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NCERT Solutions for Class 10 Maths Chapter 1 Ex 1.3 PDF Download

Get detailed NCERT Solutions for Class 10 Maths Chapter 1 Ex 1.3. Understand key concepts and enhance your learning with clear explanations and step-by-step solutions.
authorImageAnanya Gupta3 Jan, 2025
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NCERT Solutions for Class 10 Maths Chapter 1 Ex 1.3

NCERT Solutions for Class 10 Maths Chapter 1 Ex 1.3: Exercise 1.3 of Chapter 1 Real Numbers in Class 10 Maths focuses on problems related to the division algorithm. This exercise helps students understand how to find the quotient and remainder when one number is divided by another, which is an important concept for working with real numbers.

The solutions provide detailed steps for applying the division algorithm to different pairs of numbers and help in understanding how to express the relationship between two numbers using division, quotient, and remainder. Solving these problems enhances students understanding of number theory and improves their ability to solve complex mathematical problems involving division. The solutions are a useful guide for exam preparation, ensuring a deeper comprehension of the topic.

NCERT Solutions for Class 10 Maths Chapter 1 Ex 1.3 Overview

Exercise 1.3 of Chapter 1 Real Numbers focuses on the Division Algorithm and its applications. This exercise helps students understand how to divide one number by another and express the relationship between them in terms of the quotient and remainder. By solving the problems in this exercise students will develop a deeper understanding of how real numbers interact in division and how the remainder helps in solving various types of problems. The NCERT solutions provide detailed step-by-step explanations, ensuring students grasp the concept thoroughly and apply it effectively in exams.

NCERT Solutions for Class 10 Maths Chapter 1 Ex 1.3 PDF

The NCERT Solutions for Class 10 Maths Chapter 1 Exercise 1.3 provide clear and detailed explanations on the Division Algorithm and its applications. These solutions help in understanding how to express the relationship between two numbers in terms of quotient and remainder. To access the PDF of the solutions click on the link below.

NCERT Solutions for Class 10 Maths Chapter 1 Ex 1.3 PDF

NCERT Solutions for Class 10 Maths Chapter 1 Ex 1.3

Here are the NCERT Solutions for Class 10 Maths Chapter 1 Ex 1.3:

1. Prove that √ 5 is irrational.

Solutions: Let us assume that 5 is a rational number.

i.e., 5 = x/y (where, x and y are co-primes) y 5= x Squaring both sides, we get (y 5) 2 = x 2 ⇒5y 2 = x 2 ……………………………….. (1) Thus, x 2 is divisible by 5, so x is also divisible by 5. Let us say, x = 5k, for some value of k, and substituting the value of x in equation (1), we get 5y 2 = (5k) 2 ⇒y 2 = 5k 2 is divisible by 5, it means y is divisible by 5. Clearly, x and y are not co-primes. Thus, our assumption about 5 is rational is incorrect. Hence, 5 is an irrational number.

2. Prove that 3 + 2√5 + is irrational.

Solutions: Let us assume 3 + 2 5 is rational.

Then, we can find co-prime x and y (y ≠ 0) such that 3 + 2√5 = x/y Rearranging, we get ncert solutions class 10 chapter 1-1 x and y are integers, thus ncert solutions class 10 chapter 1-2 is a rational number. Therefore, 5 is also a rational number. But this contradicts the fact that 5 is irrational. So, we conclude that 3 + 2 5 is irrational.

3. Prove that the following are irrational.

(i) 1/√2

(ii) 7√5

(iii) 6 + 2

Solutions:

(i) 1/ 2

Let us assume 1/√2 is rational. Then, we can find co-prime x and y (y ≠ 0) such that 1/√2 = x/y Rearranging, we get √2 = y/x x and y are integers; thus, √2 is a rational number, which contradicts the fact that √2 is irrational. Hence, we can conclude that 1/√2 is irrational.

(ii) 7 5

Let us assume 7√5 is a rational number. Then, we can find co-prime a and b (b ≠ 0) such that 7√5 = x/y Rearranging, we get √5 = x/7y x and y are integers; thus, √5 is a rational number, which contradicts the fact that √5 is irrational. Hence, we can conclude that 7√5 is irrational.

(iii) 6 + 2

Let us assume 6 +√2 is a rational number. Then, we can find co-primes x and y (y ≠ 0) such that 6 +√2 = x/y Rearranging, we get √2 = (x/y) – x and y are integers; thus, (x/y) – 6 is a rational number and therefore, √2 is rational. This contradicts the fact that √2 is an irrational number. Hence, we can conclude that 6 +√2 is irrational.

CBSE Class 10 Sample Paper

Benefits of Solving NCERT Solutions for Class 10 Maths Chapter 1 Ex 1.3

  • Understanding the Division Algorithm : This exercise helps students grasp the Division Algorithm which is a fundamental concept in number theory. By solving the problems, students learn how to express the relationship between two integers in terms of quotient and remainder.
  • Improved Problem-Solving Skills : The problems in Exercise 1.3 require students to apply the Division Algorithm which enhances their ability to solve real-life mathematical problems involving division, quotients, and remainders.
  • Strong Foundation for Future Concepts : The concepts learned in this exercise are crucial for understanding more advanced topics in mathematics, such as factorization, LCM, HCF, and algebraic manipulations.
  • Conceptual Clarity : The solutions provide a clear, step-by-step breakdown of the division process, helping students understand how to approach division problems systematically.
  • Exam Readiness : By solving problems from Exercise 1.3 students prepare themselves for board exams, as these types of problems are often included in Class 10 Maths exams. Regular practice helps improve accuracy and speed.
  • Increased Confidence : Consistent practice using the NCERT solutions boosts students' confidence and strengthens their overall mathematical skills, making them more capable of tackling complex problems.
  • Better Grasp of Real Numbers : Exercise 1.3 focuses on the division of real numbers which is important for mastering the concept of real numbers and understanding their properties more deeply.

NCERT Solutions for Class 10 Maths Chapter 1 Ex 1.3 FAQs

Can a real number be negative?

Yes, real numbers can be both positive and negative. For example, -2, -0.5, and -π are all negative real numbers.

Are integers considered real numbers?

Yes, integers are a subset of real numbers. All integers, such as -3, 0, and 7, are real numbers because they can be represented on the number line.

What is the Fundamental Theorem of Arithmetic?

The Fundamental Theorem of Arithmetic states that every integer greater than 1 is either a prime number or can be uniquely factorized as a product of primes, with the order of factors not affecting the result.

Is zero a real number?

Yes, zero is a real number.

Are fractions real numbers?

Yes, fractions like 1/2, -3/4, and 7/8 are real numbers. Any number that can be expressed as the ratio of two integers is a rational number and, hence, a real number.
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