Preparing for Hydrocarbons, Purification and Organic Analysis for NEET requires you to understand reaction mechanisms, identify products under different conditions and remember the tests used to detect elements in organic compounds. From alkane, alkene, alkyne and benzene reactions to distillation, chromatography, Lassaigne's test and quantitative analysis, these topics combine conceptual understanding with reaction-based and numerical questions.
PW brings you the Hydrocarbon + Purification & Analysis of Organic Compounds Full Chapter Video for NEET. The video covers important concepts, reaction conditions, problem-solving approaches, useful tricks and previous year questions (PYQs). Use the video alongside these notes to revise key reactions, understand how to approach different question types and practise applying Organic Chemistry concepts for NEET 2027
A minimum of two carbon atoms is needed for a double or triple bond. Alkenes and cycloalkanes have the same general formula, CnH2n.
|
Class |
Structure |
Saturation |
General Formula |
|---|---|---|---|
|
Alkanes |
Open-chain compounds with single bonds |
Saturated |
CnH2n+2 |
|
Alkenes |
Open-chain compounds with at least one double bond |
Unsaturated |
CnH2n |
|
Alkynes |
Open-chain compounds with at least one triple bond |
Unsaturated |
CnH2n-2 |
|
Aromatic Hydrocarbons |
Benzene and its derivatives |
Aromatic |
No single formula |
Aromatic compounds must have continuous conjugation, planarity, cyclic delocalisation, and must follow Hückel’s rule. An sp3-hybridised carbon interrupts conjugation and makes the system non-aromatic.
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Alkanes are prepared by:
Catalytic hydrogenation of alkenes and alkynes using nickel, palladium, or platinum.
Reduction of alkyl halides using hydrogen and zinc.
Wurtz reaction, in which two alkyl halides react with sodium in dry ether:
2R-X + 2Na → R-R + 2NaX
Corey–House synthesis, using an organocuprate reagent.
Soda-lime decarboxylation of sodium carboxylates. The product has one less carbon atom.
Kolbe electrolysis of carboxylate salts.
Clemmensen reduction using zinc amalgam and concentrated hydrochloric acid.
Wolff–Kishner reduction using hydrazine and strong base.
Wurtz reaction and Kolbe electrolysis involve free-radical mechanisms.
Halogenation is a free-radical substitution reaction. Hydrogen is replaced by a halogen in the presence of sunlight or ultraviolet light.
R-H + X2 → R-X + HX
Fluorination is highly explosive, while iodination is slow and reversible. Chlorination and bromination are more commonly used.
Alkanes also undergo combustion, controlled oxidation, isomerisation, aromatisation, steam reaction, and pyrolysis.
Isomerisation: Anhydrous AlCl₃ and HCl, heat → Branched alkane.
Aromatisation: V₂O₅, Cr₂O₃, or Mo₂O₃ at about 773 K → Aromatic compound.
For example, n-hexane gives benzene during aromatisation. A seven-carbon cyclic system forms toluene because the carbon count must remain seven.
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Alkenes are prepared by:
Partial reduction of alkynes.
Dehydrohalogenation of alkyl halides using alcoholic KOH.
Dehydration of alcohols using concentrated sulfuric acid.
Dehalogenation of vicinal dihalides using zinc.
In dehydrohalogenation, the halogen leaves the alpha carbon and hydrogen leaves the beta carbon. The major product usually follows Saytzeff’s rule, which states that the more substituted alkene is formed predominantly.
Alcoholic KOH favours elimination, while aqueous KOH favours substitution and produces an alcohol. (*Memory Tip: Alcoholic KOH gives elimination; aqueous KOH gives substitution.)*
|
Reagent |
Product |
|---|---|
|
Lindlar catalyst |
Cis-alkene |
|
Sodium in liquid ammonia |
Trans-alkene |
The Lindlar catalyst is poisoned palladium supported on calcium carbonate or charcoal. It allows partial hydrogenation and gives a cis-alkene. Sodium in liquid ammonia gives a trans-alkene.
Alkenes undergo addition of hydrogen, halogens, hydrogen halides, water, sulfuric acid, and hypochlorous acid. Markovnikov and anti-Markovnikov rules apply to additions involving unsymmetrical alkenes.
With benzoyl peroxide, HBr follows the anti-Markovnikov rule. Bromine attaches to the carbon having more hydrogen atoms.
Ozonolysis cleaves the double bond:
Reductive ozonolysis: O3 followed by Zn and water gives aldehydes or ketones.
