
Many students preparing for NATA spend most of their time memorising Algebra formulas but struggle when similar questions appear in a different format. Topics such as quadratic equations, logarithms, matrices, determinants, AP & GP, and permutations & combinations are frequently tested, making previous-year question practice essential for improving speed and accuracy.
A smarter revision strategy is to practise the most repeated NATA Maths PYQs chapter-wise before attempting mixed questions. This collection brings together 15 frequently asked Algebra questions with detailed step-by-step solutions, helping you revise concepts, strengthen problem-solving methods and build confidence for the Mathematics section.
Start with chapter-wise PYQs: Solve NATA Maths Most Repeated Questions topic-wise – Quadratic Equations, Logarithms, AP & GP, Matrices and Determinants – before attempting mixed practice.
Question: If α\alphaα and β\betaβ are the roots of 2x2−4x+1=02x^2-4x+1=02x2−4x+1=0, find 1α+1β\frac{1}{\alpha}+\frac{1}{\beta}α1+β1.
Solution:
For ax2+bx+c=0ax^2+bx+c=0ax2+bx+c=0:
Sum of roots = −ba\frac{-b}{a}a−b
Product of roots = ca\frac{c}{a}ac
Here:
α+β=2\alpha\beta=2α+β=2
αβ=12\alpha\beta=\frac12αβ=21
1α+1β=α+βαβ=21/2=4\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{2}{1/2}=4α1+β1=αβα+β=1/22=4
Answer: 444
Question: Solve log2x+log2(x−2)=3\log_2x+\log_2(x-2)=3log2x+log2(x−2)=3.
Solution:
log2x(x−2)x(x−2)=3\log_2x(x−2)x(x-2)=3log2x(x−2)x(x−2)=3
x(x−2)=8x(x-2)=8x(x−2)=8
x2−2x−8=0x^2-2x-8=0x2−2x−8=0
(x−4)(x+2)=0(x-4)(x+2)=0(x−4)(x+2)=0
Only x=4x=4x=4 satisfies the logarithm condition.
Answer: 444
Question: The 5th term of an AP is 19, and the 11th term is 43. Find the 20th term.
Solution:
a+4d=19a+4d=19a+4d=19
a+10d=43a+10d=43a+10d=43
Subtracting:
6d=24⇒d=46d=24\Rightarrow d=46d=24⇒d=4
a=3a=3a=3
a20=3+19(4)=79a_{20}=3+19(4)=79a20=3+19(4)=79
Answer: 79
Question: Find the sum of:
1+13+19+127+⋯1+\frac13+\frac19+\frac1{27}+\cdots1+31+91+271+⋯
Solution:
Here a=1a=1a=1 and r=13r=\frac13r=31.
S∞=11−1/3=32S_\infty=\frac{1}{1-1/3}=\frac32S∞=1−1/31=23
Answer: 32\frac3223
Question: If
A=(2413)A=\begin{pmatrix}2&4\\1&3\end{pmatrix}A=(2143)
find ∣A−1∣|A^{-1}|∣A−1∣.
Solution:
∣A∣=(2)(3)−(4)(1)=2|A|=(2)(3)-(4)(1)=2∣A∣=(2)(3)−(4)(1)=2
∣A−1∣=1∣A∣=12|A^{-1}|=\frac1{|A|}=\frac12∣A−1∣=∣A∣1=21
Answer: 12\frac1221
Question: Find the modulus of
z=3+4i1−2iz=\frac{3+4i}{1-2i}z=1−2i3+4i
Solution:
∣3+4i∣=5|3+4i|=5∣3+4i∣=5
∣1−2i∣=5|1-2i|=\sqrt5∣1−2i∣=5
∣z∣=55=5|z|=\frac5{\sqrt5}=\sqrt5∣z∣=55=5
Answer: 5\sqrt55
Question: Find the middle term of
(x+2x)6\left(x+\frac2x\right)^6(x+x2)6
Solution:
The middle term is the 4th term.
