RS Aggarwal Solutions for Class 8 Maths Chapter 5 Exercise 5.4: The Physics Wallah academic team has produced a comprehensive answer for Chapter 5: Playing with Numbers in the RS Aggarwal class 8 textbook. One should read Chapter 5 Playing with Numbers Theory before attempting to solve all of the numerical problems in exercise 5D.
This will ensure that you have a firm understanding of Chapter 5 Playing with Numbers. For class 8 maths students, the NCERT textbook is a highly recommended resource for solving numerical problems and referencing NCERT solutions.RS Aggarwal Solutions for Class 8 Maths Chapter 5 Exercise 5.4 PDF
Tick (√) the correct answer in each of the following:
Question (1) If 5×6 is exactly divisible by 3, then the least value of x is
Ans: (b) 1
5 + x + 6 = (11 + x) must be divisible by 3. This happens when x = 1 or 4 or 7. Since x is digit, it cannot be more than 9. ∴ x = 1Question (2) If 64y8 is exactly by 3, then the least value of y is
Ans: (a) 0
6 + 4 + y + 8 = 18 + y This is divisible by 3 as y is equal to 0.Question (3) If 7×8 is exactly divisible by 9, then the least value of y is
Ans: (c) 3
7 + x + 8 = 15 + x 18 is divisible by 9. Therefore, 15 + x = 18 ⇒ x = 3Question (4) If 37y4 is exactly divisible by 9, then the least value of y is
Ans: (d) 4
3 + 7 + y + 4 = 14 + y ∴ 14 y = 18 ⇒ y = 18 – 14 = 4Question (5) If 4xy7 is exactly divisible by 3, then the least value of (x + y) is
Ans: (a) 1
4 + x + y +7 = 11 + (x + y) ⇒ 11 + (x + y) = 12 ⇒ (x + y) = 12 – 11 = 1Question (6) If x7y5z is exactly divisible by 3, then the least value of (x + y) is
Ans: (d) 3
x + 7 + y + 5 = (x + y) + 12 This sum is divisible by 3 is x + y + 12 is 12 or 15. ∴ x + y + 12 = 12 ⇒ x + y = 12 – 12 = 0 But x + y cannot be 0 because x and y will habe to be 0. ∴ x + y + 12 = 15 ⇒ x + y = 15 – 12 = 3Question (7) If x4y5z exactly divisible by 9, then the least value of (x + y + z) is
Ans: (c) 9
X + 4 + y + 5 + z = 9 + (x + y + z) This equation is equal to 0 for the number x4y5z to be divisible by 9. But x is the first digit, so it can’t be 0. ∴ x + 4 + y + 5 +z = 18 ⇒ x + y + z = 18 – 9 = 9Question (8) If 1A2B5 is exactly divisible by 9, then the least value of (A + B) is
Ans: (b) 1
1 +A + 2 + B + 5 = (A + B) + 8 The number is divisible by 9 is (A + B) = 1Question (9) If the 4-digit number x27y is exactly divisible by 9, then the least value of 9x + y) is
Ans: (d) 9
X + 2 + 7 + y = (x + y) + 9 This sum will be divisible by 9, if (x + y) is 0. Since, x is the first digit it can never be 0. ∴ x + y + 9 = 18 ⇒ x + y = 9Identification Skills: Students learn how to identify co-prime numbers, which are pairs of numbers with no common factors other than 1. This knowledge is foundational for advanced number theory.
Real-Life Application: Understanding co-prime numbers helps in various real-life applications, such as cryptography and coding.
2. Strengthened Grasp of GCD and LCMEfficient Calculation: The solutions provide efficient methods for calculating the greatest common divisor (GCD) and least common multiple (LCM), enhancing computational skills.
Multiple Methods: Students learn different approaches to finding GCD and LCM, such as prime factorization and the division method, broadening their mathematical toolkit.
3. Improved Problem-Solving SkillsLogical Thinking: The exercise encourages logical reasoning and analytical thinking, essential skills for solving complex mathematical problems.
Pattern Recognition: By practicing these exercises, students develop the ability to recognize patterns and relationships between numbers, boosting their problem-solving efficiency.