IBPS Clerk Quantitative Aptitude 2026: Complete Paper Analysis with Solutions

Complete analysis of IBPS Clerk Quantitative Aptitude 2026 paper is given here by Sumit sir (Banking Wallah). Success in the IBPS Clerk Quantitative Aptitude section hinges on a structured approach rather than endless new strategies. 

Know the foundational learning process, including the exam pattern, and critical problem-solving techniques for key topics like Data Interpretation, Number Series, Simplification, and various Arithmetic problems.

How to Prepare the Quantitative Aptitude 2026 Section?

The faculty emphasizes that success in quantitative aptitude stems from the disciplined execution of a fundamental process, not a search for novel strategies.

The core strategy for mastering any quantitative subject involves three crucial steps:

1. Syllabus Completion: Systematically learn all the concepts and topics prescribed in the syllabus.

2. Revision & Practice: Consistently revise learned material and practice a wide variety of problems to build speed and accuracy.

3. Mock Tests: Regularly take mock tests under exam conditions to assess performance, identify weak areas, and improve time management.

Faculty Emphasis: Continuously seeking new "strategies" without implementing this core process is a waste of time. A student who follows this simple, consistent plan will see guaranteed improvement.

IBPS Clerk Quant Exam Pattern

The quantitative aptitude section in the IBPS Clerk exam has a predictable structure, with a strong emphasis on speed.

The key difference between a Clerical and a PO (Probationary Officer) exam is the complexity level; clerical exams require less complex problem framing.

How to Solve Data Interpretation (Bar Graph) Questions?

This section uses a bar graph showing the percentage distribution of total tables sold across five months.

Dataset Overview:

• Total Tables Sold (All Months): 42,000

• Table Types: Wooden and Plastic (specific breakdown derived from questions).

Initial Data Extraction & Calculation:

The first step is to calculate the absolute number of tables sold each month from the given percentages.

Solved Examples of Data Interpretation (Bar Graph):

1. Multi-Month Average:

• Problem: Average tables sold in June, July, August, September is 7,600. Wooden tables in September are 6.67% more than Plastic. Find Wooden tables in September.

• Solution Path: Calculate total for 4 months, subtract known 3 months to find September's total. Convert 6.67% to 1/15, establishing a ratio of 16:15 for Wooden:Plastic, then divide September's total. (Answer: 1,600)

2. Simple Ratio:

• Problem: Ratio of total tables sold in April & May together to June & July together.

• Solution Path: Sum percentages directly (April + May = 35%, June + July = 50%). The ratio of percentages is the required ratio. (Answer: 7 : 10)

3. Careful Language Interpretation:

• Problem: In May, Wooden tables are 13/8 of Plastic. In August, Plastic tables are two times more than Plastic in May. Find the average of Wooden tables in August and total tables in April.

• Solution Path: Calculate Plastic tables in May. Understand "two times more than X" means 3X for August's Plastic tables. Find August's Wooden tables. Calculate the average. (Answer: 6,000)

4. Simultaneous Equations:

• Problem: Ratio of wooden tables in June to July is 7:3. Plastic tables in June are 16.66% more than in July. Find the difference between wooden tables in June and July.

• Solution Path: Set up variables for Wooden and Plastic tables for June and July using given ratios and percentages (16.66% = 1/6 implies a 7:6 ratio for Plastic tables). Form two equations based on total sales for June and July, solve simultaneously, then find the difference. (Answer: 3,200)

How to solve Data Interpretation (Caslet)?

This problem requires creating a table by carefully interpreting and connecting multiple data points to deduce unknown values.

The question is based on Rehab Patient Center:

• Four rehab centers: K, L, M, N.

• Two types of patients: Smokers and Drinkers.

Data Derivation and Logic (Key Steps):

1. Center L: Drinkers (40) is 4/9 of total L. Calculate Total L, then Smokers L.

2. Center N: Smokers (50). Drinkers N are 40% more than Smokers N. Calculate Drinkers N, then Total N.

3. Smokers K & L: This sum is 8.33% (1/12) more than Total N. Use Smokers L to find Smokers K.

4. Center K: Smokers K is 14.28% (1/7) more than Drinkers K, implying an 8:7 ratio. Use Smokers K to find Drinkers K, then Total K.

5. Center M: Total M is 170. Average Smokers (M & N) equals Drinkers N (70). Use this to find Smokers M, then Drinkers M.

Final Data Table:

How to solve Number Series Questions?

