NATA 2026 Maths Most Repeated Questions

Mathematics plays an important role in the NATA examination, testing a candidate’s logical thinking, numerical ability, and problem-solving skills. With Phase 1 approaching on June 13, 2026, aspirants should focus on strengthening their mathematical concepts and improving speed and accuracy. 

Many questions are repeatedly asked from specific Quantitative Aptitude topics, making it important for students to focus on high-weightage areas. This collection of the most repeated NATA 2026 Mathematics questions covers topics such as Percentages, Age Problems, and Time & Work. Practising these questions will help students strengthen their fundamentals, improve calculation speed, and build confidence for the NATA 2026 Mathematics section.

NATA 2026 Maths Most Repeated Question Detailed Video

Strengthen your NATA 2026 preparation with the detailed video below covering the most repeated Mathematics questions asked in previous exams. From Percentages to Time and Work, Age Problems, and other important quantitative aptitude topics, the video explains key concepts with easy-to-understand solutions and exam-focused approaches.

For additional practice and a better understanding of frequently asked question patterns, watch the complete video and revise the most important NATA Mathematics topics in a comprehensive manner. 

Most Repeated Topic-Wise Maths Questions for NATA Examination

For the Numerical Aptitude Test (NAT) section of NATA, students should concentrate on several highly recurrent topics. These include Percentage, Problem on Age, and Time and Work.

Topic 1: Percentage Problem

Question: Robert loves fruits. With his monthly allowance, he can buy either 50 apples or 40 bananas. One month, he decided to save 10%. From the remaining allowance, he bought 20 bananas. How many apples can he buy with the rest of the allowance?

Solution:

1. Initial Allowance Equivalence: Robert's total allowance (100%) can buy either 50 apples or 40 bananas.

2. Saving Calculation: He saves 10%, meaning he spends 90% of his allowance.

3. Cost of Bananas Bought:

• If 40 bananas cost 100% of the allowance, then 20 bananas (half the quantity) cost 50% of the allowance.

4. Remaining Allowance: From the 90% he decided to spend, 50% was used for bananas.

• Remaining allowance = 90% - 50% = 40%.

5. Apples from Remaining Allowance:

• Since 100% of the allowance can buy 50 apples, to find how many apples 40% of the allowance can buy, we calculate:
  (40% / 100%) * 50 apples = 20 apples.

Answer: Robert can buy 20 apples with the remaining allowance.

Topic 2: Problem on Age (Father & Daughter)

Question: Father is four times the age of his daughter. If after 5 years, he would be three times the age of the daughter, then further after 5 years (from that point), how many times older would the father be than his daughter?

Solution:

1. Present Ages:

• Let the daughter's current age be x.

• The father's current age is 4x.

2. Ages After 5 Years:

• Daughter's age = x + 5

• Father's age = 4x + 5

3. Equation After 5 Years:

• According to the problem, the father's age will be three times the daughter's age:
  4x + 5 = 3(x + 5)
  4x + 5 = 3x + 15
  4x - 3x = 15 - 5
  x = 10

4. Present Ages (Calculated):

• Daughter's age = 10 years

• Father's age = 4 * 10 = 40 years

5. Ages After "Further 5 Years":

• The question asks for ages "further after 5 years" from the initial 5-year mark, which means 10 years from the present age.

• Daughter's age = 10 + 10 = 20 years

• Father's age = 40 + 10 = 50 years

6. Ratio of Ages:

• Father's age / Daughter's age = 50 / 20 = 2.5.
  When setting up age equations where one person's age is a multiple of another's, (Memory Tip: Always multiply the multiple on the side with the smaller value (the younger person's age) to balance the equation.)

Answer: The father would be 2.5 times older than his daughter.

Topic 3: Time and Work

Question: A can do a piece of work in 10 days. B can do the same work in 20 days. With the help of C, they can finish the work in 4 days. How many days would C take to do the work alone?

Solution (LCM Method):

1. Individual Work Rates:

• A completes the work in 10 days.

• B completes the work in 20 days.

• A + B + C completes the work in 4 days.

2. Total Work (LCM):

• Find the Least Common Multiple (LCM) of 10, 20, and 4.

• LCM(10, 20, 4) = 20 units. This represents the total work to be done.

3. Calculate Daily Efficiency (Work per Day):

• A's efficiency = Total Work / A's days = 20 / 10 = 2 units/day

• B's efficiency = Total Work / B's days = 20 / 20 = 1 unit/day

• (A + B + C)'s efficiency = Total Work / (A+B+C)'s days = 20 / 4 = 5 units/day

4. Calculate C's Efficiency:

• The combined efficiency of A and B = A's efficiency + B's efficiency = 2 + 1 = 3 units/day.

• Since A, B, and C together do 5 units/day, C's efficiency is:
  C's efficiency = (A + B + C)'s efficiency - (A + B)'s efficiency
  C's efficiency = 5 - 3 = 2 units/day.

5. Days C Takes Alone:

• Days = Total Work / C's efficiency = 20 / 2 = 10 days.

Answer: C can do the work alone in 10 days.

Topic 4: Problem on Age (Brothers & Parents)

Question: The difference between the ages of two brothers is the same as the difference in the ages between their parents. The older brother is 14 years old. The mother was 30 years old when the younger brother was born. If the father is 4 years older than the mother, what was the mother's age when the elder brother was born?

Solution:

1. Define Variables:

• Let B1 be the age of the older brother.

• Let B2 be the age of the younger brother.

• Let F be the father's current age.

• Let M be the mother's current age.

2. Given Information:

• Age Difference Equality: B1 - B2 = F - M

• Older Brother's Age: B1 = 14 years.

• Mother's Age when Younger Brother was Born: Mother was 30 when B2 was 0.

• This implies the mother's current age (M) = 30 + B2 (current age of younger brother).

• Father's Age Relation: Father is 4 years older than Mother.

• F = M + 4

• Substitute M = 30 + B2: F = (30 + B2) + 4 = 34 + B2.

3. Substitute into Age Difference Equality:

• 14 - B2 = (34 + B2) - (30 + B2)

• 14 - B2 = 34 + B2 - 30 - B2

• 14 - B2 = 4

• -B2 = 4 - 14

• -B2 = -10

• B2 = 10 years (Current age of younger brother).

4. Calculate Mother's Current Age:

• M = 30 + B2 = 30 + 10 = 40 years.

5. Mother's Age when Elder Brother (B1) was Born:

• The elder brother's current age (B1) is 14 years.

• To find the mother's age when B1 was born, subtract B1's current age from the mother's current age.

• Mother's age at B1's birth = M - B1 = 40 - 14 = 26 years.

Answer: The mother's age when the elder brother was born was 26 years.

Shortcut Techniques to Solve NATA Maths Questions Faster

Using smart solving techniques can help you save valuable time in the NATA Mathematics section. 

• Convert percentages into fractions for faster calculations.

• Use the LCM method to solve Time and Work questions quickly.

• Memorize squares, cubes, and percentage-to-fraction conversions.

• Eliminate incorrect options first in multiple-choice questions.

• Use approximation techniques for lengthy calculations.

• Practice mental math to reduce dependency on rough work.

• Learn common formulas and revise them regularly.

• Attempt easier questions first to maximize your score within the time limit