RRB NTPC Maths Time And Work Questions with Solutions and Tricks

RRB NTPC Maths Time And Work is one of the most scoring chapters in railway exam maths. Questions from this topic appear regularly in the RRB NTPC examination. With clear concepts and regular practice, candidates can solve time and work questions quickly and accurately. RRB NTPC Maths Time And Work focuses on efficiency, total work, and time calculation, which are essential skills for competitive exams in 2026.

This chapter tests logical thinking rather than lengthy calculations. Candidates preparing for railway exam maths must understand RRB NTPC Maths Time And Work to improve overall accuracy and time management.

RRB NTPC Maths Time And Work Overview

RRB NTPC Maths Time And Work is based on the relationship between work done, time taken, and efficiency. The chapter includes individual work, combined work, partial work, alternate days work, and efficiency-based problems.

In RRB NTPC maths time and work, the examiner checks whether the candidate can convert statements into mathematical form. Most time and work questions follow a standard pattern. Once the base is clear, solving them becomes easier. Mentioned below are key concepts covered:

• Total work

• Efficiency of a worker

• Combined efficiency

• Fractional work

• Work done in parts

• Alternate days work

• Men and women efficiency

• Worker leaving or joining mid-way

RRB NTPC Maths Time And Work is closely linked with other railway exam maths topics such as ratio, percentage, and algebra. 

Also Read: RRB NTPC Selection Process

RRB NTPC Maths Time And Work Questions with Solution

RRB NTPC Maths Time And Work Questions with Solution help candidates understand how concepts are applied in real exam scenarios. This section includes exam-oriented questions with step-by-step solutions to improve accuracy, speed, and confidence while solving railway exam maths problems.

Q1. A completes a work in 20 days. B completes the same work in 30 days. In how many days will they complete the work together?

Solution:
A’s efficiency = 1/20
B’s efficiency = 1/30
Combined efficiency = 1/20 + 1/30 = 5/60
Time = 60/5 = 12 days

Q2. A can complete a work in 12 days and B in 18 days. Find time taken together.

Solution:
LCM = 36
A = 3 units/day, B = 2 units/day
Combined = 5 units/day
Time = 36/5 = 7.2 days

Q3. A completes 1/5 work in 4 days. B completes 1/6 work in 5 days. Find total time together.

Solution:
A total time = 20 days
B total time = 30 days
LCM = 60
Combined efficiency = 5 units/day
Time = 12 days

Q4. A completes work in 30 days, B in 60 days. They work together for 5 days. How much work remains?

Solution:
LCM = 60
Combined efficiency = 3 units/day
Work done = 15 units
Remaining = 45 units

Q5. A, B, and C complete work in 12, 15, and 20 days. Find time together.

Solution:
LCM = 60
Efficiency = 5 + 4 + 3 = 12
Time = 60/12 = 5 days

Q6. A works on alternate days and completes work in 15 days. B works on alternate days and completes work in 20 days. How many days will they take together?

Solution:
LCM = 60
A = 4 units, B = 3 units
Work in 2 days = 7 units
Total days = 17 days

Q7. A, B, C work in sequence. A=10 days, B=20 days, C=30 days.

Solution:
LCM = 60
Work in 3 days = 11 units
Remaining calculation gives 15.83 days

Q8. A and B together finish work in 18 days. B and C in 24 days. A and C in 36 days. Find time taken by all three.

Solution:
LCM = 72
Combined efficiency = 9/2
Time = 16 days

Q9. A completes 50% work in 16 days. B completes 25% work in 24 days. Find time for 75% work together.

Solution:
A total = 32 days
B total = 96 days
Time = 18 days

Q10. 20 men complete work in 30 days. After 10 days, 4 men leave. Find total days.

Solution:
Remaining work = 400 units
Remaining men = 16
Time = 35 days

Q11. A and B complete work in 12 hours. B takes 10 hours more than A alone. Find time for B to complete 50%.

Solution:
B total time = 30 hours
50% time = 15 hours

Q12. A completes 40% in 12 days. B completes 60% in 15 days. C finishes remaining in 4 days. Find time for all to complete 28%.

Solution:
Combined efficiency = 21 units/day
Time = 2 days

Q13. Workers complete work in 34 days at 9 hours/day. Workers reduced by 40%. Find new hours for 51 days.

Solution:
Required hours = 10 hours/day

Q14. A completes work in 48 days. B is half efficient. C is sum of A and B. Find time for C alone.

Solution:
C efficiency = 3 units
Time = 16 days

Q15. 4 men and 5 women complete work in 15 days. 9 men and 6 women in 10 days. Find women needed with 4 men in 7 days.

Solution:
Women required = 13 

Also Read: RRB NTPC Salary 

RRB NTPC Maths Time And Work Tricks

Using time and work tricks helps reduce calculation time in railway exam maths. Listed here are some of the important tricks: 

• Always convert days into efficiency form

• Use LCM when numbers are manageable

• For large numbers, use efficiency ratios

• In alternate day problems, calculate work per cycle

• For men and women problems, first find efficiency ratio

• For percentage work, convert to fractions

• Remember formula:
  Time = Total Work / Combined Efficiency

These time and work tricks improve speed and accuracy in RRB NTPC Maths Time And Work. 

RRB NTPC Maths Time And Work is a scoring chapter when prepared with clarity. It supports other railway exam maths topics and improves problem-solving confidence. Regular practice of time and work questions and correct use of time and work tricks will help candidates perform better in RRB NTPC 2026.