Oxidative ozonolysis: zinc is absent, so aldehydes are further oxidised to carboxylic acids.
(*Memory Tip: No zinc means oxidative ozonolysis, so aldehydes become carboxylic acids.)*
Alkenes also undergo polymerisation. Ethene forms polyethene under high temperature and pressure.
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A hydrogen attached to an sp-hybridised carbon is acidic. The sp carbon has 50% s-character, which increases its electronegativity and stabilises the conjugate base.
Terminal alkynes give:
Tollens’ Reagent: Aldehydes generally give a silver mirror or a grey/black deposit of silver.
Ammoniacal Cuprous Chloride: Gives a reddish-brown precipitate with terminal alkynes.
Alkynes can undergo two successive addition reactions. Hydration in the presence of mercuric sulfate and dilute acid initially gives an enol, which changes into a more stable carbonyl compound by tautomerisation.
Three moles of ethyne undergo cyclic polymerisation at about 873 K to form benzene. Three moles of propyne form mesitylene, or 1,3,5-trimethylbenzene.
Benzene mainly undergoes electrophilic aromatic substitution.
Nitration: Electrophile is NO₂⁺.
Sulfonation: Electrophile is SO₃.
Chlorination: Electrophile is Cl⁺.
Bromination: Electrophile is Br⁺.
Friedel–Crafts Alkylation: Electrophile is an alkyl electrophile.
Friedel–Crafts Acylation: Electrophile is an acyl electrophile.
Aluminium chloride helps generate the electrophile in Friedel–Crafts reactions. In nitration, sulfuric acid protonates nitric acid and produces the nitronium ion, NO2+.
Benzene can be prepared by:
Soda-lime decarboxylation of sodium benzoate.
Reduction of phenol with zinc dust.
Cyclic polymerisation of ethyne.
Aromatisation of n-hexane.
Benzene is reduced with hydrogen and nickel to form cyclohexane. Under ultraviolet light and heat, benzene reacts with three moles of chlorine to form benzene hexachloride, also called BHC, gammexane, lindane, or 666.
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Sublimation is used when one solid changes directly into vapour while the other component does not. Examples include iodine, camphor, naphthalene, and ammonium chloride.
Crystallisation depends on the difference in solubility of a compound and its impurities. A hot saturated solution is prepared and then cooled. The pure compound separates as crystals.
|
Type |
Use |
|---|---|
|
Simple distillation |
Liquids with a large boiling-point difference |
|
Fractional distillation |
Liquids with close boiling points |
|
Vacuum distillation |
Compounds that decompose at normal boiling points |
|
Steam distillation |
Steam-volatile, water-immiscible compounds |
Glycerol is separated from spent soap by vacuum distillation.
(*Memory Tip: Glycerol plus soap industry means vacuum distillation.)*
Chromatography has a stationary phase and a mobile phase. Silica gel and alumina are common stationary phases.
Column and thin-layer chromatography are mainly adsorption chromatography.
Paper chromatography is partition chromatography.
Spots may be detected using ultraviolet light, iodine vapour, or ninhydrin.
The Lassaigne or sodium extract test converts covalently bonded elements into ionic forms. It detects nitrogen, sulfur, phosphorus, and halogens.
Carbon and hydrogen are detected by heating the compound with copper oxide. Carbon forms carbon dioxide, which turns limewater milky. Hydrogen forms water, which turns anhydrous copper sulfate blue.
|
Element |
Test |
Observation
|
|---|---|---|
|
Chlorine |
Silver nitrate |
White AgCl |
|
Bromine |
Silver nitrate |
Pale-yellow AgBr |
|
Iodine |
Silver nitrate |
Bright-yellow AgI |
|
Nitrogen |
Iron sulfate and concentrated sulfuric acid |
Prussian blue |
|
Sulfur |
Sodium nitroprusside |
Violet or purple |
|
Sulfur and nitrogen |
Ferric chloride |
Blood red |
|
Phosphorus |
Ammonium phosphomolybdate test |
Canary-yellow precipitate |
During sodium fusion, nitrogen forms sodium cyanide:
NaCN
(*Memory Tip: In sodium fusion, nitrogen becomes NaCN.)*
|
Method |
Element Estimated |
Final Form
|
|---|---|---|
|
Liebig’s method |
Carbon and hydrogen |
Carbon dioxide and water |
|
Dumas method |
Nitrogen |
Nitrogen gas |
|
Kjeldahl’s method |
Nitrogen |
Ammonia |
|
Carius method |
Halogens, sulfur, phosphorus |
Silver halide, barium sulfate, magnesium pyrophosphate |
Kjeldahl’s method cannot estimate nitrogen in nitro compounds, azo compounds, or ring nitrogen, because the nitrogen cannot be converted into ammonia.
