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Rotational Motion: Concepts and Tricks For NEET

Moment of inertia measures resistance to rotational motion and depends on mass distribution and perpendicular distance from the axis. Key results include point masses, rods, rings, discs, spheres, and cylinders. The Parallel Axis Theorem handles shifted axes, while the Perpendicular Axis Theorem applies only to planar bodies. Standard formulas and axis selection are essential for NEET.
authorImageAmit Kumar Singh13 Oct, 2026
Rotational Motion: Concepts and Tricks For NEET

Rotational motion explains how bodies rotate about an axis. The chapter covers moment of inertia, its calculation for point masses and extended bodies, and standard formulas for different shapes.

The Parallel Axis Theorem and Perpendicular Axis Theorem are also important concepts in this topic. Correctly identifying the axis of rotation and the distance from it helps students solve numerical problems for NEET, JEE Main, and JEE Advanced.

Moment of Inertia Concept and Definition

Moment of inertia is the rotational analogue of inertia. In translational motion, a body resists changes in its state of motion. Similarly, a rotating body tends to continue rotating unless an external torque changes its motion.

For a point mass:

I = m r^2

Here, m is the mass and r is the perpendicular distance from the axis of rotation.

For a system of discrete particles:

I = Sum of m_i r_i^2

The distance must always be measured perpendicular to the axis. Since the distance is squared, its sign does not affect the result. For example, a distance of -4 is used as 4 because (-4)^2 = 16.

The moment of inertia of a point mass is zero when the mass lies directly on the axis because r = 0.

Moment Of Inertia Of Point Masses

To calculate the moment of inertia about any specified axis:

  1. Find the perpendicular distance of every mass from the axis.

  2. Calculate m_i r_i^2 for each mass.

  3. Add all contributions.

For the x-axis, distances are measured vertically from the x-axis. For the y-axis, distances are measured horizontally from the y-axis. For the z-axis, the perpendicular distance must be found geometrically.

The central principle remains:

I = Sum of m_i r_i^2

A particle located on the selected axis contributes zero.

Equilateral Triangle Of Point Masses

Three equal masses m are placed at the vertices of an equilateral triangle of side l.

For the x-axis, two masses may lie on the axis and contribute zero. The third mass is at a perpendicular distance of √3 l / 2. Therefore:

I_x = m (√3 l / 2)^2

For the y-axis, one mass lies on the axis, while the other two are at distances l and l / 2:

I_y = m l^2 + m (l / 2)^2

For the z-axis perpendicular to the triangle’s plane:

I_z = m l^2 + m l^2

For this planar arrangement:

I_x + I_y = I_z

This is a common JEE Main pattern and directly demonstrates the Perpendicular Axis Theorem.

Moment Of Inertia Of A Uniform Rod

For an extended body, divide it into small elements and integrate their contributions.

For a uniform rod of mass M and length l, a small element of length dx at distance x has mass:

dm = (M / l) dx

Its differential moment of inertia is:

dI = x^2 dm

Thus:

I = Integral of x^2 dm

For an axis through one end and perpendicular to the rod:

I = M l^2 / 3

For a nonuniform rod, the linear density must remain inside the integration. If the density is:

Lambda = Lambda_0 x

then:

dm = Lambda_0 x dx

and:

I = Integral of Lambda_0 x^3 dx = Lambda_0 l^4 / 4

The main rule is that position-dependent density cannot be treated as a constant.

Standard Results For A Thin Rod

The moment of inertia of a thin rod depends on the position and direction of the axis of rotation. The following table shows the standard results for a rod of mass M: 

 

Axis

Moment Of Inertia

Through one end and perpendicular to the rod

M l^2 / 3

Through the centre of mass and perpendicular to the rod

M l^2 / 12

Along the rod’s own axis

0

 

The result for the rod’s own axis is zero because the rod is considered thin and its mass lies on the axis.

Rod Inclined At An Angle

If a uniform rod of length l makes an angle theta with the axis, the perpendicular distance of an element at distance x is:

r = x sin theta

Therefore:

I = M l^2 sin^2 theta / 3

A useful shortcut is to use the projected length:

Effective length = l sin theta

Then apply the end-axis rod formula:

I = M (Effective length)^2 / 3

For a system of rods, calculate the moment of inertia of each rod about the same axis and add the results.

Standard Moments Of Inertia

The following results should generally be remembered for examinations.

