Worksheet for class 7 maths for chapter - 5 Factorisation

Worksheet for class 7 maths for chapter - 5 Factorisation

Sep 29, 2022, 16:45 IST

In mathematics, factorisation or factoring is defined as breaking or decomposition of an entity (for example, number, matrix, or polynomial) into another product, or common factors, which gives an original number or matrix when repeated together, etc. You will learn this lesson in your lower classes from 6 to 8.

This page consist of subjective questions worksheet for chapter Factorisation of class 7 Maths with detail solutions. Do follow all Class 7 Maths Worksheet prepared by expert faculty members of Physics Wallah.

Before solving worksheet do solve questions of NCERT Text book with the help of Physics Wallah NCERT solutions for class 7 Maths . For additional information related to the subject you can check the Maths Formula section.

Solved Example

Q1 . Find the H.C.F. of

1. 6ab ² and 9a ² b ²
2. 15x ² y ³ z ⁴ , 20x ³ y ⁴ z ⁵ and 25x ⁴ y ⁵ z ⁶

Solution:

1. H.C.F. of 6ab ² and 9a ² b ²

= (H.C.F of 6 and 9) x (H.C.F. of ab ² and a ² b ² )

2. H.C.F. of 15x ² y ³ z ⁴ ,20x3 y ⁴ z ⁵ and 25x4 y5z ⁶

= (H.C.F of 15, 20 and 25) x (x ² y3z ^4, x ³ y ⁴ z5 and x ⁴ y ⁵ z ⁶ )

= 5x ² y ³ z ⁴

Q2. Find the H.C.F. of

1. 6ab ² and 9a ² b ²
2. 5x2 y3z ^4, 20x ³ y4z5 and 25x4 y ⁵ z ⁶

Solution:

1. H.C.F. of 6ab ² and 9a ² b ²

= (H.C.F of 6 and 9) x (H.C.F. of ab ² and a ² b ² )

= 3 ab ²

2. H.C.F. of 15x ² y ³ z ⁴ ,20x ³ y ⁴ z ⁵ and 25x ⁴ y ⁵ z ⁶

= 5x ² y ³ z ⁴

Q3 . Factorise:

1. 4x ² y + 12 y
2. 3a ² b + 6ab - 24a
3. 36a ³ b - 60a ² bc
4. 6xy ² + 9x ² y - 24xy

Solution:

1. H.C.F. of 4x ² y and 12y is 4y

So, 4y is a common factor of each term.

4x ² y + 12y = 4y(x ² + 3)

2. H.C.F. of 3a ² b, 6ab and 24a is 3a

3a ² b - 6ab -24a = 3a(ab + 2b - 8)

3. H.C.F. of 36a ³ b and 60a ² bc is 12a ² b

36a ³ b - 60a ² bc = 12a ² b(3a - 5c)

4. H.C.F. of 6xy ² ,9x ² y and 24xy is 3xy

6xy ² + 9x ² y - 24xy = 3xy(2y + 3x - 8)

Q4 . Factorise:

1. 4x(a + 3b) - 7 y(a + 3b)
2. a(a ³ + 2) - 2(a ³ + 2)
3. 9(x + 2y) ³ + 6(x + 2y) ²
4. a(a - b) ³ + 3a ² b(a - b)

Solution:

1. 4x(a + 3b) - 7 y(a + 3b) = (a + 3b) (4x - 7y)

2. a(a ³ + 2) - 2(a ³ + 2) = (a ³ + 2)(a - 2)

3. 9(x + 2y) ³ + 6(x + 2y) ² = 3(x + 2y) ² [3(x + 2 y) + 2]

= 3(x + 2y) ² (3x +6y + 2 )

4. a(a - b) ³ + 3a ² b(a - b) = a(a - b) [(a - b) ² + 3ab]

= a(a - b)(a ² - 2ab + b ² + 3ab)

= a(a - b)(a ² + ab + b ² )

Also Check

1. RS Aggarwal Class 7 solutions for Maths
2. Factorisation Mind Map

Find below the worksheet-5 for chapter Factorisation