Carius analysis uses precipitate masses. Phosphorus is estimated through magnesium pyrophosphate, Mg2P2O7. For nitrogen estimation by the Dumas method, gas volume must be corrected to STP.
Q1. What are the general formulas of alkanes, alkenes and alkynes?
Answer:
Alkanes: CₙH₂ₙ₊₂
Alkenes: CₙH₂ₙ
Alkynes: CₙH₂ₙ₋₂
Q2. Which reaction converts two alkyl halide molecules into a higher alkane using sodium in dry ether?
Answer: The Wurtz reaction.
General reaction: 2R-X + 2Na → R-R + 2NaX.
Q3. What is the difference between alcoholic KOH and aqueous KOH in reactions with alkyl halides?
Answer: Alcoholic KOH generally favours elimination to form an alkene, while aqueous KOH generally favours substitution to form an alcohol.
Q4. Which reagent produces a cis-alkene from an alkyne?
Answer: Lindlar catalyst, which allows partial hydrogenation of the alkyne.
Q5. What product is obtained when an alkyne is partially reduced using sodium in liquid ammonia?
Answer: A trans-alkene.
Q6. What is the difference between reductive and oxidative ozonolysis?
Answer: Reductive ozonolysis uses zinc and water and produces aldehydes or ketones. Oxidative ozonolysis without zinc can convert aldehydes into carboxylic acids.
Q7. Why are terminal alkynes acidic?
Answer: Their terminal hydrogen is attached to an sp-hybridised carbon with 50% s-character. This increases the effective attraction for electrons and stabilises the conjugate base.
Q8. Which purification method is suitable for separating a sublimable solid from non-sublimable impurities?
Answer: Sublimation.
Q9. What is the principle of crystallisation?
Answer: Crystallisation uses differences in solubility, usually by preparing a hot saturated solution and cooling it so that the desired compound forms crystals.
Q10. Which distillation method is used for compounds that decompose at their normal boiling points?
Answer: Vacuum distillation. Reduced pressure lowers the boiling point and can help prevent thermal decomposition.
Q11. Which distillation method is generally used to separate liquids with close boiling points?
Answer: Fractional distillation.
Q12. What is the difference between adsorption chromatography and partition chromatography?
Answer: In adsorption chromatography, separation depends on different degrees of adsorption on a solid stationary phase. In partition chromatography, separation depends on the distribution of compounds between two phases. Column and thin-layer chromatography are commonly adsorption-based, while paper chromatography is partition-based.
Q13. Which test is commonly used to detect nitrogen in an organic compound?
Answer: Lassaigne's test followed by treatment with iron sulfate and acidification. A Prussian blue colour indicates nitrogen under the appropriate test conditions.
Q14. What is observed when carbon dioxide is passed through limewater?
Answer: Limewater turns milky due to the formation of calcium carbonate.
Q15. Which method is used to estimate carbon and hydrogen quantitatively?
Answer: Liebig's method. Carbon is estimated through the carbon dioxide formed, while hydrogen is estimated through the water formed.
Q16. Which method is used for nitrogen estimation by measuring nitrogen gas?
Answer: The Dumas method.
Q17. Why can Kjeldahl's method not estimate nitrogen in nitro and azo compounds?
Answer: The standard Kjeldahl method requires nitrogen to be converted into ammonia. Nitro and azo nitrogen are not converted into ammonia by this method, so they cannot be estimated using the standard procedure.
Q18. Which method is used to estimate halogens in an organic compound?
Answer: The Carius method. The halogen is converted into a silver halide precipitate, which can be used for quantitative estimation.
Watch the PW full-chapter one-shot video to revise Hydrocarbons, Purification and Analysis of Organic Compounds together. The session covers important concepts, reaction conditions, useful tricks, previous year questions (PYQs) and problem-solving approaches to help you practise different question types for NEET.
Preparing for Hydrocarbons, Purification and Organic Analysis for NEET requires regular revision of reaction conditions, product identification, purification techniques and analytical tests. Focus on understanding why reactions produce particular products, when each purification method is used and how qualitative and quantitative tests work. Practise the questions after each section and revisit concepts you find difficult. Use these notes alongside the PW full-chapter one-shot video, which covers concepts, tricks, PYQs and problem-solving approaches, to reinforce your Organic Chemistry preparation for NEET
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