SSC Simple Interest Questions, Download PDF in Hindi and English

SSC Simple Interest Questions are a part of the quantitative aptitude section in SSC exams. These questions test your understanding of the basic concept of interest on money borrowed or invested. Learning simple interest helps you solve banking, finance, and savings-related problems in exams easily.

To prepare well, you should understand the simple interest formulas for SSC, solve SSC simple interest previous year questions, and practice with SSC simple interest aptitude questions regularly.

SSC Simple Interest Questions

SSC Simple Interest Questions appear in various exams like SSC CGL, SSC CHSL, and SSC MTS. These questions are usually based on the formula of

Practicing simple interest questions for SSC CGL, SSC CHSL simple interest questions, and SSC MTS simple interest questions helps you understand all types of problems — easy, moderate, and tricky.

If you want to improve your speed, focus on learning simple interest tricks for SSC exam and solving simple interest practice sets for the SSC regularly.

SSC Simple Interest Questions PDF

Many aspirants prefer having a compiled SSC simple interest PDF to revise all formulas and practice questions at one place. The PDFs help in offline study and provide a better understanding through solved examples.

You can find the SSC Simple Interest Questions PDF English and SSC Simple Interest Questions PDF Hindi for your convenience. Both versions include detailed solutions and step-by-step explanations.

SSC Simple Interest Questions and Answers

Below, we’ve mentioned the 15 SSC Simple Interest Questions and Answers with step-by-step explanations. These questions range from easy to hard and will help you understand the topic in depth.

Q1. Find the simple interest on ₹5000 at 10% per annum for 2 years.

Options:

A) ₹800

B) ₹900

C) ₹1000

D) ₹1100
Answer: (D) SI = (5000 × 10 × 2) / 100 = ₹1000.
Explanation: Multiply principal, rate, and time; then divide by 100.

Q2. The simple interest on ₹4000 for 3 years at 5% per annum is?

Options:

A) ₹500

B) ₹600 

C) ₹700

D) ₹800
Answer: (B) SI = (4000 × 5 × 3) / 100 = ₹600.
Explanation: Apply the formula directly.

Q3. What will be the interest on ₹2000 for 4 years at 8% per annum?

Options:

A) ₹600

B) ₹640 

C) ₹700

D) ₹720
Answer: (B) SI = (2000 × 8 × 4) / 100 = ₹640.
Explanation: Interest increases with time and rate.

Q4. If the rate is 12% and the time is 3 years, what is the interest on ₹2500?

Options:

A) ₹850

B) ₹875

C) ₹900 

D) ₹950
Answer: (C) SI = (2500 × 12 × 3) / 100 = ₹900.
Explanation: Substituting in the formula gives a direct answer.

Q5. Find the amount when the principal is ₹3000, the rate is 10%, and the time is 2 years.

Options:

A) ₹3400

B) ₹3500

C) ₹3600 

D) ₹3700
Answer: (C) SI = (3000 × 10 × 2) / 100 = ₹600.
Amount = ₹3000 + ₹600 = ₹3600.
Explanation: Add interest to the principal.

Q6. A sum of ₹8000 gives ₹960 as simple interest in 2 years. Find the rate.

Options:

A) 5%

B) 6% 

C) 7%

D) 8%
Answer:(B)  960 = (8000 × R × 2) / 100 → R = 6%.
Explanation: Rearrange the formula to find the rate.

Q7. The simple interest on a sum for 5 years at 6% per annum is ₹1500. Find the principal.

Options:

A) ₹4000

B) ₹4500

C) ₹5000 

D) ₹5500
Answer: (C) 1500 = (P × 6 × 5) / 100 → P = ₹5000.
Explanation: Use the SI formula to find the principal.

Q8. A sum becomes ₹6720 in 4 years at 4% per annum simple interest. Find the principal.

Options:

A) ₹5400

B) ₹5500

C) ₹5600 

D) ₹5700
Answer: (C)
Let P = principal.
SI = A – P = 6720 – P
(P × 4 × 4) / 100 = 6720 – P → P = ₹5600.
Explanation: Subtract SI from the amount.

Q9. Find the time when ₹3000 becomes ₹3450 at 5% per annum simple interest.

Options:

A) 2 years

B) 2.5 years

C) 3 years 

D) 3.5 years
Answer: (C) SI = 3450 – 3000 = ₹450
450 = (3000 × 5 × T) / 100 → T = 3 years.
Explanation: Use the SI formula to find time.

Q10. The difference between simple interest on ₹6000 for 3 years and 4 years at 5% per annum is?

Options:

A) ₹200

B) ₹250

C) ₹300 

D) ₹350
Answer: (C) SI₁ = (6000 × 5 × 3)/100 = ₹900
SI₂ = (6000 × 5 × 4)/100 = ₹1200
Difference = ₹300.
Explanation: Interest changes directly with time.

Q11. A man lent ₹15000 at simple interest. After 3 years, he got ₹5400 as interest. Find the rate of interest.

Options:

A) 10%

B) 11%

C) 12% 

D) 13%
Answer: (C) 5400 = (15000 × R × 3) / 100 → R = 12%.
Explanation: Rearrange and calculate.

Q12. Find the simple interest on ₹12000 for 9 months at 8% per annum.

Options:

A) ₹600

B) ₹700

C) ₹720 

D) ₹800
Answer: (C) Time = 9/12 = 0.75 years
SI = (12000 × 8 × 0.75) / 100 = ₹720.
Explanation: Convert months into years.

Q13. A sum of ₹2500 amounts to ₹2875 in 3 years. Find the rate of interest.

Options:

A) 4%

B) 5% 

C) 6%

D) 7%
Answer: (B) SI = 2875 – 2500 = ₹375
375 = (2500 × R × 3) / 100 → R = 5%.
Explanation: Subtract principal to get SI.

Q14. At what rate per annum will ₹4000 amount to ₹5200 in 6 years?

Options:

A) 4%

B) 5% 

C) 6%

D) 7%
Answer: (B) SI = 5200 – 4000 = ₹1200
1200 = (4000 × R × 6)/100 → R = 5%.
Explanation: Find rate by rearranging formula.

Q15. A person lent ₹10000 for 5 years. He received ₹4000 as interest. Find the rate per annum.

Options:

A) 7%

B) 8% 

C) 9%

D) 10%
Answer: (B) 4000 = (10000 × R × 5) / 100 → R = 8%.
Explanation: Substitute values and calculate rate.

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