Identifying patterns quickly is crucial for these questions.

1. Series: 24, 22, 25, 20, 27, ?

• Pattern: Alternating subtraction and addition of consecutive prime numbers (2, 3, 5, 7, 11…).

• (Answer: 16)

2. Series: 30, ?, 15, 30, 7.5, 15

• Pattern: Alternating ×2 and ÷4. Work backward from 15.

• (Answer: 60)

3. Series: 12, 18, 36, 90, 270, ?

• Pattern: Multiplication by a factor that increases by 0.5 (×1.5, ×2, ×2.5, ×3, ×3.5).

• (Answer: 945)

4. Series: 14, 27, 53, 105, 209, ?

• Pattern: Consistent ×2 - 1.

• (Answer: 417)

5. Series: 4, 10, 32, ?, 652, 3914

• Pattern: ×n + 2, where n increases sequentially (×2+2, ×3+2, ×4+2...).

• (Answer: 130)

How to Solve Questions Based on Simplification?

These questions test calculation speed and adherence to the BODMAS rule.

1. Problem: (1200 ÷ 16) × 2 × 4 + (180 ÷ 3)

• (Answer: 660)

2. Problem: 20% of 60 + 30% of 90 + 36

• (Answer: 75)

3. Problem: √(120 + 42 + 7)

• (Answer: 13)

4. Problem: (25 - 13) + 18 - 30

• (Answer: 0)

5. Problem: (72 ÷ 24) + 180

• (Answer: 183)

How to Solve Arithmetic Problems?

Here are different types of arithmetic problems and how to solve them:

1. Time & Work

• Problem: A+B finish in 20 days, B+C in 30 days, C+A in 40 days. How long for A alone?

• Solution: Use LCM to find total work and efficiencies. Calculate 2(A+B+C) then A+B+C. Find A's efficiency by subtracting B+C's efficiency.

• (Answer: 48 days)

2. Mixtures

• Problem: Milk: Water in 9:5. Add 10L water, ratio becomes 3:2. Initial milk quantity?

• Solution: Equalize milk parts in both ratios (9:5 and 9:6). The difference in water parts (1 part) equals 10L.

• (Answer: 90 Liters)

3. Partnership

• Problem: Raju: Arun invests 7:9. After 6 months, Jitu joins with 2/3 of Arun's capital. After 1 year, Raju's profit is 5600. Total profit?

• Solution: Calculate the effective capital ratio (Capital × Time) for all three partners. Use Raju's profit to find the value of one ratio part, then calculate total profit.

• (Answer: 15,200)

4. Simple Interest

• Problem: Investment 25,000, SI 5,000 at 10% p.a. Time period?

• Solution: Calculate total interest as a percentage of the principal. Divide this by the annual interest rate.

• (Answer: 2 years)

5. Profit, Loss & Discount

• Problem: Toy sold for 1200 (20% discount), 25% profit. CP increased by 40. New difference between MP and new CP?

• Solution: Use SP and profit % to find CP. Use SP and discount % to find MP. Increase CP, then find the new difference. (A useful ratio is CP: MP = (100-D%):(100+P%)).

• (Answer: 500)

6. Averages

• Problem: Avg age of 20 students is 18. Two students (ages 'a' and 'a+8') join, average increases by 1. Avg. age of the two new students?

• Solution: Calculate initial sum of ages. Calculate new total sum of ages (22 students, avg 19). The difference is the sum of the two new students' ages.

• (Answer: 29)

7. Boats and Streams

• Problem: Stream speed 6 km/h. Boat travels 90 km downstream in 5 hours. Time to cover same distance upstream?

• Solution: Find downstream speed. Calculate boat's speed. Calculate upstream speed. Then find time taken for upstream journey.

• (Answer: 15 hours)

8. Pipes and Cisterns

• Problem: A fills in 12h, B empties in 18h. Open for 10h, then B is also open. How long to fill remaining?

• Solution: Use LCM for total work and efficiencies. Calculate work done by A in 10 hours. Find remaining work. Calculate combined efficiency when both are open.

• (Answer: 6 hours)

9. Ages

• Problem: Sum of Manish's (M) and Pankaj's (P) ages is 32. Half sum of M, P, and S (Suresh) is 25. M is 2 years older than S. Find Pankaj's age.

• Solution: Use the given equations (M+P=32, M+P+S=50, M=S+2) to find S, then M, and finally P.

• (Answer: 12 years)

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