A moving vehicle, a running athlete or a travelling train may cover different distances in different amounts of time. Understanding such situations requires you to connect distance, time and speed correctly. Many questions in this chapter involve calculations, unit conversions and comparisons between objects moving at different speeds. Identifying uniform and non-uniform motion and calculating average speed can also be confusing when the given values need to be interpreted carefully.
The NCERT Solutions Class 7 Science Curiosity Chapter 8 explain these concepts through clear answers and step-by-step calculations. They cover speed, distance, time, unit conversion, uniform and non-uniform motion, average speed and practical examples of motion.
The following solutions cover the textbook questions on speed, distance, time and different types of motion.
Answer:
Given:
Distance = 150 m
Time = 10 s
Using the formula:
Speed = Distance ÷ Time
Speed = 150 ÷ 10 = 15 m/s
To convert m/s into km/h:
15 × 18/5 = 54 km/h
Answer: 54 km/h
The conversion rules are:
m/s to km/h: multiply by 18/5
km/h to m/s: multiply by 5/18
Answer:
For Runner A:
Distance = 400 m
Time = 50 s
Speed of Runner A = 400 ÷ 50 = 8 m/s
For Runner B:
Distance = 400 m
Time = 45 s
Speed of Runner B = 400 ÷ 45 ≈ 8.89 m/s
Difference in speed:
8.89 − 8 = 0.89 m/s
Answer: Runner B has the greater speed by approximately 0.89 m/s.
Answer:
Given:
Speed = 25 m/s
Distance = 360 km
First, convert the speed into km/h:
25 × 18/5 = 90 km/h
Using:
Time = Distance ÷ Speed
Time = 360 ÷ 90 = 4 hours
Answer: 4 hours
Answer:
Distance = 180 km
Time = 3 h
Speed = Distance ÷ Time
Speed = 180 ÷ 3 = 60 km/h
Answer: 60 km/h
Convert 60 km/h into m/s:
60 × 5/18 = 16.67 m/s
Answer: 16.67 m/s
Answer:
Speed = 60 km/h
Time = 4 h
Using:
Distance = Speed × Time
Distance = 60 × 4 = 240 km
Answer: 240 km
Answer:
Speed of horse = 18 m/s
Speed of train = 72 km/h
Convert the train's speed into m/s:
72 × 5/18 = 20 m/s
Difference:
20 − 18 = 2 m/s
Answer: The train is faster than the horse by 2 m/s.
Answer:
|
Uniform Motion |
Non-uniform Motion |
|
An object covers equal distances in equal intervals of time. |
An object covers unequal distances in equal intervals of time. |
|
Its speed remains constant. |
Its speed changes with time. |
|
Example: A car moving on a straight highway without traffic at a constant speed. |
Example: A car moving through city traffic while slowing down, stopping or speeding up. |
Answer:
The object covers 8 m every 10 seconds.
|
Time (s) |
0 |
10 |
20 |
30 |
40 |
50 |
60 |
70 |
|
Distance (m) |
0 |
8 |
16 |
24 |
32 |
40 |
48 |
56 |
Therefore, the missing values are:
Distance at 20 s = 16 m
Time corresponding to 32 m = 40 s
Distance at 60 s = 48 m
Time corresponding to 48 m = 60 s
The speed of the object is:
Speed = 8 ÷ 10 = 0.8 m/s
Answer: 40 s, 16 m, 60 s and 48 m.
Answer:
The motion is non-uniform because the car covers different distances during equal intervals of time.
Total distance:
60 + 70 + 50 = 180 km
Total time = 3 hours
Average speed:
Average speed = Total distance ÷ Total time
= 180 ÷ 3
= 60 km/h
Answer:
Motion = Non-uniform
Average speed = 60 km/h
Answer:
Non-uniform motion is more common in daily life because the speed of moving objects frequently changes.
Examples:
A vehicle slows down or stops when an animal comes onto the road.
A vehicle changes its speed or stops in traffic.
A vehicle slows down while passing over potholes.
Answer:
|
Time (s) |
0 |
10 |
20 |
30 |
40 |
50 |
60 |
70 |
80 |
90 |
100 |
|
Distance (m) |
0 |
6 |
10 |
16 |
21 |
29 |
35 |
42 |
45 |
55 |
60 |
The speed is non-uniform because the object does not cover equal distances in equal intervals of time.
Total distance = 60 m
Total time = 100 s
Average speed:
Average speed = Total distance ÷ Total time
= 60 ÷ 100
= 0.6 m/s
Answer:
Speed = Non-uniform
Average speed = 0.6 m/s
For quick access during revision, having the chapter’s numerical questions and key concepts in one resource can make practice easier. The Class 7 Science Curiosity Chapter 8 Solutions PDF covers speed, distance, time, unit conversions, uniform and non-uniform motion, and average-speed questions.
Study without using the internet
The NCERT Class 7 Science Chapter 8 Solutions by PW make topics related to time, distance and motion easier to understand through numerical questions, examples and clear explanations. Key learning areas include:
Learn Speed Calculation: Understand how distance and time are related to the speed of a moving object.
Master Unit Conversions: Practise converting speed from m/s to km/h and vice versa.
Identify Different Motions: Distinguish between uniform and non-uniform motion using familiar situations.
Work Out Average Speed: Understand how total distance and total time are used to find average speed.
Practise Numerical Questions: Solve problems based on cars, trains, runners and other moving objects.
Read Motion Data: Analyse distance-time tables to identify changes in speed and patterns of motion.
Use Concepts in Daily Life: Relate measurements of time, distance and speed to everyday situations.
Follow Accurate Calculations: Apply the correct formulas, units and calculation steps while solving problems.
Understanding how objects move becomes easier when distance, time and speed are studied together. The NCERT Class 7 Science Chapter 8 Solutions explain numerical questions on speed, unit conversion, uniform and non-uniform motion and average speed with clear calculations. Practising these questions can help children apply the concepts correctly and improve accuracy while solving problems related to motion.
Related Resources