 

Body Or Configuration

Moment Of Inertia

Point mass or mass concentrated at distance R

M R^2

Thin ring about central axis

M R^2

Hollow cylinder about central axis

M R^2

Disc about central axis

M R^2 / 2

Solid cylinder about central axis

M R^2 / 2

Solid cone about symmetry axis

3 M R^2 / 10

Hollow cone about symmetry axis

M R^2 / 2

Solid sphere about diameter

2 M R^2 / 5

Hollow sphere about diameter

2 M R^2 / 3

Thin rod about one end

M l^2 / 3

Thin rod about centre

M l^2 / 12

 

Parallel Axis Theorem

The Parallel Axis Theorem relates the moment of inertia about an arbitrary axis to the moment of inertia about a parallel axis through the centre of mass.

I = I_C + M D^2

Here, I_C is the moment of inertia about the centre-of-mass axis, M is the total mass, and D is the separation between the parallel axes.

The two axes must be parallel, and the reference axis for I_C must pass through the centre of mass.

A direct consequence is that the moment of inertia is minimum about an axis passing through the centre of mass.

For example, for a ring about a tangent axis:

I = M R^2 + M R^2 = 2 M R^2

For a disc about an axis parallel to its central axis:

I = M R^2 / 2 + M D^2

Perpendicular Axis Theorem

The Perpendicular Axis Theorem applies only to a two-dimensional planar body such as a disc, ring, plate, sheet, or square lamina.

If x and y are mutually perpendicular axes in the plane and z is perpendicular to that plane through their intersection:

I_z = I_x + I_y

The theorem must not be applied directly to three-dimensional bodies such as solid spheres and hollow spheres.

For a ring:

I_z = M R^2

By symmetry, the moments about two perpendicular diameters are equal:

I_x = I_y = M R^2 / 2

For a disc:

I_z = M R^2 / 2

Therefore, about any diameter through its centre:

I_x = I_y = M R^2 / 4

Composite Bodies And Removed Parts

For multiple bodies:

I_total = I_1 + I_2 + I_3 + …

Calculate the contribution of each part about the required axis. Apply the Parallel Axis Theorem when a component’s central axis does not match the required axis.

For a removed part, treat it as negative mass:

I_remaining = I_complete body - I_removed part

This method is useful for discs with circular portions removed. For identical repeated components, calculate one contribution and multiply it by the number of components.

Common Mistakes to Avoid in Rotational Motion

Students can make mistakes in Rotational Motion by choosing the wrong axis, using incorrect formulas, or applying the axis theorems incorrectly. Keep the following points in mind while solving numerical problems.

  • Using the wrong distance: Always measure the perpendicular distance of a mass from the axis of rotation when calculating moment of inertia.

  • Applying the Parallel Axis Theorem incorrectly: The two axes must be parallel, and the reference axis must pass through the centre of mass.

  • Misusing the Perpendicular Axis Theorem: Apply it only to planar bodies, not directly to three-dimensional bodies such as solid spheres.

  • Confusing standard formulas: Check the body's shape, mass distribution, and axis of rotation before selecting a formula.

  • Ignoring the axis position: The moment of inertia changes when the axis shifts. For a rod, the values differ for an axis through its centre and one through its end.

  • Adding removed parts instead of subtracting them: When calculating the moment of inertia of a body with a portion removed, subtract the removed part's contribution from that of the complete body.

Understanding moment of inertia, standard formulas, and the Parallel and Perpendicular Axis Theorems is important for solving Rotational Motion problems. Revise these concepts and practise numerical questions to strengthen your preparation for NEET.

FAQs

What Is The Formula For The Moment Of Inertia Of A Point Mass?

The formula is I = m r^2, where r is the perpendicular distance from the axis of rotation.

When Is The Moment Of Inertia Of A Particle Zero?

It is zero when the particle lies directly on the axis because its perpendicular distance is zero.

 

When Is The Parallel Axis Theorem Used?

It is used when the required axis is parallel to an axis through the centre of mass. The formula is I = I_C + M D^2.

What Is The Limitation Of The Perpendicular Axis Theorem?

It applies only to planar or two-dimensional bodies. It cannot be directly used for solid spheres or other general three-dimensional bodies.

Which Moment Of Inertia Formulas Should Be Memorised for NEET?

Important results include those for rods, rings, discs, cylinders, cones, and spheres. Standard formulas should be remembered to save time during examination problem-solving.
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