Increasing And Decreasing Function : Stationary point is defined as the points at which slope of tangent is equal to zero or at which curve take a U turn if slope of changes from negative to positive or positive to negative.
Change of slope form negative to positive makes the stationary point as local minima and change of slope from positive to negative makes the point as local maxima this could be shown as below graph.
In above graph as we could see
has stationary point
as local minima while
has stationary point
as local maxima.
Sometimes at stationary points curve does not takes U turn and continue to increase or decrease such as shown below
In above graph as we could see
has stationary point
and decreasing while
has stationary point
and increasing.
Critical points is defined as the points at which slope of tangent is either equal to zero known as stationary points or slope of tangent is undefined such as shown below
In above graph
are critical points with slope of tangent as zero and
are points with slope of tangent as undefined.
Point of inflection for a curve is defined as the points at which curve changes it concavity. It can either shift from concave upward to concave downward or concave downward to concave upward. Sign of double differential of the curve helps in identifying point of inflection if
than curve is concave upward and if
than curve is concave downward, change of value around point of inflection form
to
makes transition from concave upward to concave downward and vice versa.
In above graph
has point of inflection at
while
has point of inflection at
As discussed, critical, stationary and point of inflection are defined with the help of derivative of the curve let’s explore it with examples.
Example 1:
Find point of inflection for the curve
?
Sol.
Double Differentiate the function with respect to x as
Equate the function to zero
Now as we know point of infection changes behaviour of slope means either increasing to decreasing or decreasing to increasing.
For
,
gives value of
as negative and for
as positive hence it’s a point of inflection and changing concavity from concave downward to concave upward.
Example 2:
Find all set of stationaries points for the function
and find behaviours of slope around it?
Sol.
Differentiate the function with respect to
as
Equate the derivative to zero
By hit and trial approach one of the factors is
and remaining factor can be found using divisor method as
Behaviour of slope around
is from negative to positive
Behaviour of slope around
is from positive to negative
Behaviour of slope around
is from negative to positive
1.
Find all set of stationaries points for the function
and find behaviour of slope around it?
2.
Find point of inflection for the curve
?
1.
Find point of inflection for the function
in the interval
and define change in concavity at points of inflection?
Sol.
Differentiate the function with respect to
as
Equate the derivative to zero
graph if cos function is shown as
Double derivative of the curve would be as
equate it to zero
Graph of
would be as
Form graph we could observe
value at
changes from – to + when moving from
to
concavity from downward to upward
value at
changes from + to - when moving from
to
concavity from upward to downward
value at
changes from – to + when moving from
to
concavity from downward to upward
value at
changes from + to – when moving from
to
concavity from upward to downward
value at
changes from – to + when moving from
to
concavity from downward to upward
value at
changes from + to - when moving from
to
concavity from upward to downward
value at
changes from – to + when moving from
to
concavity from downward to upward
value at
changes from + to - when moving from
to
concavity from upward to downward
1.
Find point of inflection for the function
in the interval
and define change in concavity at points of inflection?
2.
Find point of inflection for the function
in the interval
if possible?