Graphical Solution Of a Linear Equation
Linear equations in two variable of Class 9
(A) in order to draw the graph of a linear equation in one variable we may follow the following algorithm.
Step I :Obtain the linear equation.
Step II: If the equation is of the form ax = b, a ≠ o, then plot the point and one more point
when α is any real number. If the equation is of the form ay = b, a ≠ 0, then plot the point
and
where β is any real number.
Step III: Joint the points plotted in step II to obtain the required line.
|
If eq. is in form ax = b then we get a line parallel to Y-axis and if eg. is in form ay = b then we get a line parallel to X-axis. |
question . Draw the graph of
(i) 2x + 5 = 0 (ii) 3y - 15 = 0
Solution: (i) Graph of 2x + 5 = 0
On simplifying it we get 2x = –5 ⇒ x = – 5/2
First we plot point A1 & then we plot any other point A2
on the graph paper, then we join these two points we get required line
as shown in figure below.
(ii) Graph of 3y - 15 = 0
On simplifying it we get 3u = 15 ⇒ y = 15/3 f = 5.
First we plot the point B1 (0, 5) & then we plot any other point B2 (3, 5) on the graph paper, then we join these two points we get required line m as shown in figure.
NOTE:
(A) A point which lies on the line is a solution of that equation. A point not lying on the line is not a solution of the equation.
(B) In order to draw the graph of a linear equation ax + by + c = 0 may follow the following algorithm.
Step I : Obtain the linear equation ax + by + c = 0.
Step II : Express y in terms of x i.e. y = or x in terms of y i.e.
.
Step III : Put any two or three values for x or y and calculate the corresponding values of y or x respectively from the expression obtained in Step II. Let we get points as .
Step IV : Plot the points on graph paper.
Step V : Joint the pints marked in step IV to obtain. The line obtained is the graph of the equation ax +by + c = 0.
5. Draw the graph of the line x – 2y = 3, from the graph find the coordinate of the point when
(i) x = – 5 (ii) y = 0
Solution: Here given equation is x - 2y = 3.
Solving it for y we get 2y = x - 3 ⇒ y =
Let x = 0, then
x = 3, then y = = 0,
x = - 2, then y = Hence we get
x |
0 |
3 |
-2 |
y |
- 3/2 |
0 |
- 5/2 |
Clearly when x = - 5 then y = - 4 and when y = 0 then x = 3.
question . Draw the graphs of the lines represented by the equations x + y = 4 and 2x - y = 2 in the same graph. Also find the coordinate of the point where the two lines intersect.
Solution: Given equations are
x + y = 4 ......(i) & 2x - y = 2 ......(ii)
(i) We have y = 4 - x
x |
0 |
2 |
4 |
y |
4 |
2 |
0 |
(ii) We have y = 2x – 2
x |
1 |
0 |
3 |
y |
0 |
–2 |
4 |
By drawing the lines on a graph paper, clearly we can say that P is the point of intersection where coordinates are x = 2, y = 2.