
By solving these questions students can strengthen their problem-solving skills and become more confident in applying formulas accurately during exams. These questions also cover a range of difficulty levels, providing a comprehensive understanding of the chapter. Practicing them regularly allows students to become adept at recognizing different types of problems and effectively applying appropriate formulas, ensuring better performance in their exams.Perimeter is the total length around a two-dimensional shape. It measures the distance around the edges of a figure. For rectangles and squares, the perimeter can be calculated using simple formulas:
Area is the amount of space enclosed within a two-dimensional shape. It measures the surface covered by the shape. The formulas for calculating area vary depending on the shape:
Important Questions for Class 7 Maths Chapter 9 PDF
Very Short Answer Questions (1-5)
1. What is the formula for the perimeter of a square?
Answer: P=4s
2. How do you find the area of a rectangle?
Answer: A=l×b
3. What is the formula to find the area of a parallelogram?
Answer: A=b×h
4. What is the perimeter of a rectangle with length 10 cm and breadth 6 cm?
Answer: P=2(l+b)=32cm
Short Answer Questions
1. Find the area of a square park whose perimeter is 480 480 m.
Answer: Given, Perimeter(P)= 480 480 m
s=Side of square
P= 4 × s 4×s
480 480 = 4 × s 4×s
s= 480 4 4804
s= 120 120 m
Area of Square=s2
= ( 120 ) 2 (120)2
= 14 , 400 14,400 sq.m
2. If the perimeter of a rectangle is 390 390 cm and the length is 30 30 cm. Find its breadth in the area.
Answer: Given, Perimeter= 390 390 cm , length= 30 30 cm
B= Breadth
A= Area
P= 2 ( l + b ) 2(l+b)
390 = 2 ( 30 + b ) 390=2(30+b)
390 2 = ( 30 + b ) 3902=(30+b)
195 = ( 30 + b ) 195=(30+b)
b = 195 − 30 b=195−30
b = 165 b=165 cm
A= l × b l×b
A= 30 × 165 30×165
A= 4 , 950 4,950 sq.cm
3. A wire bent in the shape of a rectangle. Its length is 30 30 cm and breadth is 15 15 cm and if the same wire is rebent in the shape of a square. What will be the measure of slides and which encloses more area.
Answer: We know, perimeter of rectangle
P= 2 ( l + b ) 2(l+b)
Where, l=length and b = breadth
= 2 ( 30 + 15 ) 2(30+15)
= 2 ( 45 ) 2(45)
= 90 90 cm
Perimeter of Square= Perimeter of rectangle
90 = 4 s 90=4s s = s i d e s=side
s = 90 4 s=904
s = 22.5 s=22.5 cm
Area of rectangle = l × b l×b
= 30 × 15 30×15
= 450 450 sq. cm
Area of Square=s2
= ( 22.5 ) 2 (22.5)2
= 506.25 506.25 sq.cm
Hence, Square encloses a large area.