T4=(63)x3(2x)3T_4=\binom63x^3\left(\frac2x\right)^3T4=(36)x3(x2)3
=20×8=160=20\times8=160=20×8=160
Answer: 160
Question: In how many ways can the letters of ARCH be arranged so that vowels are never together?
Solution:
ARCH contains only one vowel (A), so the condition is always satisfied.
Total arrangements:
4!=244!=244!=24
Answer: 24
Question: A committee of 4 is formed from 6 men and 4 women containing at least 2 women.
Solution:
|
Case |
Ways |
|
2 Women + 2 Men |
90 |
|
3 Women + 1 Man |
24 |
|
4 Women |
1 |
Total:
90+24+1=11590+24+1=11590+24+1=115
Answer: 115
Question: Solve ∣2x−3∣<5|2x-3|<5∣2x−3∣<5.
Solution:
−5<2x−3<5-5<2x-3<5−5<2x−3<5
−2<2x<8-2<2x<8−2<2x<8
−1<x<4-1<x<4−1<x<4
Answer: x∈(−1,4)x\in(-1,4)x∈(−1,4)
Question: Find the value of kkk if
(k236)\begin{pmatrix}k&2\\3&6\end{pmatrix}(k326)
is singular.
Solution:
A singular matrix has determinant zero.
6k−6=06k-6=06k−6=0
k=1k=1k=1
Answer: 1
Question: For what value of ppp does the system have infinitely many solutions?
x+2y=3x+2y=3x+2y=3
3x+py=93x+py=93x+py=9
Solution:
13=2p=39\frac13=\frac2p=\frac3931=p2=93
p=6p=6p=6
Answer: 6
Question: The roots of
x3−6x2+11x−6=0x^3-6x^2+11x-6=0x3−6x2+11x−6=0
are in AP. Find the roots.
Solution:
Let the roots be:
a−d, a, a+da-d,\ a,\ a+da−d, a, a+d
From the sum of roots:
3a=6⇒a=23a=6\Rightarrow a=23a=6⇒a=2
From the product:
(2−d)(2)(2+d)=6(2-d)(2)(2+d)=6(2−d)(2)(2+d)=6
d=1d=1d=1
Roots:
1, 2, 3
Question: Evaluate:
log35×log59\log_35\times\log_59log35×log59
Solution:
log5log3×log9log5\frac{\log5}{\log3}\times\frac{\log9}{\log5}log3log5×log5log9
=log39=2=\log_39=2=log39=2
Answer: 2
Question: Find
12+22+32+⋯+1021^2+2^2+3^2+\cdots+10^212+22+32+⋯+102
Solution:
Use:
Sn=n(n+1)(2n+1)6S_n=\frac{n(n+1)(2n+1)}6Sn=6n(n+1)(2n+1)
S10=10×11×216=385S_{10}=\frac{10\times11\times21}6=385S10=610×11×21=385
Answer: 385
Practising previous year questions is most effective when you follow a structured revision strategy instead of solving questions randomly. Focus on understanding the method behind each problem, strengthen frequently tested formulas and revisit repeated question patterns to improve both speed and accuracy.
Start with chapter-wise PYQs: Solve questions topic-wise – Quadratic Equations, Logarithms, AP & GP, Matrices and Determinants – before attempting mixed practice.
Write complete working steps: Even while practising MCQs, solve the calculation step by step to minimise errors and improve conceptual clarity.
Reattempt repeated PYQs: Rather than solving many new questions, revisit previous year Algebra questions multiple times until you can solve them confidently within the exam time limit.
Success in the NATA Mathematics section comes from consistent practice with questions that reflect the actual exam pattern. Revising these repeated Algebra PYQs helps strengthen concepts across quadratic equations, logarithms, matrices, sequences, determinants and permutations while improving calculation speed and problem-solving accuracy.